是否有一种内置的方法来测量Windows命令行上命令的执行时间?


当前回答

测量时间的替代方法是简单的“Get-Date”。你不会有转发输出的麻烦。

$start = Get-Date
[System.Threading.Thread]::Sleep(1500)
$(Get-Date) - $start

输出:

Days              : 0
Hours             : 0
Minutes           : 0
Seconds           : 1
Milliseconds      : 506
Ticks             : 15060003
TotalDays         : 1.74305590277778E-05
TotalHours        : 0.000418333416666667
TotalMinutes      : 0.025100005
TotalSeconds      : 1.5060003
TotalMilliseconds : 1506.0003

其他回答

这是对Luke Sampson的nice timecmd.bat的评论/编辑并回复

出于某种原因,这只给我整秒的输出…这对我来说毫无用处。我的意思是,我运行timecmd pause,结果总是1秒,2秒,4秒……甚至是0.00秒!Windows 7。- Camilo Martin 13年9月25日16:00

在某些配置上,分隔符可能不同。以下变化至少应该涵盖大多数西方国家。

set options="tokens=1-4 delims=:,." (added comma)

在添加','后,%time%毫秒在我的系统上工作

(*因为网站不允许匿名评论,没有很好地跟踪身份,即使我总是使用相同的客人电子邮件,结合ipv6 ip和浏览器指纹应该足以唯一识别没有密码)

如果您使用的是Windows 2003(注意不支持Windows server 2008及更高版本),您可以使用Windows server 2003资源工具包,其中包含显示详细执行统计信息的time .exe。这里有一个例子,计时命令“timeit -?”:

C:\>timeit timeit -?
Invalid switch -?
Usage: TIMEIT [-f filename] [-a] [-c] [-i] [-d] [-s] [-t] [-k keyname | -r keyname] [-m mask] [commandline...]
where:        -f specifies the name of the database file where TIMEIT
                 keeps a history of previous timings.  Default is .\timeit.dat
              -k specifies the keyname to use for this timing run
              -r specifies the keyname to remove from the database.  If
                 keyname is followed by a comma and a number then it will
                 remove the slowest (positive number) or fastest (negative)
                 times for that keyname.
              -a specifies that timeit should display average of all timings
                 for the specified key.
              -i specifies to ignore non-zero return codes from program
              -d specifies to show detail for average
              -s specifies to suppress system wide counters
              -t specifies to tabular output
              -c specifies to force a resort of the data base
              -m specifies the processor affinity mask

Version Number:   Windows NT 5.2 (Build 3790)
Exit Time:        7:38 am, Wednesday, April 15 2009
Elapsed Time:     0:00:00.000
Process Time:     0:00:00.015
System Calls:     731
Context Switches: 299
Page Faults:      515
Bytes Read:       0
Bytes Written:    0
Bytes Other:      298

您可以在Windows 2003资源工具包中获得TimeIt。它不能从微软下载中心直接下载,但仍然可以从archive.org - Windows Server 2003资源工具包工具中获得。

在Perl安装了可用的雇佣解决方案后,运行:

C:\BATCH>time.pl "echo Fine result"
0.01063
Fine result

STDERR出现在被测量的秒之前

#!/usr/bin/perl -w

use Time::HiRes qw();
my $T0 = [ Time::HiRes::gettimeofday ];

my $stdout = `@ARGV`;

my $time_elapsed = Time::HiRes::tv_interval( $T0 );

print $time_elapsed, "\n";
print $stdout;

如果你愿意

测量执行时间精确到(hh:mm:ss)的百分之一秒。ff格式) 不需要下载和安装资源包 看起来像一个巨大的DOS书呆子(谁不是呢)

尝试将以下脚本复制到一个新的批处理文件(例如timecmd.bat):

@echo off
@setlocal

set start=%time%

:: Runs your command
cmd /c %*

set end=%time%
set options="tokens=1-4 delims=:.,"
for /f %options% %%a in ("%start%") do set start_h=%%a&set /a start_m=100%%b %% 100&set /a start_s=100%%c %% 100&set /a start_ms=100%%d %% 100
for /f %options% %%a in ("%end%") do set end_h=%%a&set /a end_m=100%%b %% 100&set /a end_s=100%%c %% 100&set /a end_ms=100%%d %% 100

set /a hours=%end_h%-%start_h%
set /a mins=%end_m%-%start_m%
set /a secs=%end_s%-%start_s%
set /a ms=%end_ms%-%start_ms%
if %ms% lss 0 set /a secs = %secs% - 1 & set /a ms = 100%ms%
if %secs% lss 0 set /a mins = %mins% - 1 & set /a secs = 60%secs%
if %mins% lss 0 set /a hours = %hours% - 1 & set /a mins = 60%mins%
if %hours% lss 0 set /a hours = 24%hours%
if 1%ms% lss 100 set ms=0%ms%

:: Mission accomplished
set /a totalsecs = %hours%*3600 + %mins%*60 + %secs%
echo command took %hours%:%mins%:%secs%.%ms% (%totalsecs%.%ms%s total)

使用

如果你把timecmd.bat放在你路径中的一个目录中,你可以在任何地方调用它,像这样:

timecmd [your command]

E.g.

C:\>timecmd pause
Press any key to continue . . .
command took 0:0:1.18

如果你想做输出重定向,你可以这样引用命令:

timecmd "dir c:\windows /s > nul"

这应该可以处理从午夜之前到午夜之后运行的命令,但是如果您的命令运行了24小时或更长时间,则输出将是错误的。

driblio的答案可以短一点(虽然可读性不高)

@echo off

:: Calculate the start timestamp
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _started=_hours*60*60*100+_min*60*100+_sec*100+_cs


:: yourCommandHere


:: Calculate the difference in cSeconds
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _duration=_hours*60*60*100+_min*60*100+_sec*100+_cs-_started

:: Populate variables for rendering (100+ needed for padding)
set /a _hours=_duration/60/60/100,_min=100+_duration/60/100%%60,_sec=100+(_duration/100%%60%%60),_cs=100+_duration%%100

echo Done at: %_time% took : %_hours%:%_min:~-2%:%_sec:~-2%.%_cs:~-2%

::prints something like:
::Done at: 12:37:53,70 took: 0:02:03.55

根据Luke Sampson的评论,这个版本是八进制安全的,尽管任务应该在24小时内完成。