是否有一种方法可以方便地在Python中定义类c结构?我厌倦了写这样的东西:
class MyStruct():
def __init__(self, field1, field2, field3):
self.field1 = field1
self.field2 = field2
self.field3 = field3
是否有一种方法可以方便地在Python中定义类c结构?我厌倦了写这样的东西:
class MyStruct():
def __init__(self, field1, field2, field3):
self.field1 = field1
self.field2 = field2
self.field3 = field3
当前回答
你可以用元组来做很多你在C语言中使用结构体的事情(比如x,y坐标或RGB颜色)。
对于其他任何东西,你可以使用字典,或像这样的实用程序类:
>>> class Bunch:
... def __init__(self, **kwds):
... self.__dict__.update(kwds)
...
>>> mystruct = Bunch(field1=value1, field2=value2)
我认为“权威”的讨论在这里,在Python Cookbook的出版版本中。
其他回答
每当我需要一个“行为像字典一样的即时数据对象”(我不会想到C结构体!),我就会想到这个可爱的hack:
class Map(dict):
def __init__(self, **kwargs):
super(Map, self).__init__(**kwargs)
self.__dict__ = self
现在你可以说:
struct = Map(field1='foo', field2='bar', field3=42)
self.assertEquals('bar', struct.field2)
self.assertEquals(42, struct['field3'])
当你需要一个“不是类的数据包”的时候,非常方便,当命名元组是不可理解的……
也许你正在寻找没有构造函数的struct:
class Sample:
name = ''
average = 0.0
values = None # list cannot be initialized here!
s1 = Sample()
s1.name = "sample 1"
s1.values = []
s1.values.append(1)
s1.values.append(2)
s1.values.append(3)
s2 = Sample()
s2.name = "sample 2"
s2.values = []
s2.values.append(4)
for v in s1.values: # prints 1,2,3 --> OK.
print v
print "***"
for v in s2.values: # prints 4 --> OK.
print v
就我个人而言,我也喜欢这种变体。它扩展了@dF的答案。
class struct:
def __init__(self, *sequential, **named):
fields = dict(zip(sequential, [None]*len(sequential)), **named)
self.__dict__.update(fields)
def __repr__(self):
return str(self.__dict__)
它支持两种初始化模式(可以混合使用):
# Struct with field1, field2, field3 that are initialized to None.
mystruct1 = struct("field1", "field2", "field3")
# Struct with field1, field2, field3 that are initialized according to arguments.
mystruct2 = struct(field1=1, field2=2, field3=3)
而且,它打印得更好:
print(mystruct2)
# Prints: {'field3': 3, 'field1': 1, 'field2': 2}
有一个python包正是用于此目的。看到cstruct2py
cstruct2py是一个纯python库,用于从C代码生成python类,并使用它们来打包和解包数据。该库可以解析C头文件(结构体、联合、枚举和数组声明),并在python中模拟它们。生成的python类可以解析和打包数据。
例如:
typedef struct {
int x;
int y;
} Point;
after generating pythonic class...
p = Point(x=0x1234, y=0x5678)
p.packed == "\x34\x12\x00\x00\x78\x56\x00\x00"
如何使用
首先,我们需要生成python结构体:
import cstruct2py
parser = cstruct2py.c2py.Parser()
parser.parse_file('examples/example.h')
现在我们可以从C代码中导入所有的名称:
parser.update_globals(globals())
我们也可以直接这样做:
A = parser.parse_string('struct A { int x; int y;};')
使用C代码中的类型和定义
a = A()
a.x = 45
print a
buf = a.packed
b = A(buf)
print b
c = A('aaaa11112222', 2)
print c
print repr(c)
输出将是:
{'x':0x2d, 'y':0x0}
{'x':0x2d, 'y':0x0}
{'x':0x31316161, 'y':0x32323131}
A('aa111122', x=0x31316161, y=0x32323131)
克隆
对于克隆cstruct2py运行:
git clone https://github.com/st0ky/cstruct2py.git --recursive
还可以按位置将初始化参数传递给实例变量
# Abstract struct class
class Struct:
def __init__ (self, *argv, **argd):
if len(argd):
# Update by dictionary
self.__dict__.update (argd)
else:
# Update by position
attrs = filter (lambda x: x[0:2] != "__", dir(self))
for n in range(len(argv)):
setattr(self, attrs[n], argv[n])
# Specific class
class Point3dStruct (Struct):
x = 0
y = 0
z = 0
pt1 = Point3dStruct()
pt1.x = 10
print pt1.x
print "-"*10
pt2 = Point3dStruct(5, 6)
print pt2.x, pt2.y
print "-"*10
pt3 = Point3dStruct (x=1, y=2, z=3)
print pt3.x, pt3.y, pt3.z
print "-"*10