是否可以使用一些代码获得设备的IP地址?
当前回答
根据我的测试,这是我的建议
import java.net.*;
import java.util.*;
public class hostUtil
{
public static String HOST_NAME = null;
public static String HOST_IPADDRESS = null;
public static String getThisHostName ()
{
if (HOST_NAME == null) obtainHostInfo ();
return HOST_NAME;
}
public static String getThisIpAddress ()
{
if (HOST_IPADDRESS == null) obtainHostInfo ();
return HOST_IPADDRESS;
}
protected static void obtainHostInfo ()
{
HOST_IPADDRESS = "127.0.0.1";
HOST_NAME = "localhost";
try
{
InetAddress primera = InetAddress.getLocalHost();
String hostname = InetAddress.getLocalHost().getHostName ();
if (!primera.isLoopbackAddress () &&
!hostname.equalsIgnoreCase ("localhost") &&
primera.getHostAddress ().indexOf (':') == -1)
{
// Got it without delay!!
HOST_IPADDRESS = primera.getHostAddress ();
HOST_NAME = hostname;
//System.out.println ("First try! " + HOST_NAME + " IP " + HOST_IPADDRESS);
return;
}
for (Enumeration<NetworkInterface> netArr = NetworkInterface.getNetworkInterfaces(); netArr.hasMoreElements();)
{
NetworkInterface netInte = netArr.nextElement ();
for (Enumeration<InetAddress> addArr = netInte.getInetAddresses (); addArr.hasMoreElements ();)
{
InetAddress laAdd = addArr.nextElement ();
String ipstring = laAdd.getHostAddress ();
String hostName = laAdd.getHostName ();
if (laAdd.isLoopbackAddress()) continue;
if (hostName.equalsIgnoreCase ("localhost")) continue;
if (ipstring.indexOf (':') >= 0) continue;
HOST_IPADDRESS = ipstring;
HOST_NAME = hostName;
break;
}
}
} catch (Exception ex) {}
}
}
其他回答
老实说,我对代码安全只是有点熟悉,所以这可能有点像黑客。但对我来说,这是最通用的方法:
package com.my_objects.ip;
import java.net.InetAddress;
import java.net.UnknownHostException;
public class MyIpByHost
{
public static void main(String a[])
{
try
{
InetAddress host = InetAddress.getByName("nameOfDevice or webAddress");
System.out.println(host.getHostAddress());
}
catch (UnknownHostException e)
{
e.printStackTrace();
}
} }
在AndroidManifest.xml中声明ACCESS_WIFI_STATE权限:
<uses-permission
android:name="android.permission.ACCESS_WIFI_STATE"/>
可以通过WifiManager获取IP地址:
Context context = requireContext().getApplicationContext();
WifiManager wm = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
String ip = Formatter.formatIpAddress(wm.getConnectionInfo().getIpAddress());
最近,一个IP地址仍然由getLocalIpAddress()返回,尽管与网络断开连接(没有服务指示器)。说明“设置>关于话机>状态”中显示的IP地址与应用程序想象的不一致。
我之前已经通过添加以下代码实现了一个解决方案:
ConnectivityManager cm = getConnectivityManager();
NetworkInfo net = cm.getActiveNetworkInfo();
if ((null == net) || !net.isConnectedOrConnecting()) {
return null;
}
有谁听过吗?
在Kotlin中,没有Formatter
private fun getIPAddress(useIPv4 : Boolean): String {
try {
var interfaces = Collections.list(NetworkInterface.getNetworkInterfaces())
for (intf in interfaces) {
var addrs = Collections.list(intf.getInetAddresses());
for (addr in addrs) {
if (!addr.isLoopbackAddress()) {
var sAddr = addr.getHostAddress();
var isIPv4: Boolean
isIPv4 = sAddr.indexOf(':')<0
if (useIPv4) {
if (isIPv4)
return sAddr;
} else {
if (!isIPv4) {
var delim = sAddr.indexOf('%') // drop ip6 zone suffix
if (delim < 0) {
return sAddr.toUpperCase()
}
else {
return sAddr.substring(0, delim).toUpperCase()
}
}
}
}
}
}
} catch (e: java.lang.Exception) { }
return ""
}
您不需要像目前提供的解决方案那样添加权限。以字符串形式下载此网站:
http://www.ip-api.com/json
or
http://www.telize.com/geoip
下载一个网站作为字符串可以用java代码完成:
http://www.itcuties.com/java/read-url-to-string/
像这样解析JSON对象:
https://stackoverflow.com/a/18998203/1987258
json属性“query”或“ip”包含ip地址。
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