这个代码对我有用。

        private void OnChanged(object source, FileSystemEventArgs e)
    {

        string fullFilePath = e.FullPath.ToString();
        string fullURL = buildTheUrlFromStudyXML(fullFilePath);

        System.Diagnostics.Process.Start("iexplore", fullURL);

        Timer timer = new Timer();
        ((FileSystemWatcher)source).Changed -= new FileSystemEventHandler(OnChanged);
        timer.Interval = 1000;
        timer.Elapsed += new ElapsedEventHandler(t_Elapsed);
        timer.Start();
    }

    private void t_Elapsed(object sender, ElapsedEventArgs e)
    {
        ((Timer)sender).Stop();
        theWatcher.Changed += new FileSystemEventHandler(OnChanged);
    }

这个解决方案适用于我的生产应用程序:

环境:

VB。Net Framework 4.5.2

手动设置对象属性:NotifyFilter = Size

然后使用下面的代码:

Public Class main
    Dim CalledOnce = False
    Private Sub FileSystemWatcher1_Changed(sender As Object, e As IO.FileSystemEventArgs) Handles FileSystemWatcher1.Changed
            If (CalledOnce = False) Then
                CalledOnce = True
                If (e.ChangeType = 4) Then
                    ' Do task...
                CalledOnce = False
            End If
        End Sub
End Sub

很多答案都令人震惊，真的。 这里有一些代码从我的XanderUI控件库修复这个问题。

private void OnChanged(object sender, FilesystemEventArgs e)
{
    if (FSWatcher.IncludeSubdirectories == true)
    {
        if (File.Exists(e.FullPath)) { DO YOUR FILE CHANGE STUFF HERE... }
    }
    else DO YOUR DIRECTORY CHANGE STUFF HERE...
}

这里有一个你可以尝试的新解决方案。很适合我。在已更改事件的事件处理程序中，以编程方式从设计器输出中删除处理程序(如果需要的话)，然后以编程方式将处理程序添加回来。例子:

public void fileSystemWatcher1_Changed( object sender, System.IO.FileSystemEventArgs e )
    {            
        fileSystemWatcher1.Changed -= new System.IO.FileSystemEventHandler( fileSystemWatcher1_Changed );
        MessageBox.Show( "File has been uploaded to destination", "Success!" );
        fileSystemWatcher1.Changed += new System.IO.FileSystemEventHandler( fileSystemWatcher1_Changed );
    }

FileSystemWatcher中的任何重复的OnChanged事件都可以通过检查File来检测和丢弃。GetLastWriteTime文件的时间戳。像这样:

DateTime lastRead = DateTime.MinValue;

void OnChanged(object source, FileSystemEventArgs a)
{
    DateTime lastWriteTime = File.GetLastWriteTime(uri);
    if (lastWriteTime != lastRead)
    {
        doStuff();
        lastRead = lastWriteTime;
    }
    // else discard the (duplicated) OnChanged event
}

一直在寻找答案，但我想到了一个肮脏的解决方案。因为我的事件触发了两次，所以第二个动作什么也不做。

       $count = 1
       $action = { 
            if($count -eq 1){                  
                #DO SOMETHING
                $count = 2 
            }else{
                $count = 1
            }
        }