我怎么能从今天的日期和一个人的出生日期找到一个python年龄?出生日期来自Django模型中的DateField。


当前回答

你可以使用Python 3来完成这一切。只需运行下面的代码就可以了。

# Creating a variables:

greeting = "Hello, "
name = input("what is your name?")
birth_year = input("Which year you were born?")
response = "Your age is "

# Converting string variable to int:

calculation = 2020 - int(birth_year) 


# Printing:

print(f'{greeting}{name}. {response}{calculation}')

其他回答

进口日期时间

def age(date_of_birth):
    if date_of_birth > datetime.date.today().replace(year = date_of_birth.year):
        return datetime.date.today().year - date_of_birth.year - 1
    else:
        return datetime.date.today().year - date_of_birth.year

在你的情况下:

import datetime

# your model
def age(self):
    if self.birthdate > datetime.date.today().replace(year = self.birthdate.year):
        return datetime.date.today().year - self.birthdate.year - 1
    else:
        return datetime.date.today().year - self.birthdate.year

考虑到int(True)是1,int(False)是0,元组比较从左到右,这可以做得更简单:

from datetime import date

def calculate_age(born):
    today = date.today()
    return today.year - born.year - ((today.month, today.day) < (born.month, born.day))
import datetime

今天的日期

td=datetime.datetime.now().date() 

你的出生年月日

bd=datetime.date(1989,3,15)

你的年龄

age_years=int((td-bd).days /365.25)

下面是一个用年、月或日来计算一个人年龄的方法。

假设一个人的出生日期是2012-01-17T00:00:00 因此,他的年龄在2013-01-16T00:00:00将是11个月

或者他出生在2012-12-17T00:00:00, 他的年龄在2013-01-12T00:00:00将是26天

或者他出生在2000-02-29T00:00:00, 他的年龄在2012-02-29T00:00:00将是12岁

您将需要导入datetime。

代码如下:

def get_person_age(date_birth, date_today):

"""
At top level there are three possibilities : Age can be in days or months or years.
For age to be in years there are two cases: Year difference is one or Year difference is more than 1
For age to be in months there are two cases: Year difference is 0 or 1
For age to be in days there are 4 possibilities: Year difference is 1(20-dec-2012 - 2-jan-2013),
                                                 Year difference is 0, Months difference is 0 or 1
"""
years_diff = date_today.year - date_birth.year
months_diff = date_today.month - date_birth.month
days_diff = date_today.day - date_birth.day
age_in_days = (date_today - date_birth).days

age = years_diff
age_string = str(age) + " years"

# age can be in months or days.
if years_diff == 0:
    if months_diff == 0:
        age = age_in_days
        age_string = str(age) + " days"
    elif months_diff == 1:
        if days_diff < 0:
            age = age_in_days
            age_string = str(age) + " days"
        else:
            age = months_diff
            age_string = str(age) + " months"
    else:
        if days_diff < 0:
            age = months_diff - 1
        else:
            age = months_diff
        age_string = str(age) + " months"
# age can be in years, months or days.
elif years_diff == 1:
    if months_diff < 0:
        age = months_diff + 12
        age_string = str(age) + " months" 
        if age == 1:
            if days_diff < 0:
                age = age_in_days
                age_string = str(age) + " days" 
        elif days_diff < 0:
            age = age-1
            age_string = str(age) + " months"
    elif months_diff == 0:
        if days_diff < 0:
            age = 11
            age_string = str(age) + " months"
        else:
            age = 1
            age_string = str(age) + " years"
    else:
        age = 1
        age_string = str(age) + " years"
# The age is guaranteed to be in years.
else:
    if months_diff < 0:
        age = years_diff - 1
    elif months_diff == 0:
        if days_diff < 0:
            age = years_diff - 1
        else:
            age = years_diff
    else:
        age = years_diff
    age_string = str(age) + " years"

if age == 1:
    age_string = age_string.replace("years", "year").replace("months", "month").replace("days", "day")

return age_string

以上代码中使用的一些额外函数是:

def get_todays_date():
    """
    This function returns todays date in proper date object format
    """
    return datetime.now()

And

def get_date_format(str_date):
"""
This function converts string into date type object
"""
str_date = str_date.split("T")[0]
return datetime.strptime(str_date, "%Y-%m-%d")

现在,我们必须为get_date_format()提供像2000-02-29T00:00:00这样的字符串

它将把它转换为日期类型对象,该对象将被提供给get_person_age(date_birth, date_today)。

函数get_person_age(date_birth, date_today)将返回字符串格式的年龄。

正如@[Tomasz Zielinski]和@ williams所建议的那样,python-dateutil可以只做5行。

from dateutil.relativedelta import *
from datetime import date
today = date.today()
dob = date(1982, 7, 5)
age = relativedelta(today, dob)

>>relativedelta(years=+33, months=+11, days=+16)`