如果你想用django模板打印在页面中，那么下面的代码就足够了:

{{ birth_date|timesince }}

正如@[Tomasz Zielinski]和@ williams所建议的那样，python-dateutil可以只做5行。

from dateutil.relativedelta import *
from datetime import date
today = date.today()
dob = date(1982, 7, 5)
age = relativedelta(today, dob)

>>relativedelta(years=+33, months=+11, days=+16)`

serializers.py

age = serializers.SerializerMethodField('get_age')

class Meta:
    model = YourModel
    fields = [..,'','birthdate','age',..]


import datetime

def get_age(self, instance):
    return datetime.datetime.now().year - instance.birthdate.year

from datetime import date

days_in_year = 365.2425    
age = int((date.today() - birth_date).days / days_in_year)

在Python 3中，你可以对datetime.timedelta执行除法:

from datetime import date, timedelta

age = (date.today() - birth_date) // timedelta(days=365.2425)

为了便于阅读和理解，稍微修改了Danny的解决方案

    from datetime import date

    def calculate_age(birth_date):
        today = date.today()
        age = today.year - birth_date.year
        full_year_passed = (today.month, today.day) < (birth_date.month, birth_date.day)
        if not full_year_passed:
            age -= 1
        return age

一个比@DannyWAdairs稍微优雅一点的解决方案可能是使用.timetuple()方法[Python-doc]:

from datetime import date

def calculate_age(born):
    today = date.today()
    return today.year - born.year - (today.timetuple()[1:3] < born.timetuple()[1:3])

你可以很容易地使用这个来进一步推广它，将其粒度增加到秒，这样，如果它大于或等于当天的秒数，年龄就会增加，例如born是一个datetime对象:

from datetime import datetime

def calculate_age_with_seconds(born):
    today = datetime.now()
    return today.year - born.year - (today.timetuple()[1:6] < born.timetuple()[1:6])

这对于date或datetime对象都适用。