字典updateValue更新字典中现有键的值，如果键不存在，则添加新的键-值对。

的例子,

var caseStatusParams: [String: AnyObject] = ["userId" : UserDefault.userID ]
caseStatusParams.updateValue("Hello" as AnyObject, forKey: "otherNotes")

结果- - - - - -

▿  : 2 elements
    - key : "userId"
    - value : 866
▿  : 2 elements
    - key : "otherNotes"
    - value : "Hello"

如果你想修改或更新NSDictionary那么 首先，将它类型转换为NSMutableDictionary

let newdictionary = NSDictionary as NSMutableDictionary

然后简单地使用

 newdictionary.setValue(value: AnyObject?, forKey: String)

给出以下两本词典:

var dic1 = ["a": 1, "c": 2]
var dic2 = ["e": 3, "f": 4]

下面是如何添加从dic2到dic1的所有项:

dic2.forEach {
   dic1[$0.key] = $0.value
}

我添加了字典扩展

extension Dictionary {   
  func cloneWith(_ dict: [Key: Value]) -> [Key: Value] {
    var result = self
    dict.forEach { key, value in result[key] = value }
    return result  
  }
}

你可以像这样使用克隆

 newDictionary = dict.reduce([3 : "efg"]) { r, e in r.cloneWith(e) }

斯威夫特 3+

向Dictionary分配新值的示例。你需要声明它为NSMutableDictionary:

var myDictionary: NSMutableDictionary = [:]
let newValue = 1
myDictionary["newKey"] = newValue
print(myDictionary)

添加新元素只需设置:

listParameters["your parameter"] = value