我如何从十六进制字符串格式创建一个UIColor,如#00FF00?
当前回答
你可以使用这个库
https://github.com/burhanuddin353/TFTColor
斯威夫特
UIColor.colorWithRGB(hexString: "FF34AE" alpha: 1.0)
objective - c
[UIColor colorWithRGBHexString:@"FF34AE" alpha:1.0f]
其他回答
我最终为UIColor创建了一个类别,我可以在我的其他项目中重用,并添加了这个函数:
+ (UIColor *)colorFromHex:(unsigned long)hex
{
return [UIColor colorWithRed:((float)((hex & 0xFF0000) >> 16))/255.0
green:((float)((hex & 0xFF00) >> 8))/255.0
blue:((float)(hex & 0xFF))/255.0
alpha:1.0];
}
用法是这样的:
UIColor *customRedColor = [UIColor colorFromHex:0x990000];
这比传递字符串并将其转换为数字然后移位位要快得多。
你也可以从你的.pch文件中导入类别,这样你就可以很容易地在你的应用程序中到处使用colorFromHex,就像它内置到UIColor中一样:
#ifdef __OBJC__
#import <UIKit/UIKit.h>
#import <Foundation/Foundation.h>
// Your other stuff here...
#import "UIColor+HexColor.h"
#endif
swift 1.2更新
class func colorWithHexString (hex:String) -> UIColor {
var cString: NSString = hex.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()).uppercaseString
if (cString.hasPrefix("#")) {
cString = cString.substringFromIndex(1)
}
if (count(cString as String) != 6) {
return UIColor.grayColor()
}
var rString: String = cString.substringToIndex(2)
var gString: String = (cString.substringFromIndex(2) as NSString).substringToIndex(2)
var bString: String = (cString.substringFromIndex(4) as NSString).substringToIndex(2)
var r:CUnsignedInt = 0, g:CUnsignedInt = 0, b:CUnsignedInt = 0;
NSScanner(string: rString).scanHexInt(&r)
NSScanner(string: gString).scanHexInt(&g)
NSScanner(string: bString).scanHexInt(&b)
return UIColor(red: CGFloat(Float(r) / 255.0), green: CGFloat(Float(g) / 255.0), blue: CGFloat(Float(b) / 255.0), alpha: CGFloat(1))
}
十六进制初始化
extension UIColor{
public convenience init(hex : String) {
var cString:String = hex.trimmingCharacters(in: .whitespacesAndNewlines).uppercased()
if (cString.hasPrefix("#")) {
cString.remove(at: cString.startIndex)
}
if ((cString.count) != 6) {
self.init(red: 1, green: 1, blue: 1, alpha: 1)
return
}
var rgbValue:UInt32 = 0
Scanner(string: cString).scanHexInt32(&rgbValue)
self.init(
red: CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgbValue & 0x0000FF) / 255.0,
alpha: CGFloat(1.0)
)
}
//Iniitailization
let myColor = UIColor(hex: "#452b4e")
编码愉快!享受! !
斯威夫特2.0:
将此方法添加到VC或扩展UIColor。
func colorWithHexString (hex:String) -> UIColor {
var cString:String = hex.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()).uppercaseString
if (cString.hasPrefix("#")) {
cString = (cString as NSString).substringFromIndex(1)
}
if (cString.characters.count != 6) {
return UIColor.grayColor()
}
let rString = (cString as NSString).substringToIndex(2)
let gString = ((cString as NSString).substringFromIndex(2) as NSString).substringToIndex(2)
let bString = ((cString as NSString).substringFromIndex(4) as NSString).substringToIndex(2)
var r:CUnsignedInt = 0, g:CUnsignedInt = 0, b:CUnsignedInt = 0;
NSScanner(string: rString).scanHexInt(&r)
NSScanner(string: gString).scanHexInt(&g)
NSScanner(string: bString).scanHexInt(&b)
return UIColor(red: CGFloat(r) / 255.0, green: CGFloat(g) / 255.0, blue: CGFloat(b) / 255.0, alpha: CGFloat(1))
}
用法:
loginButton.tintColor = self.colorWithHexString("#be1337")
OR
let hexColor = self.colorWithHexString("#be1337")
你可以做这样的扩展
extension UIColor {
convenience init(hex: UInt, alpha: CGFloat = 1) {
self.init(
red: CGFloat((hex & 0xFF0000) >> 16) / 255.0,
green: CGFloat((hex & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(hex & 0x0000FF) / 255.0,
alpha: alpha
)
}
}
像这样用在任何地方
let color1 = UIColor(hex: 0xffffff)
let color2 = UIColor(hex: 0xffffff, alpha: 0.2)
推荐文章
- 如何删除默认的导航栏空间在SwiftUI导航视图
- 如何在iOS中使用Swift编程segue
- Swift -整数转换为小时/分钟/秒
- Swift:声明一个空字典
- 在成功提交我的应用程序后,“太多符号文件”
- 首先添加一个UIView,甚至是导航栏
- 我如何改变UIButton标题颜色?
- 如何从UIImage (Cocoa Touch)或CGImage (Core Graphics)获取像素数据?
- 在Swift中如何调用GCD主线程上的参数方法?
- NSLayoutConstraints是可动画的吗?
- iOS -构建失败,CocoaPods无法找到头文件
- CFNetwork SSLHandshake iOS 9失败
- 请求失败:不可接受的内容类型:文本/html使用AFNetworking 2.0
- 缺少推荐的图标文件-该包不包含iPhone / iPod Touch的应用程序图标,像素为“120x120”,png格式
- 以编程方式创建segue