我有一个数字向量:

numbers <- c(4,23,4,23,5,43,54,56,657,67,67,435,
         453,435,324,34,456,56,567,65,34,435)

我如何让R计算x值在向量中出现的次数?


当前回答

numbers <- c(4,23,4,23,5,43,54,56,657,67,67,435 453,435,324,34,456,56,567,65,34,435)

> length(grep(435, numbers))
[1] 3


> length(which(435 == numbers))
[1] 3


> require(plyr)
> df = count(numbers)
> df[df$x == 435, ] 
     x freq
11 435    3


> sum(435 == numbers)
[1] 3


> sum(grepl(435, numbers))
[1] 3


> sum(435 == numbers)
[1] 3


> tabulate(numbers)[435]
[1] 3


> table(numbers)['435']
435 
  3 


> length(subset(numbers, numbers=='435')) 
[1] 3

其他回答

我的首选解决方案使用rle,它将返回一个值(在您的示例中是标签x)和一个长度,它表示该值按顺序出现了多少次。

通过结合rle和sort,可以非常快速地计算任何值出现的次数。这对解决更复杂的问题很有帮助。

例子:

> numbers <- c(4,23,4,23,5,43,54,56,657,67,67,435,453,435,324,34,456,56,567,65,34,435)
> a <- rle(sort(numbers))
> a
  Run Length Encoding
    lengths: int [1:15] 2 1 2 2 1 1 2 1 2 1 ...
    values : num [1:15] 4 5 23 34 43 54 56 65 67 324 ...

如果你想要的值没有显示,或者你需要为以后存储该值,创建一个data.frame。

> b <- data.frame(number=a$values, n=a$lengths)
> b
    values n
 1       4 2
 2       5 1
 3      23 2
 4      34 2
 5      43 1
 6      54 1
 7      56 2
 8      65 1
 9      67 2
 10    324 1
 11    435 3
 12    453 1
 13    456 1
 14    567 1
 15    657 1

我发现我很少想知道一个值的频率,而不是所有值的频率,rle似乎是获得计数和存储所有值的最快方法。

在R中有一个标准函数

汇总(数字)

numbers <- c(4,23,4,23,5,43,54,56,657,67,67,435 453,435,324,34,456,56,567,65,34,435)

> length(grep(435, numbers))
[1] 3


> length(which(435 == numbers))
[1] 3


> require(plyr)
> df = count(numbers)
> df[df$x == 435, ] 
     x freq
11 435    3


> sum(435 == numbers)
[1] 3


> sum(grepl(435, numbers))
[1] 3


> sum(435 == numbers)
[1] 3


> tabulate(numbers)[435]
[1] 3


> table(numbers)['435']
435 
  3 


> length(subset(numbers, numbers=='435')) 
[1] 3

这可以用outer来完成,以获得一个等式矩阵,后面跟着rowsum,具有明显的含义。 为了将计数和数字放在同一个数据集中,首先创建data.frame。如果需要分离输入和输出,则不需要此步骤。

df <- data.frame(No = numbers)
df$count <- rowSums(outer(df$No, df$No, FUN = `==`))

如果你想计算随后出现的次数,你可以使用sapply函数:

index<-sapply(1:length(numbers),function(x)sum(numbers[1:x]==numbers[x]))
cbind(numbers, index)

输出:

        numbers index
 [1,]       4     1
 [2,]      23     1
 [3,]       4     2
 [4,]      23     2
 [5,]       5     1
 [6,]      43     1
 [7,]      54     1
 [8,]      56     1
 [9,]     657     1
[10,]      67     1
[11,]      67     2
[12,]     435     1
[13,]     453     1
[14,]     435     2
[15,]     324     1
[16,]      34     1
[17,]     456     1
[18,]      56     2
[19,]     567     1
[20,]      65     1
[21,]      34     2
[22,]     435     3