我知道这是一个老问题，但我认为一定有一种比其他例子更简单的方法来做到这一点，因此我做了一个库，在不污染代码库的情况下干净地解决这个问题。包含附件非常简单:

from redmail import EmailSender
from pathlib import Path

# Configure an email sender
email = EmailSender(
    host="<SMTP HOST>", port=0,
    user_name="me@example.com", password="<PASSWORD>"
)

# Send an email
email.send(
    sender="me@example.com",
    receivers=["you@example.com"],
    subject="An example email"
    attachments={
        "myfile.txt": Path("path/to/a_file.txt"),
        "myfile.html": "<h1>Content of a HTML attachment</h1>"
    }
)

你也可以直接附加字节，Pandas DataFrame(根据键中的文件扩展名转换为格式)，Matplotlib图或枕头图像。这个库很可能是你需要一个电子邮件发送者的所有功能(它比附件要多得多)。

如何安装:

pip install redmail

你喜欢怎么用就怎么用。我还写了大量的文档:https://red-mail.readthedocs.io/en/latest/

下面是Oli为python3编写的修改版本

import smtplib
from pathlib import Path
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email import encoders


def send_mail(send_from, send_to, subject, message, files=[],
              server="localhost", port=587, username='', password='',
              use_tls=True):
    """Compose and send email with provided info and attachments.

    Args:
        send_from (str): from name
        send_to (list[str]): to name(s)
        subject (str): message title
        message (str): message body
        files (list[str]): list of file paths to be attached to email
        server (str): mail server host name
        port (int): port number
        username (str): server auth username
        password (str): server auth password
        use_tls (bool): use TLS mode
    """
    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = COMMASPACE.join(send_to)
    msg['Date'] = formatdate(localtime=True)
    msg['Subject'] = subject

    msg.attach(MIMEText(message))

    for path in files:
        part = MIMEBase('application', "octet-stream")
        with open(path, 'rb') as file:
            part.set_payload(file.read())
        encoders.encode_base64(part)
        part.add_header('Content-Disposition',
                        'attachment; filename={}'.format(Path(path).name))
        msg.attach(part)

    smtp = smtplib.SMTP(server, port)
    if use_tls:
        smtp.starttls()
    smtp.login(username, password)
    smtp.sendmail(send_from, send_to, msg.as_string())
    smtp.quit()

我能找到的最简单的代码是:

#for attachment email
from django.core.mail import EmailMessage

    def attachment_email(request):
            email = EmailMessage(
            'Hello', #subject
            'Body goes here', #body
            'MyEmail@MyEmail.com', #from
            ['SendTo@SendTo.com'], #to
            ['bcc@example.com'], #bcc
            reply_to=['other@example.com'],
            headers={'Message-ID': 'foo'},
            )

            email.attach_file('/my/path/file')
            email.send()

它基于官方的Django文档

有了我的代码，您可以使用gmail发送电子邮件附件，您将需要:

将您的gmail地址设置为您的SMTP邮箱地址 将您的gmail帐户密码设置为__YOUR SMTP password HERE___ 在___EMAIL TO RECEIVE the MESSAGE__部分，您需要设置目的电子邮件地址。 告警通知是主题。 有人进入房间，附上的照片是尸体。 ["/home/pi/webcam.jpg"]是一个图像附件。

以下是完整的代码:

#!/usr/bin/env python
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email.MIMEText import MIMEText
from email.Utils import COMMASPACE, formatdate
from email import Encoders
import os

USERNAME = "___YOUR SMTP EMAIL HERE___"
PASSWORD = "__YOUR SMTP PASSWORD HERE___"

def sendMail(to, subject, text, files=[]):
    assert type(to)==list
    assert type(files)==list

    msg = MIMEMultipart()
    msg['From'] = USERNAME
    msg['To'] = COMMASPACE.join(to)
    msg['Date'] = formatdate(localtime=True)
    msg['Subject'] = subject

    msg.attach( MIMEText(text) )

    for file in files:
        part = MIMEBase('application', "octet-stream")
        part.set_payload( open(file,"rb").read() )
        Encoders.encode_base64(part)
        part.add_header('Content-Disposition', 'attachment; filename="%s"'
                       % os.path.basename(file))
        msg.attach(part)

    server = smtplib.SMTP('smtp.gmail.com:587')
    server.ehlo_or_helo_if_needed()
    server.starttls()
    server.ehlo_or_helo_if_needed()
    server.login(USERNAME,PASSWORD)
    server.sendmail(USERNAME, to, msg.as_string())
    server.quit()

sendMail( ["___EMAIL TO RECEIVE THE MESSAGE__"],
        "Alarm notification",
        "Someone has entered the room, picture attached",
        ["/home/pi/webcam.jpg"] )

其他的答案也很好，但我还是想分享一种不同的方法，以防有人正在寻找替代方案。

主要的区别是，使用这种方法，你可以使用HTML/CSS来格式化你的邮件，所以你可以有创意，给你的电子邮件一些样式。虽然没有强制使用HTML，但仍然可以只使用纯文本。

注意，该函数接受将电子邮件发送给多个收件人，也允许附加多个文件。

我只在python2上尝试过，但我认为它在python3上也能正常工作:

import os.path
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.application import MIMEApplication

def send_email(subject, message, from_email, to_email=[], attachment=[]):
    """
    :param subject: email subject
    :param message: Body content of the email (string), can be HTML/CSS or plain text
    :param from_email: Email address from where the email is sent
    :param to_email: List of email recipients, example: ["a@a.com", "b@b.com"]
    :param attachment: List of attachments, exmaple: ["file1.txt", "file2.txt"]
    """
    msg = MIMEMultipart()
    msg['Subject'] = subject
    msg['From'] = from_email
    msg['To'] = ", ".join(to_email)
    msg.attach(MIMEText(message, 'html'))

    for f in attachment:
        with open(f, 'rb') as a_file:
            basename = os.path.basename(f)
            part = MIMEApplication(a_file.read(), Name=basename)

        part['Content-Disposition'] = 'attachment; filename="%s"' % basename
        msg.attach(part)

    email = smtplib.SMTP('your-smtp-host-name.com')
    email.sendmail(from_email, to_email, msg.as_string())

我希望这能有所帮助!: -)

下面是我从SoccerPlayer的帖子中找到的内容的组合，下面的链接使我更容易附加一个xlsx文件。在这里找到

file = 'File.xlsx'
username=''
password=''
send_from = ''
send_to = 'recipient1 , recipient2'
Cc = 'recipient'
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = send_to
msg['Cc'] = Cc
msg['Date'] = formatdate(localtime = True)
msg['Subject'] = ''
server = smtplib.SMTP('smtp.gmail.com')
port = '587'
fp = open(file, 'rb')
part = MIMEBase('application','vnd.ms-excel')
part.set_payload(fp.read())
fp.close()
encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment', filename='Name File Here')
msg.attach(part)
smtp = smtplib.SMTP('smtp.gmail.com')
smtp.ehlo()
smtp.starttls()
smtp.login(username,password)
smtp.sendmail(send_from, send_to.split(',') + msg['Cc'].split(','), msg.as_string())
smtp.quit()