函数中Python多行字符串的缩进方式是怎样的?

    def method():
        string = """line one
line two
line three"""

or

    def method():
        string = """line one
        line two
        line three"""

还是别的什么?

在第一个例子中,将字符串挂在函数外面看起来有点奇怪。


当前回答

你可能想和""对齐

def foo():
    string = """line one
             line two
             line three"""

由于换行符和空格包含在字符串本身中,因此必须对其进行后处理。如果你不想这样做,而你有很多文本,你可能想把它们单独存储在一个文本文件中。如果一个文本文件不适合你的应用程序,而你不想进行后期处理,我可能会选择

def foo():
    string = ("this is an "
              "implicitly joined "
              "string")

如果你想对一个多行字符串进行后处理,去掉你不需要的部分,你应该考虑textwrap模块或PEP 257中提供的后处理文档字符串的技术:

def trim(docstring):
    if not docstring:
        return ''
    # Convert tabs to spaces (following the normal Python rules)
    # and split into a list of lines:
    lines = docstring.expandtabs().splitlines()
    # Determine minimum indentation (first line doesn't count):
    indent = sys.maxint
    for line in lines[1:]:
        stripped = line.lstrip()
        if stripped:
            indent = min(indent, len(line) - len(stripped))
    # Remove indentation (first line is special):
    trimmed = [lines[0].strip()]
    if indent < sys.maxint:
        for line in lines[1:]:
            trimmed.append(line[indent:].rstrip())
    # Strip off trailing and leading blank lines:
    while trimmed and not trimmed[-1]:
        trimmed.pop()
    while trimmed and not trimmed[0]:
        trimmed.pop(0)
    # Return a single string:
    return '\n'.join(trimmed)

其他回答

你可能想和""对齐

def foo():
    string = """line one
             line two
             line three"""

由于换行符和空格包含在字符串本身中,因此必须对其进行后处理。如果你不想这样做,而你有很多文本,你可能想把它们单独存储在一个文本文件中。如果一个文本文件不适合你的应用程序,而你不想进行后期处理,我可能会选择

def foo():
    string = ("this is an "
              "implicitly joined "
              "string")

如果你想对一个多行字符串进行后处理,去掉你不需要的部分,你应该考虑textwrap模块或PEP 257中提供的后处理文档字符串的技术:

def trim(docstring):
    if not docstring:
        return ''
    # Convert tabs to spaces (following the normal Python rules)
    # and split into a list of lines:
    lines = docstring.expandtabs().splitlines()
    # Determine minimum indentation (first line doesn't count):
    indent = sys.maxint
    for line in lines[1:]:
        stripped = line.lstrip()
        if stripped:
            indent = min(indent, len(line) - len(stripped))
    # Remove indentation (first line is special):
    trimmed = [lines[0].strip()]
    if indent < sys.maxint:
        for line in lines[1:]:
            trimmed.append(line[indent:].rstrip())
    # Strip off trailing and leading blank lines:
    while trimmed and not trimmed[-1]:
        trimmed.pop()
    while trimmed and not trimmed[0]:
        trimmed.pop(0)
    # Return a single string:
    return '\n'.join(trimmed)

我的观点是,转义行尾以获得缩进

def foo():
    return "{}\n"\
           "freq: {}\n"\
           "temp: {}\n".format( time, freq, temp )

第一个选项是好的-包括缩进。 它是python风格的-提供了代码的可读性。

正确显示:

print string.lstrip()

我更喜欢

    def method():
        string = \
"""\
line one
line two
line three\
"""

or

    def method():
        string = """\
line one
line two
line three\
"""

这取决于您希望文本如何显示。如果你想让它全部向左对齐,那么要么像第一个代码片段那样格式化它,要么遍历所有的行,向左修剪所有的空间。