回答10年的老问题，帮助新人。

我们可以将这个包用于javascript时间之前

 
// Load locale-specific relative date/time formatting rules.
import en from 'javascript-time-ago/locale/en'
 
// Add locale-specific relative date/time formatting rules.
TimeAgo.addLocale(en)
 
// Create relative date/time formatter.
const timeAgo = new TimeAgo('en-US')
 
timeAgo.format(new Date())
// "just now"
 
timeAgo.format(Date.now() - 60 * 1000)
// "a minute ago"
 
timeAgo.format(Date.now() - 2 * 60 * 60 * 1000)
// "2 hours ago"
 
timeAgo.format(Date.now() - 24 * 60 * 60 * 1000)
// "a day ago"

我使用这个包:javascript-time-ago

设置TimeAgo 导入TimeAgo 从javascript-time-ago/locale/en.json导入en TimeAgo.addDefaultLocale (en) 写一个函数 // twitter-now是twitter风格。查看文档以获得更多选项 const clockToDateString = (timestamp) => timeAgo。format(new Date(timestamp.toNumber() * 1000)， 'twitter-now') 在dom中使用它 < div > {clockToDateString (post.postTime)} < / div >

以下是对Sky Sander的解决方案的轻微修改，允许日期作为字符串输入，并能够显示像“1分钟”而不是“73秒”这样的跨度

var timeSince = function(date) { if (typeof date !== 'object') { date = new Date(date); } var seconds = Math.floor((new Date() - date) / 1000); var intervalType; var interval = Math.floor(seconds / 31536000); if (interval >= 1) { intervalType = 'year'; } else { interval = Math.floor(seconds / 2592000); if (interval >= 1) { intervalType = 'month'; } else { interval = Math.floor(seconds / 86400); if (interval >= 1) { intervalType = 'day'; } else { interval = Math.floor(seconds / 3600); if (interval >= 1) { intervalType = "hour"; } else { interval = Math.floor(seconds / 60); if (interval >= 1) { intervalType = "minute"; } else { interval = seconds; intervalType = "second"; } } } } } if (interval > 1 || interval === 0) { intervalType += 's'; } return interval + ' ' + intervalType; }; var aDay = 24 * 60 * 60 * 1000; console.log(timeSince(new Date(Date.now() - aDay))); console.log(timeSince(new Date(Date.now() - aDay * 2)));

回复@Stas Parshin的答案，这是最好的答案，代码更少，但它在与typescript一起使用时有bug, Intl的.format函数需要2个输入

number, Units - i.e of type 'RelativeTimeFormatUnit' so if you pass a object key typescript will through error saying unit must be of type RelativeTimeFormatUnit and not of type string, so the work-around for this is to use the type to make another list of same type and rest you can have look at code... Happy coding. console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; type RelativeTimeFormatUnit = | "year" | "years" | "quarter" | "quarters" | "month" | "months" | "week" | "weeks" | "day" | "days" | "hour" | "hours" | "minute" | "minutes" | "second" | "seconds" ; const units: RelativeTimeFormatUnit[] = ["years", "months", "weeks", "days", "hours", "minutes", "seconds"]; // order matters here. const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { let i = 0; if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), units[i++]); } } }

function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));

Lokely使用的一个简短版本:

const intervals = [
  { label: 'year', seconds: 31536000 },
  { label: 'month', seconds: 2592000 },
  { label: 'day', seconds: 86400 },
  { label: 'hour', seconds: 3600 },
  { label: 'minute', seconds: 60 },
  { label: 'second', seconds: 1 }
];

function timeSince(date) {
  const seconds = Math.floor((Date.now() - date.getTime()) / 1000);
  const interval = intervals.find(i => i.seconds < seconds);
  const count = Math.floor(seconds / interval.seconds);
  return `${count} ${interval.label}${count !== 1 ? 's' : ''} ago`;
}