我在玩苹果的新Swift编程语言,遇到了一些问题…
目前我试图读取一个plist文件,在Objective-C中,我会做以下工作来获取内容作为NSDictionary:
NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Config" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:filePath];
我如何得到一个plist作为一个字典在Swift?
我假设我可以得到路径到plist:
let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")
当这工作(如果它是正确的?):我如何获得内容作为一个字典?
还有一个更普遍的问题:
是否可以使用默认的NS*类?我想是的……还是我遗漏了什么?据我所知,默认框架NS*类仍然有效,可以使用吗?
斯威夫特5
如果你想获取某个键的特定值,那么我们可以使用下面的扩展,它使用Bundle上的infoDictionary属性。
可以使用Bundle.main.infoDictionary获取所有信息。在表单字典中plist值,因此我们可以直接使用Bundle上的object(forInfoDictionaryKey: key)方法查询
extension Bundle {
static func infoPlistValue(forKey key: String) -> Any? {
guard let value = Bundle.main.object(forInfoDictionaryKey: key) else {
return nil
}
return value
}
}
使用
guard let apiURL = Bundle.infoPlistValue(forKey: "API_URL_KEY") as? String else { return }
我使用swift字典,但在我的文件管理器类中转换它们和nsdictionary,如下所示:
func writePlist(fileName:String, myDict:Dictionary<String, AnyObject>){
let docsDir:String = dirPaths[0] as String
let docPath = docsDir + "/" + fileName
let thisDict = myDict as NSDictionary
if(thisDict.writeToFile(docPath, atomically: true)){
NSLog("success")
} else {
NSLog("failure")
}
}
func getPlist(fileName:String)->Dictionary<String, AnyObject>{
let docsDir:String = dirPaths[0] as String
let docPath = docsDir + "/" + fileName
let thisDict = NSDictionary(contentsOfFile: docPath)
return thisDict! as! Dictionary<String, AnyObject>
}
这似乎是最不麻烦的读写方式,但让我的其余代码保持尽可能快。
你仍然可以在Swift中使用nsdictionary:
Swift 4
var nsDictionary: NSDictionary?
if let path = Bundle.main.path(forResource: "Config", ofType: "plist") {
nsDictionary = NSDictionary(contentsOfFile: path)
}
Swift 3+
if let path = Bundle.main.path(forResource: "Config", ofType: "plist"),
let myDict = NSDictionary(contentsOfFile: path){
// Use your myDict here
}
以及旧版本的Swift
var myDict: NSDictionary?
if let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist") {
myDict = NSDictionary(contentsOfFile: path)
}
if let dict = myDict {
// Use your dict here
}
NSClasses仍然可用,完全可以在Swift中使用。我想他们可能很快就会把重点转移到swift上,但是目前swift api并没有核心NSClasses的所有功能。
Swift 2.0:访问信息。Plist
我有一个名为CoachMarksDictionary的字典,在信息中具有布尔值。Plist。我想访问bool值并使其为真。
let path = NSBundle.mainBundle().pathForResource("Info", ofType: "plist")!
let dict = NSDictionary(contentsOfFile: path) as! [String: AnyObject]
if let CoachMarksDict = dict["CoachMarksDictionary"] {
print("Info.plist : \(CoachMarksDict)")
var dashC = CoachMarksDict["DashBoardCompleted"] as! Bool
print("DashBoardCompleted state :\(dashC) ")
}
写给Plist:
自定义Plist:-
Make from File-New-File-Resource-PropertyList。增加了三个字符串:DashBoard_New, DashBoard_Draft, DashBoard_Completed)
func writeToCoachMarksPlist(status:String?,keyName:String?)
{
let path1 = NSBundle.mainBundle().pathForResource("CoachMarks", ofType: "plist")
let coachMarksDICT = NSMutableDictionary(contentsOfFile: path1!)! as NSMutableDictionary
var coachMarksMine = coachMarksDICT.objectForKey(keyName!)
coachMarksMine = status
coachMarksDICT.setValue(status, forKey: keyName!)
coachMarksDICT.writeToFile(path1!, atomically: true)
}
该方法可以调用为
self.writeToCoachMarksPlist(" true - means user has checked the marks",keyName: "the key in the CoachMarks dictionary").