我有一个带有Azure后端的IOS应用程序,想要记录某些事件,如登录和应用程序用户正在运行的版本。

如何使用Swift返回版本和构建号?


当前回答

Bundle+Extension.swift (SwiftUI, swift 5, Xcode 11)

我结合了一些答案的想法,并扩展了一点:

一个SwiftUI的例子 如果Info.plist中缺少键,则显示警告三角形表情符号(而不是使应用程序崩溃)


进口的基础

extension Bundle {
    
    public var appVersionShort: String {
        if let result = infoDictionary?["CFBundleShortVersionString"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
    public var appVersionLong: String {
        if let result = infoDictionary?["CFBundleVersion"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
    public var appName: String {
        if let result = infoDictionary?["CFBundleName"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
}

SwiftUI实例使用

VStack {

     Text("Version: \(Bundle.main.appVersionShort!) (\(Bundle.main.appVersionLong!))")
                    .font(.subheadline)
                    .frame(maxWidth: .infinity, maxHeight: .infinity)
}

其他回答

我也知道这个问题已经有了答案,但我总结了之前的答案:

(*)扩展更新

extension Bundle {
    var releaseVersionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }
    var buildVersionNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }
    var releaseVersionNumberPretty: String {
        return "v\(releaseVersionNumber ?? "1.0.0")"
    }
}

用法:

someLabel.text = Bundle.main.releaseVersionNumberPretty

@Deprecated:旧答案

斯威夫特3.1:

class func getVersion() -> String {
    guard let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String else {
        return "no version info"
    }
    return version
}

对于旧版本:

class func getVersion() -> String {
    if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
        return version
    }
    return "no version info"
}

如果你想设置标签文本或者想在其他地方使用;

self.labelVersion.text = getVersion()

Xcode 8, Swift 3:

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"

对于Swift 3.0 NSBundle不工作,下面的代码工作完美。

let versionNumberString =
      Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
          as! String

对于版本号,它是:

let buildNumberString =
      Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion")
          as! String

令人困惑的'CFBundleVersion'是在Xcode General->Identity中输入的构建号。

斯威夫特3:

版本号

if let versionNumberString = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String { // do something }

建立数

if let buildNumberString = Bundle.main.infoDictionary?["CFBundleVersion"] as? String { // do something }

EDIT

Swift 4.2更新

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String

EDIT

正如@azdev在Xcode的新版本上指出的那样,你会得到一个编译错误,尝试我以前的解决方案,要解决这个问题,只需编辑它,建议使用一个打开包字典!

let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"]

最后编辑

使用与Objective-C中相同的逻辑,但有一些小的变化

//First get the nsObject by defining as an optional anyObject
let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"]

//Then just cast the object as a String, but be careful, you may want to double check for nil
let version = nsObject as! String