我有一个目标:
myObject = { 'a': 1, 'b': 2, 'c': 3 }
我正在寻找一个本地方法,类似于Array.prototype.map,可按如下方式使用:
newObject = myObject.map(function (value, label) {
return value * value;
});
// newObject is now { 'a': 1, 'b': 4, 'c': 9 }
JavaScript是否有这样的对象映射函数?(我希望Node.JS使用这个,所以我不关心跨浏览器问题。)
我需要一个允许修改密钥的版本(基于@Amberlamps和@yonatanmn答案);
var facts = [ // can be an object or array - see jsfiddle below
{uuid:"asdfasdf",color:"red"},
{uuid:"sdfgsdfg",color:"green"},
{uuid:"dfghdfgh",color:"blue"}
];
var factObject = mapObject({}, facts, function(key, item) {
return [item.uuid, {test:item.color, oldKey:key}];
});
function mapObject(empty, obj, mapFunc){
return Object.keys(obj).reduce(function(newObj, key) {
var kvPair = mapFunc(key, obj[key]);
newObj[kvPair[0]] = kvPair[1];
return newObj;
}, empty);
}
factObject(事实对象)=
{
"asdfasdf": {"color":"red","oldKey":"0"},
"sdfgsdfg": {"color":"green","oldKey":"1"},
"dfghdfgh": {"color":"blue","oldKey":"2"}
}
编辑:对传入起始对象{}进行轻微更改。允许为[](如果键是整数)
映射函数在Object.prototype上不存在,但是您可以这样模拟它
var myMap = function ( obj, callback ) {
var result = {};
for ( var key in obj ) {
if ( Object.prototype.hasOwnProperty.call( obj, key ) ) {
if ( typeof callback === 'function' ) {
result[ key ] = callback.call( obj, obj[ key ], key, obj );
}
}
}
return result;
};
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
var newObject = myMap( myObject, function ( value, key ) {
return value * value;
});
使用以下映射函数定义myObject.map
o => f=> Object.keys(o).reduce((a,c)=> c=='map' ? a : (a[c]=f(o[c],c),a), {})
让map=o=>f=>Object.keys(o).reduce((a,c)=>c=='map'?a:(a[c]=f(o[c],c),a),{})//测试初始化myObject={“a”:1,“b”:2,“c”:3}myObject.map=map(myObject);//你可以这样做,但不建议这样做//(您将看到“map”键任意/所有对象)//Object.prototype.map=map(myObject);//所述OP所需接口newObject=myObject.map(函数(值,标签){返回值*值;});console.log(newObject);
ES6:
Object.prototype.map = function(mapFunc) {
return Object.keys(this).map((key, index) => mapFunc(key, this[key], index));
}
2015年:
Object.prototype.map = function (mapFunc) {
var _this = this;
return Object.keys(this).map(function (key, index) {
return mapFunc(key, _this[key], index);
});
};
节点中的测试:
> a = {foo: "bar"}
{ foo: 'bar' }
> a.map((k,v,i) => v)
[ 'bar' ]