我怎么能从今天的日期和一个人的出生日期找到一个python年龄?出生日期来自Django模型中的DateField。
当前回答
延伸到丹尼·w·阿代尔回答,得到月也
def calculate_age(b):
t = date.today()
c = ((t.month, t.day) < (b.month, b.day))
c2 = (t.day< b.day)
return t.year - b.year - c,c*12+t.month-b.month-c2
其他回答
延伸到丹尼·w·阿代尔回答,得到月也
def calculate_age(b):
t = date.today()
c = ((t.month, t.day) < (b.month, b.day))
c2 = (t.day< b.day)
return t.year - b.year - c,c*12+t.month-b.month-c2
由于我没有看到正确的实现,我以这种方式重新编码了我的…
def age_in_years(from_date, to_date=datetime.date.today()):
if (DEBUG):
logger.debug("def age_in_years(from_date='%s', to_date='%s')" % (from_date, to_date))
if (from_date>to_date): # swap when the lower bound is not the lower bound
logger.debug('Swapping dates ...')
tmp = from_date
from_date = to_date
to_date = tmp
age_delta = to_date.year - from_date.year
month_delta = to_date.month - from_date.month
day_delta = to_date.day - from_date.day
if (DEBUG):
logger.debug("Delta's are : %i / %i / %i " % (age_delta, month_delta, day_delta))
if (month_delta>0 or (month_delta==0 and day_delta>=0)):
return age_delta
return (age_delta-1)
如果你出生在2月29日,你就认为自己在2月28日是“18岁”,这是错误的。 交换边界可以省略…这只是我的代码的个人方便:)
from datetime import date
days_in_year = 365.2425
age = int((date.today() - birth_date).days / days_in_year)
在Python 3中,你可以对datetime.timedelta执行除法:
from datetime import date, timedelta
age = (date.today() - birth_date) // timedelta(days=365.2425)
from datetime import date
def calculate_age(born):
today = date.today()
try:
birthday = born.replace(year=today.year)
except ValueError: # raised when birth date is February 29 and the current year is not a leap year
birthday = born.replace(year=today.year, month=born.month+1, day=1)
if birthday > today:
return today.year - born.year - 1
else:
return today.year - born.year
更新:使用丹尼的解决方案,效果更好
为了便于阅读和理解,稍微修改了Danny的解决方案
from datetime import date
def calculate_age(birth_date):
today = date.today()
age = today.year - birth_date.year
full_year_passed = (today.month, today.day) < (birth_date.month, birth_date.day)
if not full_year_passed:
age -= 1
return age
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