谁能告诉我如何在Swift中舍入一个双数值到x位小数点后数位?
我有:
var totalWorkTimeInHours = (totalWorkTime/60/60)
totalWorkTime是一个NSTimeInterval (double),单位为秒。
totalWorkTimeInHours会给我小时数,但它给我的时间量是如此长的精确数字,例如1.543240952039......
当我打印totalWorkTimeInHours时,我如何将其四舍五入到1.543 ?
谁能告诉我如何在Swift中舍入一个双数值到x位小数点后数位?
我有:
var totalWorkTimeInHours = (totalWorkTime/60/60)
totalWorkTime是一个NSTimeInterval (double),单位为秒。
totalWorkTimeInHours会给我小时数,但它给我的时间量是如此长的精确数字,例如1.543240952039......
当我打印totalWorkTimeInHours时,我如何将其四舍五入到1.543 ?
当前回答
Lots of example are using maths, the problem is floats are approximations of real number, there is no way to express 0.1 (1/10) exactly as a float just as there is no exact way to express ⅓ exactly using decimal points, so you need to ask your self exactly what your are trying to achieve, if you just want to display them leave them as they are in code, trying to round them is going to justify give you less accurate result as you are throwing away precious, round ⅓ in decimal notation to 1 decimal place is not going to give you a number closer to ⅓, us NumberFormate to round it, if you have something like a viewModel class it can be used to return a string representation to your models numbers. NumberFormaters give you lots of control on how numbers are formatted and the number of decimal places you want.
其他回答
在Swift 5.5和Xcode 13.2中:
let pi: Double = 3.14159265358979
String(format:"%.2f", pi)
例子:
附注:自Swift 2.0和Xcode 7.2以来一直如此
你可以添加这个扩展:
extension Double {
var clean: String {
return self.truncatingRemainder(dividingBy: 1) == 0 ? String(format: "%.0f", self) : String(format: "%.2f", self)
}
}
像这样叫它:
let ex: Double = 10.123546789
print(ex.clean) // 10.12
一个方便的方法是使用Double类型的扩展
extension Double {
var roundTo2f: Double {return Double(round(100 *self)/100) }
var roundTo3f: Double {return Double(round(1000*self)/1000) }
}
用法:
let regularPie: Double = 3.14159
var smallerPie: Double = regularPie.roundTo3f // results 3.142
var smallestPie: Double = regularPie.roundTo2f // results 3.14
为了避免Float不完美,请使用Decimal
extension Float {
func rounded(rule: NSDecimalNumber.RoundingMode, scale: Int) -> Float {
var result: Decimal = 0
var decimalSelf = NSNumber(value: self).decimalValue
NSDecimalRound(&result, &decimalSelf, scale, rule)
return (result as NSNumber).floatValue
}
}
前女友。 1075.58在使用Float时四舍五入为1075.57 1075.58在使用十进制时四舍五入为1075.58,比例为2和。down
如果你想在逗号后面只有0表示圆,试试这个:
extension Double {
func isInteger() -> Any {
let check = floor(self) == self
if check {
return Int(self)
} else {
return self
}
}
}
let toInt: Double = 10.0
let stillDouble: Double = 9.12
print(toInt.isInteger) // 10
print(stillDouble.isInteger) // 9.12