我想创建一个日期列表,从今天开始,追溯到任意天数,例如,在我的示例中是100天。还有比这更好的办法吗?
import datetime
a = datetime.datetime.today()
numdays = 100
dateList = []
for x in range (0, numdays):
dateList.append(a - datetime.timedelta(days = x))
print dateList
我想创建一个日期列表,从今天开始,追溯到任意天数,例如,在我的示例中是100天。还有比这更好的办法吗?
import datetime
a = datetime.datetime.today()
numdays = 100
dateList = []
for x in range (0, numdays):
dateList.append(a - datetime.timedelta(days = x))
print dateList
当前回答
从上面的答案,我创建了这个例子的日期生成器
import datetime
date = datetime.datetime.now()
time = date.time()
def date_generator(date, delta):
counter =0
date = date - datetime.timedelta(days=delta)
while counter <= delta:
yield date
date = date + datetime.timedelta(days=1)
counter +=1
for date in date_generator(date, 30):
if date.date() != datetime.datetime.now().date():
start_date = datetime.datetime.combine(date, datetime.time())
end_date = datetime.datetime.combine(date, datetime.time.max)
else:
start_date = datetime.datetime.combine(date, datetime.time())
end_date = datetime.datetime.combine(date, time)
print('start_date---->',start_date,'end_date---->',end_date)
其他回答
一个泛型方法,允许在参数化窗口大小(天,分钟,小时,秒)上创建日期范围:
from datetime import datetime, timedelta
def create_date_ranges(start, end, **interval):
start_ = start
while start_ < end:
end_ = start_ + timedelta(**interval)
yield (start_, min(end_, end))
start_ = end_
测试:
def main():
tests = [
('2021-11-15:00:00:00', '2021-11-17:13:00:00', {'days': 1}),
('2021-11-15:00:00:00', '2021-11-16:13:00:00', {'hours': 12}),
('2021-11-15:00:00:00', '2021-11-15:01:45:00', {'minutes': 30}),
('2021-11-15:00:00:00', '2021-11-15:00:01:12', {'seconds': 30})
]
for t in tests:
print("\nInterval: %s, range(%s to %s)" % (t[2], t[0], t[1]))
start = datetime.strptime(t[0], '%Y-%m-%d:%H:%M:%S')
end = datetime.strptime(t[1], '%Y-%m-%d:%H:%M:%S')
ranges = list(create_date_ranges(start, end, **t[2]))
x = list(map(
lambda x: (x[0].strftime('%Y-%m-%d:%H:%M:%S'), x[1].strftime('%Y-%m-%d:%H:%M:%S')),
ranges
))
print(x)
main()
测试输出:
Interval: {'days': 1}, range(2021-11-15:00:00:00 to 2021-11-17:13:00:00)
[('2021-11-15:00:00:00', '2021-11-16:00:00:00'), ('2021-11-16:00:00:00', '2021-11-17:00:00:00'), ('2021-11-17:00:00:00', '2021-11-17:13:00:00')]
Interval: {'hours': 12}, range(2021-11-15:00:00:00 to 2021-11-16:13:00:00)
[('2021-11-15:00:00:00', '2021-11-15:12:00:00'), ('2021-11-15:12:00:00', '2021-11-16:00:00:00'), ('2021-11-16:00:00:00', '2021-11-16:12:00:00'), ('2021-11-16:12:00:00', '2021-11-16:13:00:00')]
Interval: {'minutes': 30}, range(2021-11-15:00:00:00 to 2021-11-15:01:45:00)
[('2021-11-15:00:00:00', '2021-11-15:00:30:00'), ('2021-11-15:00:30:00', '2021-11-15:01:00:00'), ('2021-11-15:01:00:00', '2021-11-15:01:30:00'), ('2021-11-15:01:30:00', '2021-11-15:01:45:00')]
Interval: {'seconds': 30}, range(2021-11-15:00:00:00 to 2021-11-15:00:01:12)
[('2021-11-15:00:00:00', '2021-11-15:00:00:30'), ('2021-11-15:00:00:30', '2021-11-15:00:01:00'), ('2021-11-15:00:01:00', '2021-11-15:00:01:12')]
是的,重新发明轮子.... 只要搜索论坛,你就会得到这样的东西:
from dateutil import rrule
from datetime import datetime
list(rrule.rrule(rrule.DAILY,count=100,dtstart=datetime.now()))
一个带有datetime和dateutil的月日期范围生成器。简单易懂的:
import datetime as dt
from dateutil.relativedelta import relativedelta
def month_range(start_date, n_months):
for m in range(n_months):
yield start_date + relativedelta(months=+m)
一般来说,Pandas非常适合时间序列,并直接支持日期范围。
例如pd.date_range():
import pandas as pd
from datetime import datetime
datelist = pd.date_range(datetime.today(), periods=100).tolist()
它也有很多选择,让生活更轻松。例如,如果您只想要工作日,您只需交换bdate_range。
参见日期范围文档
此外,它完全支持pytz时区,可以平滑地跨越春季/秋季夏令时转换。
编辑由OP:
如果你需要实际的python日期时间,而不是Pandas时间戳:
import pandas as pd
from datetime import datetime
pd.date_range(end = datetime.today(), periods = 100).to_pydatetime().tolist()
#OR
pd.date_range(start="2018-09-09",end="2020-02-02")
这使用"end"参数来匹配原始问题,但如果你想要降序日期:
pd.date_range(datetime.today(), periods=100).to_pydatetime().tolist()
你也可以使用日期序数来简化:
def date_range(start_date, end_date):
for ordinal in range(start_date.toordinal(), end_date.toordinal()):
yield datetime.date.fromordinal(ordinal)
或者像评论中建议的那样,你可以创建一个这样的列表:
date_range = [
datetime.date.fromordinal(ordinal)
for ordinal in range(
start_date.toordinal(),
end_date.toordinal(),
)
]