我需要在c++中加载和使用CSV文件数据。在这一点上,它实际上只是一个以逗号分隔的解析器(即不用担心转义新行和逗号)。主要需要的是逐行解析器,它将在每次调用方法时为下一行返回一个向量。
我发现这篇文章看起来很有前途: http://www.boost.org/doc/libs/1_35_0/libs/spirit/example/fundamental/list_parser.cpp
我从未使用过Boost's Spirit,但我愿意尝试一下。但前提是我忽略了一个更直接的解决方案。
我需要在c++中加载和使用CSV文件数据。在这一点上,它实际上只是一个以逗号分隔的解析器(即不用担心转义新行和逗号)。主要需要的是逐行解析器,它将在每次调用方法时为下一行返回一个向量。
我发现这篇文章看起来很有前途: http://www.boost.org/doc/libs/1_35_0/libs/spirit/example/fundamental/list_parser.cpp
我从未使用过Boost's Spirit,但我愿意尝试一下。但前提是我忽略了一个更直接的解决方案。
当前回答
如果可以的话,这是我简单快速的贡献。 没有提高。
接受分隔符和分隔符中的分隔符,只要成对或远离分隔符即可。
#include <iostream>
#include <vector>
#include <fstream>
std::vector<std::string> SplitCSV(const std::string &data, char separator, char delimiter)
{
std::vector<std::string> Values;
std::string Val = "";
bool VDel = false; // Is within delimiter?
size_t CDel = 0; // Delimiters counter within delimiters.
const char *C = data.c_str();
size_t P = 0;
do
{
if ((Val.length() == 0) && (C[P] == delimiter))
{
VDel = !VDel;
CDel = 0;
P++;
continue;
}
if (VDel)
{
if (C[P] == delimiter)
{
if (((CDel % 2) == 0) && ( (C[P+1] == separator) || (C[P+1] == 0) || (C[P+1] == '\n') || (C[P+1] == '\r') ))
{
VDel = false;
CDel = 0;
P++;
continue;
}
else
CDel++;
}
}
else
{
if (C[P] == separator)
{
Values.push_back(Val);
Val = "";
P++;
continue;
}
if ((C[P] == 0) || (C[P] == '\n') || (C[P] == '\r'))
break;
}
Val += C[P];
P++;
} while(P < data.length());
Values.push_back(Val);
return Values;
}
bool ReadCsv(const std::string &fname, std::vector<std::vector<std::string>> &data,
char separator = ',', char delimiter = '\"')
{
bool Ret = false;
std::ifstream FCsv(fname);
if (FCsv)
{
FCsv.seekg(0, FCsv.end);
size_t Siz = FCsv.tellg();
if (Siz > 0)
{
FCsv.seekg(0);
data.clear();
std::string Line;
while (getline(FCsv, Line, '\n'))
data.push_back(SplitCSV(Line, separator, delimiter));
Ret = true;
}
FCsv.close();
}
return Ret;
}
int main(int argc, char *argv[])
{
std::vector<std::vector<std::string>> Data;
ReadCsv("fsample.csv", Data);
return 0;
}
其他回答
不管怎样,下面是我的实现。它处理wstring输入,但是可以很容易地调整为string。它不处理字段中的换行符(因为我的应用程序也不这样做,但添加它的支持并不太难),它不符合RFC中的“\r\n”行尾(假设您使用std::getline),但它确实正确地处理空格修剪和双引号(希望如此)。
using namespace std;
// trim whitespaces around field or double-quotes, remove double-quotes and replace escaped double-quotes (double double-quotes)
wstring trimquote(const wstring& str, const wstring& whitespace, const wchar_t quotChar)
{
wstring ws;
wstring::size_type strBegin = str.find_first_not_of(whitespace);
if (strBegin == wstring::npos)
return L"";
wstring::size_type strEnd = str.find_last_not_of(whitespace);
wstring::size_type strRange = strEnd - strBegin + 1;
if((str[strBegin] == quotChar) && (str[strEnd] == quotChar))
{
ws = str.substr(strBegin+1, strRange-2);
strBegin = 0;
while((strEnd = ws.find(quotChar, strBegin)) != wstring::npos)
{
ws.erase(strEnd, 1);
strBegin = strEnd+1;
}
}
else
ws = str.substr(strBegin, strRange);
return ws;
}
pair<unsigned, unsigned> nextCSVQuotePair(const wstring& line, const wchar_t quotChar, unsigned ofs = 0)
{
pair<unsigned, unsigned> r;
r.first = line.find(quotChar, ofs);
r.second = wstring::npos;
if(r.first != wstring::npos)
{
r.second = r.first;
while(((r.second = line.find(quotChar, r.second+1)) != wstring::npos)
&& (line[r.second+1] == quotChar)) // WARNING: assumes null-terminated string such that line[r.second+1] always exist
r.second++;
}
return r;
}
unsigned parseLine(vector<wstring>& fields, const wstring& line)
{
unsigned ofs, ofs0, np;
const wchar_t delim = L',';
const wstring whitespace = L" \t\xa0\x3000\x2000\x2001\x2002\x2003\x2004\x2005\x2006\x2007\x2008\x2009\x200a\x202f\x205f";
const wchar_t quotChar = L'\"';
pair<unsigned, unsigned> quot;
fields.clear();
ofs = ofs0 = 0;
quot = nextCSVQuotePair(line, quotChar);
while((np = line.find(delim, ofs)) != wstring::npos)
{
if((np > quot.first) && (np < quot.second))
{ // skip delimiter inside quoted field
ofs = quot.second+1;
quot = nextCSVQuotePair(line, quotChar, ofs);
continue;
}
fields.push_back( trimquote(line.substr(ofs0, np-ofs0), whitespace, quotChar) );
ofs = ofs0 = np+1;
}
fields.push_back( trimquote(line.substr(ofs0), whitespace, quotChar) );
return fields.size();
}
不好意思,但是为了隐藏几行代码,这似乎是非常复杂的语法。
为什么不这样呢:
/**
Read line from a CSV file
@param[in] fp file pointer to open file
@param[in] vls reference to vector of strings to hold next line
*/
void readCSV( FILE *fp, std::vector<std::string>& vls )
{
vls.clear();
if( ! fp )
return;
char buf[10000];
if( ! fgets( buf,999,fp) )
return;
std::string s = buf;
int p,q;
q = -1;
// loop over columns
while( 1 ) {
p = q;
q = s.find_first_of(",\n",p+1);
if( q == -1 )
break;
vls.push_back( s.substr(p+1,q-p-1) );
}
}
int _tmain(int argc, _TCHAR* argv[])
{
std::vector<std::string> vls;
FILE * fp = fopen( argv[1], "r" );
if( ! fp )
return 1;
readCSV( fp, vls );
readCSV( fp, vls );
readCSV( fp, vls );
std::cout << "row 3, col 4 is " << vls[3].c_str() << "\n";
return 0;
}
使用流解析CSV文件行
我写了一个解析CSV文件行的小例子,如果需要,它可以用for和while循环来开发:
#include <iostream>
#include <fstream>
#include <string.h>
using namespace std;
int main() {
ifstream fin("Infile.csv");
ofstream fout("OutFile.csv");
string strline, strremain, strCol1 , strout;
string delimeter =";";
int d1;
继续到文件的末尾:
while (!fin.eof()){
从InFile获取第一行:
getline(fin,strline,'\n');
在直线上找到度距仪的位置:
d1 = strline.find(';');
然后解析第一列:
strCol1 = strline.substr(0,d1); // parse first Column
d1++;
strremain = strline.substr(d1); // remaining line
创建CSV格式输出行:
strout.append(strCol1);
strout.append(delimeter);
写行到输出文件:
fout << strout << endl; //out file line
}
fin.close();
fout.close();
return(0);
}
代码已编译并运行。好运!
如果您正在使用Visual Studio / MFC,下面的解决方案可能会使您的工作更轻松。它支持Unicode和MBCS,有注释,除了CString之外没有其他依赖项,对我来说工作得很好。它不支持在带引号的字符串中嵌入换行符,但我不在乎,只要它在这种情况下不崩溃,它不会崩溃。
总体策略是,将带引号的字符串和空字符串作为特殊情况处理,其余使用Tokenize。对于带引号的字符串,策略是找到真正的结束引号,跟踪是否遇到了连续的引号对。如果是,则使用Replace将成对转换为单个。毫无疑问,有更有效的方法,但在我的案例中,性能还不够重要,不足以证明进一步优化的合理性。
class CParseCSV {
public:
// Construction
CParseCSV(const CString& sLine);
// Attributes
bool GetString(CString& sDest);
protected:
CString m_sLine; // line to extract tokens from
int m_nLen; // line length in characters
int m_iPos; // index of current position
};
CParseCSV::CParseCSV(const CString& sLine) : m_sLine(sLine)
{
m_nLen = m_sLine.GetLength();
m_iPos = 0;
}
bool CParseCSV::GetString(CString& sDest)
{
if (m_iPos < 0 || m_iPos > m_nLen) // if position out of range
return false;
if (m_iPos == m_nLen) { // if at end of string
sDest.Empty(); // return empty token
m_iPos = -1; // really done now
return true;
}
if (m_sLine[m_iPos] == '\"') { // if current char is double quote
m_iPos++; // advance to next char
int iTokenStart = m_iPos;
bool bHasEmbeddedQuotes = false;
while (m_iPos < m_nLen) { // while more chars to parse
if (m_sLine[m_iPos] == '\"') { // if current char is double quote
// if next char exists and is also double quote
if (m_iPos < m_nLen - 1 && m_sLine[m_iPos + 1] == '\"') {
// found pair of consecutive double quotes
bHasEmbeddedQuotes = true; // request conversion
m_iPos++; // skip first quote in pair
} else // next char doesn't exist or is normal
break; // found closing quote; exit loop
}
m_iPos++; // advance to next char
}
sDest = m_sLine.Mid(iTokenStart, m_iPos - iTokenStart);
if (bHasEmbeddedQuotes) // if string contains embedded quote pairs
sDest.Replace(_T("\"\""), _T("\"")); // convert pairs to singles
m_iPos += 2; // skip closing quote and trailing delimiter if any
} else if (m_sLine[m_iPos] == ',') { // else if char is comma
sDest.Empty(); // return empty token
m_iPos++; // advance to next char
} else { // else get next comma-delimited token
sDest = m_sLine.Tokenize(_T(","), m_iPos);
}
return true;
}
// calling code should look something like this:
CStdioFile fIn(pszPath, CFile::modeRead);
CString sLine, sToken;
while (fIn.ReadString(sLine)) { // for each line of input file
if (!sLine.IsEmpty()) { // ignore blank lines
CParseCSV csv(sLine);
while (csv.GetString(sToken)) {
// do something with sToken here
}
}
}
使用Boost Tokenizer的解决方案:
std::vector<std::string> vec;
using namespace boost;
tokenizer<escaped_list_separator<char> > tk(
line, escaped_list_separator<char>('\\', ',', '\"'));
for (tokenizer<escaped_list_separator<char> >::iterator i(tk.begin());
i!=tk.end();++i)
{
vec.push_back(*i);
}