if(str.length == 0 || [str isKindOfClass: [NSNull class]]){
    NSLog(@"String is empty");
}
else{
    NSLog(@"String is not empty");
}    

你最好使用这个类别:

@implementation NSString (Empty)

    - (BOOL) isWhitespace{
        return ([[self stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]length] == 0);
    }

@end

简单地检查你的字符串长度

 if (!yourString.length)
 {
   //your code  
 }

发送给NIL的消息将返回NIL或0，因此不需要测试NIL:)。

快乐编码…

只需使用一个if else条件，如下所示:

方法1:

if ([yourString isEqualToString:@""]) {
        // yourString is empty.
    } else {
        // yourString has some text on it.
    }

方法2:

if ([yourString length] == 0) {
    // Empty yourString
} else {
    // yourString is not empty
}

- (BOOL)isEmpty:(NSString *)string{
    if ((NSNull *) string == [NSNull null]) {
        return YES;
    }
    if (string == nil) {
        return YES;
    }
    if ([string length] == 0) {
        return YES;
    }
    if ([[string stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceAndNewlineCharacterSet]] length] == 0) {
        return YES;
    }
    if([[string stringByStrippingWhitespace] isEqualToString:@""]){
        return YES;
    }
    return NO;
}

我这样写:

@implementation NSObject (AdditionalMethod)
-(BOOL) isNotEmpty
{
    return !(self == nil
    || [self isKindOfClass:[NSNull class]]
    || ([self respondsToSelector:@selector(length)]
        && [(NSData *)self length] == 0)
    || ([self respondsToSelector:@selector(count)]
        && [(NSArray *)self count] == 0));

};
@end

问题是如果self为nil，这个函数就永远不会被调用。它将返回false，这是所期望的。