ECMAScript 6 引入了许可声明。

我听说它被描述为一个当地变量,但我仍然不确定它是如何行为不同于 var 关键词。

什么是差异?什么时候应该被允许使用而不是 var?


当前回答

区块范围

在顶级(功能之外)

var globalVariable = 42;
let blockScopedVariable = 43;

console.log(globalVariable); // 42
console.log(blockScopedVariable); // 43

console.log(this.globalVariable); // 42
console.log(this.blockScopedVariable); // undefined

在一个功能之内

(() => {
  var functionScopedVariable = 42;
  let blockScopedVariable = 43;

  console.log(functionScopedVariable); // 42
  console.log(blockScopedVariable); // 43
})();

console.log(functionScopedVariable); // ReferenceError: functionScopedVariable is not defined
console.log(blockScopedVariable); // ReferenceError: blockScopedVariable is not defined

在一个区块内

{
  var globalVariable = 42;
  let blockScopedVariable = 43;
  console.log(globalVariable); // 42
  console.log(blockScopedVariable); // 43
}

console.log(globalVariable); // 42
console.log(blockScopedVariable); // ReferenceError: blockScopedVariable is not defined

在一个圈子里

用Let in Loops宣言的变量只能在该圈内提到。

for (var i = 0; i < 3; i++) {
  var j = i * 2;
}
console.log(i); // 3
console.log(j); // 4

for (let k = 0; k < 3; k++) {
  let l = k * 2;
}
console.log(typeof k); // undefined
console.log(typeof l); // undefined
// Trying to do console.log(k) or console.log(l) here would throw a ReferenceError.

// Logs 3 thrice, not what we meant.
for (var i = 0; i < 3; i++) {
  setTimeout(() => console.log(i), 0);
}

// Logs 0, 1 and 2, as expected.
for (let j = 0; j < 3; j++) {
  setTimeout(() => console.log(j), 0);
}

临时死区

由于临时死亡区,使用声明的变量在被声明之前无法访问,试图这样做会导致错误。

console.log(noTDZ); // undefined
var noTDZ = 43;
console.log(hasTDZ); // ReferenceError: hasTDZ is not defined
let hasTDZ = 42;

没有重新宣布

var a;
var a; // Works fine.

let b;
let b; // SyntaxError: Identifier 'b' has already been declared

var c;
let c; // SyntaxError: Identifier 'c' has already been declared

格斯特

没有重新分配

const a = 42;
a = 43; // TypeError: Assignment to constant variable.

请注意,这并不意味着值是不可改变的;它的属性仍然可以改变。

const obj = {};
obj.a = 42;
console.log(obj.a); // 42

如果您想要一个不可变的对象,您应该使用 Object.freeze()。

const obj = Object.freeze({a: 40});
obj.a = 42;
console.log(obj.a); // 40
console.log(obj.b); // undefined

初步者需要

在使用 const 表示变量时,您必须始终指定值。

const a; // SyntaxError: Missing initializer in const declaration

其他回答

使用 var 声明定义的变量在其定义的整个函数中已知,从函数的开始。 (*) 使用 let 声明定义的变量仅在其定义的区块中已知,从其定义的时刻开始。

// i IS NOT known here
// j IS NOT known here
// k IS known here, but undefined
// l IS NOT known here

function loop(arr) {
    // i IS known here, but undefined
    // j IS NOT known here
    // k IS known here, but has a value only the second time loop is called
    // l IS NOT known here

    for( var i = 0; i < arr.length; i++ ) {
        // i IS known here, and has a value
        // j IS NOT known here
        // k IS known here, but has a value only the second time loop is called
        // l IS NOT known here
    };

    // i IS known here, and has a value
    // j IS NOT known here
    // k IS known here, but has a value only the second time loop is called
    // l IS NOT known here

    for( let j = 0; j < arr.length; j++ ) {
        // i IS known here, and has a value
        // j IS known here, and has a value
        // k IS known here, but has a value only the second time loop is called
        // l IS NOT known here
    };

    // i IS known here, and has a value
    // j IS NOT known here
    // k IS known here, but has a value only the second time loop is called
    // l IS NOT known here
}

loop([1,2,3,4]);

for( var k = 0; k < arr.length; k++ ) {
    // i IS NOT known here
    // j IS NOT known here
    // k IS known here, and has a value
    // l IS NOT known here
};

for( let l = 0; l < arr.length; l++ ) {
    // i IS NOT known here
    // j IS NOT known here
    // k IS known here, and has a value
    // l IS known here, and has a value
};

loop([1,2,3,4]);

// i IS NOT known here
// j IS NOT known here
// k IS known here, and has a value
// l IS NOT known here


今天使用安全吗?

有些人会说,在未来,我们只会使用让陈述,而这些陈述会变得过时。JavaScript老师Kyle Simpson写了一篇非常复杂的文章,他认为为什么不会这样。

事实上,我们实际上需要问自己是否安全使用放弃声明,这个问题的答案取决于你的环境:

此分類上一篇


如何跟踪浏览器支持


下面是让关键词的解释,有几个例子。

主要区别在于,一个变量的范围是整个关闭功能。

此图在维基百科上显示哪些浏览器支持JavaScript 1.7.

请注意,只有 Mozilla 和 Chrome 浏览器支持它. IE、Safari 和其他可能不支持它。

ES6 引入了两个新的关键字(let 和 const) 替代到 var。

当你需要一个区块水平下降时,你可以用Let和Const而不是VAR去。

下面的表总结了 var, let 和 const 之间的差异

此分類上一篇

我刚刚遇到了一个使用案例,我不得不使用Var over让介绍新的变量。

我想创建一个新的变量,具有动态变量名称。

let variableName = 'a';
eval("let " + variableName + '= 10;');
console.log(a);   // this doesn't work
var variableName = 'a';
eval("var " + variableName + '= 10;');
console.log(a);   // this works

上面的代码不起作用,因为 eval 引入一个新的代码区块. 使用 var 的声明将声明这个代码区块之外的变量,因为 var 声明函数范围内的变量。

另一方面,让我们在区块范围内宣布一个变量,因此,一个变量仅在 eval 区块中可见。

下面表明“让我们”和“存在”在范围内是如何不同的:

let gfoo = 123;
if (true) {
    let gfoo = 456;
}
console.log(gfoo); // 123

var hfoo = 123;
if (true) {
    var hfoo = 456;
}
console.log(hfoo); // 456

gfoo,定义为 let 最初是在全球范围内,当我们宣布 gfoo 再次在如果条款的范围改变,当一个新的值被分配到变量在该范围内,它不会影响全球范围。

虽然 hfoo,由 var 定义,起初在全球范围内,但再次当我们在 if 条款内宣布它时,它考虑到全球范围 hfoo,尽管 var 已再次被用来宣布它。