是否有任何方法关闭我的JavaScript代码中的所有console.log语句,用于测试目的?
当前回答
当使用React时,你可以利用钩子来管理它,这样它就被限制在你的组件范围内
import { useEffect, useRef } from "react";
type LoggingReplacements = {
debug?: typeof console["debug"];
error?: typeof console["error"];
info?: typeof console["info"];
log?: typeof console["log"];
warn?: typeof console["warn"];
};
/**
* This replaces console.XXX loggers with custom implementations. It will restore console log on unmount of the component.
* @param replacements a map of replacement loggers. They're all optional and only the functions defined will be replaced.
*/
export function useReplaceLogging({
debug,
error,
info,
log,
warn,
}: LoggingReplacements): void {
const originalConsoleDebug = useRef(console.debug);
const originalConsoleError = useRef(console.error);
const originalConsoleInfo = useRef(console.info);
const originalConsoleLog = useRef(console.log);
const originalConsoleWarn = useRef(console.warn);
if (debug) {
console.debug = debug;
}
if (error) {
console.error = error;
}
if (info) {
console.info = info;
}
if (log) {
console.log = log;
}
if (warn) {
console.warn = warn;
}
useEffect(() => {
return function restoreConsoleLog() {
console.debug = originalConsoleDebug.current;
console.error = originalConsoleError.current;
console.info = originalConsoleInfo.current;
console.log = originalConsoleLog.current;
console.warn = originalConsoleWarn.current;
};
}, []);
}
在https://github.com/trajano/react-hooks/tree/master/src/useReplaceLogging上编写测试代码
其他回答
在脚本中重新定义console.log函数。
console.log = function() {}
够了,不再给控制台发消息了。
编辑:
扩展了Cide的想法。一个自定义记录器,您可以使用它从代码中切换登录。
从我的Firefox控制台:
var logger = function()
{
var oldConsoleLog = null;
var pub = {};
pub.enableLogger = function enableLogger()
{
if(oldConsoleLog == null)
return;
window['console']['log'] = oldConsoleLog;
};
pub.disableLogger = function disableLogger()
{
oldConsoleLog = console.log;
window['console']['log'] = function() {};
};
return pub;
}();
$(document).ready(
function()
{
console.log('hello');
logger.disableLogger();
console.log('hi', 'hiya');
console.log('this wont show up in console');
logger.enableLogger();
console.log('This will show up!');
}
);
如何使用上面的“记录器”?在就绪事件中,调用记录器。disableLogger使控制台消息不被记录。向记录器添加调用。enabllogger和logger。在希望将消息记录到控制台的方法中的disableLogger。
如果你正在使用gulp,那么你可以使用这个插件:
使用下面的命令安装这个插件: NPM安装gulp-remove-logging 接下来,将这一行添加到gulpfile中: Var gulp_remove_logging = require("gulp-remove-logging"); 最后,将配置设置(见下文)添加到gulpfile中。 任务配置 饮而尽。任务("remove_logging",函数(){ 返回gulp.src (" src / javascript / * * / * . js”) .pipe ( gulp_remove_logging () ) .pipe ( gulp.dest ( “构建/ javascript /” ) ); });
据我从文档中得知,Firebug没有提供任何变量来切换调试状态。相反,将console.log()包装在一个有条件地调用它的包装器中,即:
DEBUG = true; // set to false to disable debugging
function debug_log() {
if ( DEBUG ) {
console.log.apply(this, arguments);
}
}
为了不需要改变所有现有的调用,你可以使用这个代替:
DEBUG = true; // set to false to disable debugging
old_console_log = console.log;
console.log = function() {
if ( DEBUG ) {
old_console_log.apply(this, arguments);
}
}
https://stackoverflow.com/a/46189791/871166的简化
switch (process.env.LOG_LEVEL) {
case 'ERROR':
console.warn = function() {};
case 'WARN':
console.info = function() {};
case 'INFO':
console.log = function() {};
case 'LOG':
console.debug = function() {};
console.dir = function() {};
}
我认为2020年最简单、最容易理解的方法是创建一个像log()这样的全局函数,你可以选择以下方法之一:
const debugging = true;
function log(toLog) {
if (debugging) {
console.log(toLog);
}
}
function log(toLog) {
if (true) { // You could manually change it (Annoying, though)
console.log(toLog);
}
}
你可以说这些功能的缺点是:
您仍然在运行时调用函数 您必须记住在第二个选项中更改调试变量或if语句 您需要确保在加载所有其他文件之前加载了该函数
And my retorts to these statements is that this is the only method that won't completely remove the console or console.log function which I think is bad programming because other developers who are working on the website would have to realize that you ignorantly removed them. Also, you can't edit JavaScript source code in JavaScript, so if you really want something to just wipe all of those from the code you could use a minifier that minifies your code and removes all console.logs. Now, the choice is yours, what will you do?