FileSystemWatcher中的任何重复的OnChanged事件都可以通过检查File来检测和丢弃。GetLastWriteTime文件的时间戳。像这样:

DateTime lastRead = DateTime.MinValue;

void OnChanged(object source, FileSystemEventArgs a)
{
    DateTime lastWriteTime = File.GetLastWriteTime(uri);
    if (lastWriteTime != lastRead)
    {
        doStuff();
        lastRead = lastWriteTime;
    }
    // else discard the (duplicated) OnChanged event
}

试试这个，效果很好

  private static readonly FileSystemWatcher Watcher = new FileSystemWatcher();
    static void Main(string[] args)
    {
        Console.WriteLine("Watching....");

        Watcher.Path = @"D:\Temp\Watcher";
        Watcher.Changed += OnChanged;
        Watcher.EnableRaisingEvents = true;
        Console.ReadKey();
    }

    static void OnChanged(object sender, FileSystemEventArgs e)
    {
        try
        {
            Watcher.Changed -= OnChanged;
            Watcher.EnableRaisingEvents = false;
            Console.WriteLine($"File Changed. Name: {e.Name}");
        }
        catch (Exception exception)
        {
            Console.WriteLine(exception);
        }
        finally
        {
            Watcher.Changed += OnChanged;
            Watcher.EnableRaisingEvents = true;
        }
    }

我的场景是，我有一个虚拟机，其中有一个Linux服务器。我正在Windows主机上开发文件。当我在主机上的一个文件夹中更改某些内容时，我希望所有的更改都被上传，并通过Ftp同步到虚拟服务器上。这是我如何消除重复更改事件当我写入一个文件(这标志着包含文件要修改的文件夹):

private Hashtable fileWriteTime = new Hashtable();

private void fsw_sync_Changed(object source, FileSystemEventArgs e)
{
    string path = e.FullPath.ToString();
    string currentLastWriteTime = File.GetLastWriteTime( e.FullPath ).ToString();

    // if there is no path info stored yet
    // or stored path has different time of write then the one now is inspected
    if ( !fileWriteTime.ContainsKey(path) ||
         fileWriteTime[path].ToString() != currentLastWriteTime
    )
    {
        //then we do the main thing
        log( "A CHANGE has occured with " + path );

        //lastly we update the last write time in the hashtable
        fileWriteTime[path] = currentLastWriteTime;
    }
}

我主要创建一个哈希表来存储文件写时间信息。然后，如果哈希表有被修改的文件路径，并且它的时间值与当前通知的文件更改相同，那么我就知道它是事件的副本，并忽略它。

一直在寻找答案，但我想到了一个肮脏的解决方案。因为我的事件触发了两次，所以第二个动作什么也不做。

       $count = 1
       $action = { 
            if($count -eq 1){                  
                #DO SOMETHING
                $count = 2 
            }else{
                $count = 1
            }
        }  

这个解决方案适用于我的生产应用程序:

环境:

VB。Net Framework 4.5.2

手动设置对象属性:NotifyFilter = Size

然后使用下面的代码:

Public Class main
    Dim CalledOnce = False
    Private Sub FileSystemWatcher1_Changed(sender As Object, e As IO.FileSystemEventArgs) Handles FileSystemWatcher1.Changed
            If (CalledOnce = False) Then
                CalledOnce = True
                If (e.ChangeType = 4) Then
                    ' Do task...
                CalledOnce = False
            End If
        End Sub
End Sub

我是这样处理双重创造问题的，忽略了第一个事件:

Private WithEvents fsw As New System.IO.FileSystemWatcher
Private complete As New List(Of String)

Private Sub fsw_Created(ByVal sender As Object, _
    ByVal e As System.IO.FileSystemEventArgs) Handles fsw.Created

    If Not complete.Contains(e.FullPath) Then
        complete.Add(e.FullPath)

    Else
        complete.Remove(e.FullPath)
        Dim th As New Threading.Thread(AddressOf hprocess)
        th.Start(e)

    End If

End Sub