问题是如何将JavaScript Date格式化为一个字符串，声明时间经过，类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
我的尝试是基于其他的答案。
function timeSince(date) {
let minute = 60;
let hour = minute * 60;
let day = hour * 24;
let month = day * 30;
let year = day * 365;
let suffix = ' ago';
let elapsed = Math.floor((Date.now() - date) / 1000);
if (elapsed < minute) {
return 'just now';
}
// get an array in the form of [number, string]
let a = elapsed < hour && [Math.floor(elapsed / minute), 'minute'] ||
elapsed < day && [Math.floor(elapsed / hour), 'hour'] ||
elapsed < month && [Math.floor(elapsed / day), 'day'] ||
elapsed < year && [Math.floor(elapsed / month), 'month'] ||
[Math.floor(elapsed / year), 'year'];
// pluralise and append suffix
return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}
其他回答
可读性强且跨浏览器兼容的代码:
@Travis给出的
var DURATION_IN_SECONDS = { epochs: ['year', 'month', 'day', 'hour', 'minute'], year: 31536000, month: 2592000, day: 86400, hour: 3600, minute: 60 }; function getDuration(seconds) { var epoch, interval; for (var i = 0; i < DURATION_IN_SECONDS.epochs.length; i++) { epoch = DURATION_IN_SECONDS.epochs[i]; interval = Math.floor(seconds / DURATION_IN_SECONDS[epoch]); if (interval >= 1) { return { interval: interval, epoch: epoch }; } } }; function timeSince(date) { var seconds = Math.floor((new Date() - new Date(date)) / 1000); var duration = getDuration(seconds); var suffix = (duration.interval > 1 || duration.interval === 0) ? 's' : ''; return duration.interval + ' ' + duration.epoch + suffix; }; alert(timeSince('2015-09-17T18:53:23'));
在这种情况下可能有点过头了，但如果有机会，moment.js真的很棒!
js是一个javascript datetime库，在这种情况下使用它，你需要做:
moment(yourdate).fromNow()
http://momentjs.com/docs/#/displaying/fromnow/
2018附录:Luxon是一个新的现代图书馆，可能值得一看!
2022年附录:Day.js是一个较新的库，比Luxon轻80%左右，具有类似的功能。
这是对国际的另一种看法。RelativeTimeFormat
支持过去日期和将来日期 同时接受字符串和日期 易于添加自定义范围(编辑范围) 可以很容易地翻译为Intl.RelativeTimeFormat('ua')
console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), key); } } }
https://jsfiddle.net/tv9701uf
你可以使用Luxon:
DateTime.toRelative()
https://moment.github.io/luxon/api-docs/index.html#datetimetorelative
这里还有一些例子:
const DateTime = luxon.DateTime; // toRelative console.log(DateTime.now().minus({ seconds: 1 }).toRelative()) // 1 second ago console.log(DateTime.now().minus({ seconds: 10 }).toRelative()) // 10 seconds ago console.log(DateTime.now().minus({ days: 2 }).toRelative()) console.log(DateTime.now().minus({ years: 3 }).toRelative()) console.log(DateTime.now().plus({ years: 3 }).toRelative()) console.log(DateTime.now().plus({ days: 2 }).toRelative()) console.log(DateTime.now().plus({ seconds: 1 }).toRelative()) console.log(DateTime.now().plus({ seconds: 10 }).toRelative()) // toRelativeCalendar console.log(DateTime.now().minus({ seconds: 1 }).toRelativeCalendar()) // today console.log(DateTime.now().minus({ seconds: 10 }).toRelativeCalendar()) // today console.log(DateTime.now().minus({ days: 2 }).toRelativeCalendar()) console.log(DateTime.now().minus({ years: 3 }).toRelativeCalendar()) console.log(DateTime.now().plus({ years: 3 }).toRelativeCalendar()) console.log(DateTime.now().plus({ days: 2 }).toRelativeCalendar()) console.log(DateTime.now().plus({ seconds: 1 }).toRelativeCalendar()) console.log(DateTime.now().plus({ seconds: 10 }).toRelativeCalendar()) <script src="https://moment.github.io/luxon/global/luxon.min.js"></script>
我修改了Sky Sanders的版本。Math.floor(…)操作在if块中计算
var timeSince = function(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
if (seconds < 5){
return "just now";
}else if (seconds < 60){
return seconds + " seconds ago";
}
else if (seconds < 3600) {
minutes = Math.floor(seconds/60)
if(minutes > 1)
return minutes + " minutes ago";
else
return "1 minute ago";
}
else if (seconds < 86400) {
hours = Math.floor(seconds/3600)
if(hours > 1)
return hours + " hours ago";
else
return "1 hour ago";
}
//2 days and no more
else if (seconds < 172800) {
days = Math.floor(seconds/86400)
if(days > 1)
return days + " days ago";
else
return "1 day ago";
}
else{
//return new Date(time).toLocaleDateString();
return date.getDate().toString() + " " + months[date.getMonth()] + ", " + date.getFullYear();
}
}
