我怎么能从今天的日期和一个人的出生日期找到一个python年龄?出生日期来自Django模型中的DateField。
当前回答
你可以使用Python 3来完成这一切。只需运行下面的代码就可以了。
# Creating a variables:
greeting = "Hello, "
name = input("what is your name?")
birth_year = input("Which year you were born?")
response = "Your age is "
# Converting string variable to int:
calculation = 2020 - int(birth_year)
# Printing:
print(f'{greeting}{name}. {response}{calculation}')
其他回答
进口日期时间
def age(date_of_birth):
if date_of_birth > datetime.date.today().replace(year = date_of_birth.year):
return datetime.date.today().year - date_of_birth.year - 1
else:
return datetime.date.today().year - date_of_birth.year
在你的情况下:
import datetime
# your model
def age(self):
if self.birthdate > datetime.date.today().replace(year = self.birthdate.year):
return datetime.date.today().year - self.birthdate.year - 1
else:
return datetime.date.today().year - self.birthdate.year
考虑到int(True)是1,int(False)是0,元组比较从左到右,这可以做得更简单:
from datetime import date
def calculate_age(born):
today = date.today()
return today.year - born.year - ((today.month, today.day) < (born.month, born.day))
import datetime
今天的日期
td=datetime.datetime.now().date()
你的出生年月日
bd=datetime.date(1989,3,15)
你的年龄
age_years=int((td-bd).days /365.25)
下面是一个用年、月或日来计算一个人年龄的方法。
假设一个人的出生日期是2012-01-17T00:00:00 因此,他的年龄在2013-01-16T00:00:00将是11个月
或者他出生在2012-12-17T00:00:00, 他的年龄在2013-01-12T00:00:00将是26天
或者他出生在2000-02-29T00:00:00, 他的年龄在2012-02-29T00:00:00将是12岁
您将需要导入datetime。
代码如下:
def get_person_age(date_birth, date_today):
"""
At top level there are three possibilities : Age can be in days or months or years.
For age to be in years there are two cases: Year difference is one or Year difference is more than 1
For age to be in months there are two cases: Year difference is 0 or 1
For age to be in days there are 4 possibilities: Year difference is 1(20-dec-2012 - 2-jan-2013),
Year difference is 0, Months difference is 0 or 1
"""
years_diff = date_today.year - date_birth.year
months_diff = date_today.month - date_birth.month
days_diff = date_today.day - date_birth.day
age_in_days = (date_today - date_birth).days
age = years_diff
age_string = str(age) + " years"
# age can be in months or days.
if years_diff == 0:
if months_diff == 0:
age = age_in_days
age_string = str(age) + " days"
elif months_diff == 1:
if days_diff < 0:
age = age_in_days
age_string = str(age) + " days"
else:
age = months_diff
age_string = str(age) + " months"
else:
if days_diff < 0:
age = months_diff - 1
else:
age = months_diff
age_string = str(age) + " months"
# age can be in years, months or days.
elif years_diff == 1:
if months_diff < 0:
age = months_diff + 12
age_string = str(age) + " months"
if age == 1:
if days_diff < 0:
age = age_in_days
age_string = str(age) + " days"
elif days_diff < 0:
age = age-1
age_string = str(age) + " months"
elif months_diff == 0:
if days_diff < 0:
age = 11
age_string = str(age) + " months"
else:
age = 1
age_string = str(age) + " years"
else:
age = 1
age_string = str(age) + " years"
# The age is guaranteed to be in years.
else:
if months_diff < 0:
age = years_diff - 1
elif months_diff == 0:
if days_diff < 0:
age = years_diff - 1
else:
age = years_diff
else:
age = years_diff
age_string = str(age) + " years"
if age == 1:
age_string = age_string.replace("years", "year").replace("months", "month").replace("days", "day")
return age_string
以上代码中使用的一些额外函数是:
def get_todays_date():
"""
This function returns todays date in proper date object format
"""
return datetime.now()
And
def get_date_format(str_date):
"""
This function converts string into date type object
"""
str_date = str_date.split("T")[0]
return datetime.strptime(str_date, "%Y-%m-%d")
现在,我们必须为get_date_format()提供像2000-02-29T00:00:00这样的字符串
它将把它转换为日期类型对象,该对象将被提供给get_person_age(date_birth, date_today)。
函数get_person_age(date_birth, date_today)将返回字符串格式的年龄。
正如@[Tomasz Zielinski]和@ williams所建议的那样,python-dateutil可以只做5行。
from dateutil.relativedelta import *
from datetime import date
today = date.today()
dob = date(1982, 7, 5)
age = relativedelta(today, dob)
>>relativedelta(years=+33, months=+11, days=+16)`
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