public static String getdeviceIpAddress() {
    try {
        for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
            NetworkInterface intf = en.nextElement();
            for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
                InetAddress inetAddress = enumIpAddr.nextElement();
                if (!inetAddress.isLoopbackAddress() && inetAddress instanceof Inet4Address) {
                    return inetAddress.getHostAddress();
                }
            }
        }
    } catch (SocketException ex) {
        ex.printStackTrace();
    }
    return null;
}

你可以使用LinkProperties。建议用于新的Android版本。

此功能检索WiFi和移动数据的本地IP地址。它需要Manifest.permission。ACCESS_NETWORK_STATE许可。

@Nullable
public static String getDeviceIpAddress(@NonNull ConnectivityManager connectivityManager) {
    LinkProperties linkProperties = connectivityManager.getLinkProperties(connectivityManager.getActiveNetwork());
    InetAddress inetAddress;
    for(LinkAddress linkAddress : linkProperties.getLinkAddresses()) {
        inetAddress = linkAddress.getAddress();
        if (inetAddress instanceof Inet4Address
                && !inetAddress.isLoopbackAddress()
                && inetAddress.isSiteLocalAddress()) {
            return inetAddress.getHostAddress();
        }
    }
    return null;
}

最近，一个IP地址仍然由getLocalIpAddress()返回，尽管与网络断开连接(没有服务指示器)。说明“设置>关于话机>状态”中显示的IP地址与应用程序想象的不一致。

我之前已经通过添加以下代码实现了一个解决方案:

ConnectivityManager cm = getConnectivityManager();
NetworkInfo net = cm.getActiveNetworkInfo();
if ((null == net) || !net.isConnectedOrConnecting()) {
    return null;
}

有谁听过吗?

我不使用Android，但我会用完全不同的方式来解决这个问题。

发送一个查询到谷歌，像这样: https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=my%20ip

并引用发布响应的HTML字段。您也可以直接查询到源。

谷歌最可能比你的应用程序存在的时间长。

只要记住，这可能是你的用户在这个时候没有互联网，你希望发生什么!

祝你好运

这是互联网上最简单的方法…… 首先，将此权限添加到您的manifest文件中…

“互联网” “ACCESS_NETWORK_STATE”

将此添加到Activity的onCreate文件中。

getPublicIP（）;

现在将这个函数添加到MainActivity.class中。

private void getPublicIP() { ArrayList<String> urls=new ArrayList<String>(); //to read each line new Thread(new Runnable(){ public void run(){ //TextView t; //to show the result, please declare and find it inside onCreate() try { // Create a URL for the desired page URL url = new URL("https://api.ipify.org/"); //My text file location //First open the connection HttpURLConnection conn=(HttpURLConnection) url.openConnection(); conn.setConnectTimeout(60000); // timing out in a minute BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream())); //t=(TextView)findViewById(R.id.TextView1); // ideally do this in onCreate() String str; while ((str = in.readLine()) != null) { urls.add(str); } in.close(); } catch (Exception e) { Log.d("MyTag",e.toString()); } //since we are in background thread, to post results we have to go back to ui thread. do the following for that PermissionsActivity.this.runOnUiThread(new Runnable(){ public void run(){ try { Toast.makeText(PermissionsActivity.this, "Public IP:"+urls.get(0), Toast.LENGTH_SHORT).show(); } catch (Exception e){ Toast.makeText(PermissionsActivity.this, "TurnOn wiffi to get public ip", Toast.LENGTH_SHORT).show(); } } }); } }).start(); }

在你的活动中，下面的函数getIpAddress(context)返回电话的IP地址:

public static String getIpAddress(Context context) {
    WifiManager wifiManager = (WifiManager) context.getApplicationContext()
                .getSystemService(WIFI_SERVICE);

    String ipAddress = intToInetAddress(wifiManager.getDhcpInfo().ipAddress).toString();

    ipAddress = ipAddress.substring(1);

    return ipAddress;
}

public static InetAddress intToInetAddress(int hostAddress) {
    byte[] addressBytes = { (byte)(0xff & hostAddress),
                (byte)(0xff & (hostAddress >> 8)),
                (byte)(0xff & (hostAddress >> 16)),
                (byte)(0xff & (hostAddress >> 24)) };

    try {
        return InetAddress.getByAddress(addressBytes);
    } catch (UnknownHostException e) {
        throw new AssertionError();
    }
}