我遇到了这样的情况,我需要将分离的对象重新附加到hibernate会话,尽管会话中可能已经存在相同标识的对象,这将导致错误。
现在,我可以做两件事之一。
getHibernateTemplate()。更新(obj)
当且仅当对象在hibernate会话中还不存在时,这才有效。当我以后需要它时,抛出异常,声明具有给定标识符的对象已经存在于会话中。
getHibernateTemplate()。合并(obj)
当且仅当hibernate会话中存在对象时,此操作才有效。如果稍后使用此方法,则在需要对象处于会话中时抛出异常。
对于这两种场景,我如何将会话附加到对象?我不想使用异常来控制这个问题解决方案的流程,因为一定有更优雅的解决方案……
所有这些答案都忽略了一个重要的区别。update()用于(重新)将对象图附加到Session。你传递给它的对象是被管理的对象。
merge() is actually not a (re)attachment API. Notice merge() has a return value? That's because it returns you the managed graph, which may not be the graph you passed it. merge() is a JPA API and its behavior is governed by the JPA spec. If the object you pass in to merge() is already managed (already associated with the Session) then that's the graph Hibernate works with; the object passed in is the same object returned from merge(). If, however, the object you pass into merge() is detached, Hibernate creates a new object graph that is managed and it copies the state from your detached graph onto the new managed graph. Again, this is all dictated and governed by the JPA spec.
就“确保该实体受到管理,或者使其受到管理”的通用策略而言,这在某种程度上取决于您是否还想考虑尚未插入的数据。假设你这样做,使用一些类似
if ( session.contains( myEntity ) ) {
// nothing to do... myEntity is already associated with the session
}
else {
session.saveOrUpdate( myEntity );
}
注意,我使用的是saveOrUpdate()而不是update()。如果您不想在这里处理尚未插入的数据,请使用update()来代替…