也有可能在LINQ中使用XML:

在c#中创建XML树(LINQ to XML)

在使用树时，XML是最成熟和最灵活的解决方案，而LINQ为您提供了所需的所有工具。 您的树的配置也变得更加清晰和用户友好，因为您可以简单地使用XML文件进行初始化。

如果你需要处理对象，你可以使用XML序列化:

XML序列化

通常优秀的C5通用集合库具有几种不同的基于树的数据结构，包括集、包和字典。如果您想研究它们的实现细节，可以使用源代码。(我在产品代码中使用过C5集合，效果很好，尽管我没有特别使用过任何树结构。)

我已经使用上面的NTree类添加了一个完整的解决方案和示例。我还添加了AddChild方法…

    public class NTree<T>
    {
        public T data;
        public LinkedList<NTree<T>> children;

        public NTree(T data)
        {
            this.data = data;
            children = new LinkedList<NTree<T>>();
        }

        public void AddChild(T data)
        {
            var node = new NTree<T>(data) { Parent = this };
            children.AddFirst(node);
        }

        public NTree<T> Parent { get; private set; }

        public NTree<T> GetChild(int i)
        {
            foreach (NTree<T> n in children)
                if (--i == 0)
                    return n;
            return null;
        }

        public void Traverse(NTree<T> node, TreeVisitor<T> visitor, string t, ref NTree<T> r)
        {
            visitor(node.data, node, t, ref r);
            foreach (NTree<T> kid in node.children)
                Traverse(kid, visitor, t, ref r);
        }
    }

    public static void DelegateMethod(KeyValuePair<string, string> data, NTree<KeyValuePair<string, string>> node, string t, ref NTree<KeyValuePair<string, string>> r)
    {
        string a = string.Empty;
        if (node.data.Key == t)
        {
            r = node;
            return;
        }
    }

使用它

 NTree<KeyValuePair<string, string>> ret = null;
 tree.Traverse(tree, DelegateMethod, node["categoryId"].InnerText, ref ret);

试试这个简单的例子。

public class TreeNode<TValue>
{
    #region Properties
    public TValue Value { get; set; }
    public List<TreeNode<TValue>> Children { get; private set; }
    public bool HasChild { get { return Children.Any(); } }
    #endregion
    #region Constructor
    public TreeNode()
    {
        this.Children = new List<TreeNode<TValue>>();
    }
    public TreeNode(TValue value)
        : this()
    {
        this.Value = value;
    }
    #endregion
    #region Methods
    public void AddChild(TreeNode<TValue> treeNode)
    {
        Children.Add(treeNode);
    }
    public void AddChild(TValue value)
    {
        var treeNode = new TreeNode<TValue>(value);
        AddChild(treeNode);
    }
    #endregion
}

如果你需要一个使用较少内存的根树数据结构实现，你可以这样写你的Node类(c++实现):

class Node {
       Node* parent;
       int item; // depending on your needs

       Node* firstChild; //pointer to left most child of node
       Node* nextSibling; //pointer to the sibling to the right
}

我对解做了一些扩展。

使用递归泛型声明和派生子类，可以更好地专注于实际目标。

注意，它不同于非泛型实现，你不需要将'node'转换为'NodeWorker'。

以下是我的例子:

public class GenericTree<T> where T : GenericTree<T> // recursive constraint
{
  // no specific data declaration

  protected List<T> children;

  public GenericTree()
  {
    this.children = new List<T>();
  }

  public virtual void AddChild(T newChild)
  {
    this.children.Add(newChild);
  }

  public void Traverse(Action<int, T> visitor)
  {
    this.traverse(0, visitor);
  }

  protected virtual void traverse(int depth, Action<int, T> visitor)
  {
    visitor(depth, (T)this);
    foreach (T child in this.children)
      child.traverse(depth + 1, visitor);
  }
}

public class GenericTreeNext : GenericTree<GenericTreeNext> // concrete derivation
{
  public string Name {get; set;} // user-data example

  public GenericTreeNext(string name)
  {
    this.Name = name;
  }
}

static void Main(string[] args)
{
  GenericTreeNext tree = new GenericTreeNext("Main-Harry");
  tree.AddChild(new GenericTreeNext("Main-Sub-Willy"));
  GenericTreeNext inter = new GenericTreeNext("Main-Inter-Willy");
  inter.AddChild(new GenericTreeNext("Inter-Sub-Tom"));
  inter.AddChild(new GenericTreeNext("Inter-Sub-Magda"));
  tree.AddChild(inter);
  tree.AddChild(new GenericTreeNext("Main-Sub-Chantal"));
  tree.Traverse(NodeWorker);
}

static void NodeWorker(int depth, GenericTreeNext node)
{                                // a little one-line string-concatenation (n-times)
  Console.WriteLine("{0}{1}: {2}", String.Join("   ", new string[depth + 1]), depth, node.Name);
}