我如何从两个不同的表(叫他们tab1和tab2)选择计数(*)有作为结果:
Count_1 Count_2
123 456
我试过了:
select count(*) Count_1 from schema.tab1 union all select count(*) Count_2 from schema.tab2
但我所拥有的只有:
Count_1
123
456
我如何从两个不同的表(叫他们tab1和tab2)选择计数(*)有作为结果:
Count_1 Count_2
123 456
我试过了:
select count(*) Count_1 from schema.tab1 union all select count(*) Count_2 from schema.tab2
但我所拥有的只有:
Count_1
123
456
当前回答
select
t1.Count_1,t2.Count_2
from
(SELECT count(1) as Count_1 FROM tab1) as t1,
(SELECT count(1) as Count_2 FROM tab2) as t2
其他回答
我的经验是使用SQL Server,但是你能做到:
select (select count(*) from table1) as count1,
(select count(*) from table2) as count2
在SQL Server我得到的结果,你是后。
我很快想到了:
Select (select count(*) from Table1) as Count1, (select count(*) from Table2) as Count2
注意:我在SQL Server中测试了这个,所以从Dual是不必要的(因此存在差异)。
如果表(或者至少是一个键列)是相同类型的,那么就先做联合,然后计数。
select count(*)
from (select tab1key as key from schema.tab1
union all
select tab2key as key from schema.tab2
)
或者把你的语句加上另一个和()。
select sum(amount) from
(
select count(*) amount from schema.tab1 union all select count(*) amount from schema.tab2
)
Declare @all int
SET @all = (select COUNT(*) from tab1) + (select count(*) from tab2)
Print @all
or
SELECT (select COUNT(*) from tab1) + (select count(*) from tab2)
其他略有不同的方法:
with t1_count as (select count(*) c1 from t1),
t2_count as (select count(*) c2 from t2)
select c1,
c2
from t1_count,
t2_count
/
select c1,
c2
from (select count(*) c1 from t1) t1_count,
(select count(*) c2 from t2) t2_count
/