问题是如何将JavaScript Date格式化为一个字符串，声明时间经过，类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
您可能需要查看humanized_time_span: https://github.com/layam/js_humanized_time_span
它与框架无关，并且完全可定制。
只需下载/包含脚本，然后你可以这样做:
humanized_time_span("2011-05-11 12:00:00")
=> '3 hours ago'
humanized_time_span("2011-05-11 12:00:00", "2011-05-11 16:00:00)
=> '4 hours ago'
甚至是这样:
var custom_date_formats = {
past: [
{ ceiling: 60, text: "less than a minute ago" },
{ ceiling: 86400, text: "$hours hours, $minutes minutes and $seconds seconds ago" },
{ ceiling: null, text: "$years years ago" }
],
future: [
{ ceiling: 60, text: "in less than a minute" },
{ ceiling: 86400, text: "in $hours hours, $minutes minutes and $seconds seconds time" },
{ ceiling: null, text: "in $years years" }
]
}
humanized_time_span("2010/09/10 10:00:00", "2010/09/10 10:00:05", custom_date_formats)
=> "less than a minute ago"
更多信息请阅读文档。
其他回答
我一直在寻找这个问题的答案，并且几乎实现了其中一个解决方案，但一位同事提醒我检查react-intl库，因为我们已经在使用它了。
所以在解决方案中…在使用react-intl库的情况下，它们有一个<FormattedRelative>组件。
https://github.com/yahoo/react-intl/wiki/Components#formattedrelative
您可能需要查看humanized_time_span: https://github.com/layam/js_humanized_time_span
它与框架无关，并且完全可定制。
只需下载/包含脚本，然后你可以这样做:
humanized_time_span("2011-05-11 12:00:00")
=> '3 hours ago'
humanized_time_span("2011-05-11 12:00:00", "2011-05-11 16:00:00)
=> '4 hours ago'
甚至是这样:
var custom_date_formats = {
past: [
{ ceiling: 60, text: "less than a minute ago" },
{ ceiling: 86400, text: "$hours hours, $minutes minutes and $seconds seconds ago" },
{ ceiling: null, text: "$years years ago" }
],
future: [
{ ceiling: 60, text: "in less than a minute" },
{ ceiling: 86400, text: "in $hours hours, $minutes minutes and $seconds seconds time" },
{ ceiling: null, text: "in $years years" }
]
}
humanized_time_span("2010/09/10 10:00:00", "2010/09/10 10:00:05", custom_date_formats)
=> "less than a minute ago"
更多信息请阅读文档。
以下是对Sky Sander的解决方案的轻微修改，允许日期作为字符串输入，并能够显示像“1分钟”而不是“73秒”这样的跨度
var timeSince = function(date) { if (typeof date !== 'object') { date = new Date(date); } var seconds = Math.floor((new Date() - date) / 1000); var intervalType; var interval = Math.floor(seconds / 31536000); if (interval >= 1) { intervalType = 'year'; } else { interval = Math.floor(seconds / 2592000); if (interval >= 1) { intervalType = 'month'; } else { interval = Math.floor(seconds / 86400); if (interval >= 1) { intervalType = 'day'; } else { interval = Math.floor(seconds / 3600); if (interval >= 1) { intervalType = "hour"; } else { interval = Math.floor(seconds / 60); if (interval >= 1) { intervalType = "minute"; } else { interval = seconds; intervalType = "second"; } } } } } if (interval > 1 || interval === 0) { intervalType += 's'; } return interval + ' ' + intervalType; }; var aDay = 24 * 60 * 60 * 1000; console.log(timeSince(new Date(Date.now() - aDay))); console.log(timeSince(new Date(Date.now() - aDay * 2)));
我修改了Sky Sanders的版本。Math.floor(…)操作在if块中计算
var timeSince = function(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
if (seconds < 5){
return "just now";
}else if (seconds < 60){
return seconds + " seconds ago";
}
else if (seconds < 3600) {
minutes = Math.floor(seconds/60)
if(minutes > 1)
return minutes + " minutes ago";
else
return "1 minute ago";
}
else if (seconds < 86400) {
hours = Math.floor(seconds/3600)
if(hours > 1)
return hours + " hours ago";
else
return "1 hour ago";
}
//2 days and no more
else if (seconds < 172800) {
days = Math.floor(seconds/86400)
if(days > 1)
return days + " days ago";
else
return "1 day ago";
}
else{
//return new Date(time).toLocaleDateString();
return date.getDate().toString() + " " + months[date.getMonth()] + ", " + date.getFullYear();
}
}
这是一个简化版的@sky-sanders的回答。
function timeSince(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
var description = ["years", "months", "days", "hours", "minutes", "seconds"]
var result = [];
var interval = seconds;
for (i = 0; i < divisors.length; i++) {
interval = Math.floor(seconds / divisors[i])
if (interval > 1) {
result.push(interval + " " + description[i])
}
seconds -= interval * divisors[i]
}
return result.join(" ")
}
