我需要通过GPS程序获得我的当前位置。 我怎样才能做到呢?


当前回答

class MyLocation {
    Timer timer1;
    LocationManager lm;
    LocationResult locationResult;
    boolean gps_enabled = false;
    boolean network_enabled = false;

    public boolean getLocation(Context context, LocationResult result) {
        // I use LocationResult callback class to pass location value from
        // MyLocation to user code.
        locationResult = result;
        if (lm == null)
            lm = (LocationManager) context
                    .getSystemService(Context.LOCATION_SERVICE);

        // Exceptions will be thrown if the provider is not permitted.
        try {
            gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
        }
        catch (Exception ex) {
        }
        try {
            network_enabled = lm
                    .isProviderEnabled(LocationManager.NETWORK_PROVIDER);
        }
        catch (Exception ex) {
        }

        // Don't start listeners if no provider is enabled.
        if (!gps_enabled && !network_enabled)
            return false;

        if (gps_enabled)
            lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0,
                    locationListenerGps);
        if (network_enabled)
            lm.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0,
                    locationListenerNetwork);
        timer1 = new Timer();
        timer1.schedule(new GetLastLocation(), 5000);
        return true;
    }

    LocationListener locationListenerGps = new LocationListener() {
        public void onLocationChanged(Location location) {
            timer1.cancel();
            locationResult.gotLocation(location);
            lm.removeUpdates(this);
            lm.removeUpdates(locationListenerNetwork);
        }

        public void onProviderDisabled(String provider) {
        }

        public void onProviderEnabled(String provider) {
        }

        public void onStatusChanged(String provider, int status, Bundle extras) {
        }
    };

    LocationListener locationListenerNetwork = new LocationListener() {
        public void onLocationChanged(Location location) {
            timer1.cancel();
            locationResult.gotLocation(location);
            lm.removeUpdates(this);
            lm.removeUpdates(locationListenerGps);
        }

        public void onProviderDisabled(String provider) {
        }

        public void onProviderEnabled(String provider) {
        }

        public void onStatusChanged(String provider, int status, Bundle extras) {
        }
    };

    class GetLastLocation extends TimerTask {
        @Override
        public void run() {
            lm.removeUpdates(locationListenerGps);
            lm.removeUpdates(locationListenerNetwork);

            Location net_loc = null, gps_loc = null;
            if (gps_enabled)
                gps_loc = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
            if (network_enabled)
                net_loc = lm
                        .getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

            // If there are both values, use the latest one.
            if (gps_loc != null && net_loc != null) {
                if (gps_loc.getTime() > net_loc.getTime())
                    locationResult.gotLocation(gps_loc);
                else
                    locationResult.gotLocation(net_loc);
                return;
            }

            if (gps_loc != null) {
                locationResult.gotLocation(gps_loc);
                return;
            }
            if (net_loc != null) {
                locationResult.gotLocation(net_loc);
                return;
            }
            locationResult.gotLocation(null);
        }
    }

    public static abstract class LocationResult {
        public abstract void gotLocation(Location location);
    }
}

我希望这对你有所帮助……

其他回答

对于位置检查,您可以使用以下代码。你可以把它放在你的onStart()的主活动和显示警报对话框,如果返回为false。

private boolean isLocationAccurate()
    {
        if (Build.VERSION.SDK_INT < Build.VERSION_CODES.KITKAT)
        {
            String provider = Settings.Secure
                    .getString(getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
            if (provider != null && !provider.contains("gps"))
            {
                return false;
            }
        }
        else
        {
            try
            {
                int status = Settings.Secure
                        .getInt(this.getContentResolver(), Settings.Secure.LOCATION_MODE);
                if (status != Settings.Secure.LOCATION_MODE_HIGH_ACCURACY)
                {
                    return false;
                }
            }
            catch (Settings.SettingNotFoundException e)
            {
                Log.e(TAG, e.getMessage());
            }
        }

        return true;
    }

你需要使用latest/最新的

GoogleApiClient Api

基本上你需要做的是:

private GoogleApiClient mGoogleApiClient;
mGoogleApiClient = new GoogleApiClient.Builder(this)
                .addApi(LocationServices.API)
                .addConnectionCallbacks(this)
                .addOnConnectionFailedListener(this)
                .build();

然后

@Override
    public void onConnected(Bundle connectionHint) {
        mLastLocation = LocationServices.FusedLocationApi.getLastLocation(
                mGoogleApiClient);
        if (mLastLocation != null) {
            mLatitudeText.setText(String.valueOf(mLastLocation.getLatitude()));
            mLongitudeText.setText(String.valueOf(mLastLocation.getLongitude()));
        }
    }

为最准确可靠的定位。请看我的帖子:

https://stackoverflow.com/a/33599228/2644905

不要使用LocationListener,它是不准确的,有延迟响应。老实说,这更容易实现。 请阅读文档:https://developers.google.com/android/reference/com/google/android/gms/common/api/GoogleApiClient

我已经得到非常准确的位置使用FusedLocationProviderClient (谷歌播放服务要求)

权限要求

android.permission.ACCESS_FINE_LOCATION

android.permission.ACCESS_COARSE_LOCATION

依赖

“com.google.android.gms: play-services-location: 15.0.0”

芬兰湾的科特林代码

val client = FusedLocationProviderClient(this)
val location = client.lastLocation
location.addOnCompleteListener {
    // this is a lambda expression and we get an 'it' iterator to access the 'result'
    // it.result.latitude gives the latitude
    // it.result.longitude gives the longitude 
    val geocoder = Geocoder(applicationContext, Locale.getDefault())
    val address = geocoder.getFromLocation(it.result.latitude, it.result.longitude, 1)
    if (address != null && address.size > 0) {
        // Get the current city
        city = address[0].locality
    }
}
location.addOnFailureListener {
    // Some error in getting the location, let's log it
    Log.d("xtraces", it.message)
}

LocationManager是一个类,它提供内置方法来获取最后知道的位置

步骤1:如下所示创建LocationManager对象

导航(导航);

步骤2:添加标准

*Criteria is use for setting accuracy*

Criteria criteria = new Criteria();
int currentapiVersion = android.os.Build.VERSION.SDK_INT;

if (currentapiVersion >= android.os.Build.VERSION_CODES.HONEYCOMB) {

    criteria.setSpeedAccuracy(Criteria.ACCURACY_HIGH);
    criteria.setAccuracy(Criteria.ACCURACY_FINE);
    criteria.setAltitudeRequired(true);
    criteria.setBearingRequired(true);
    criteria.setSpeedRequired(true);

}

步骤3:获取可用的提供商

有两种类型的供应商GPS和网络

 String provider = locationManager.getBestProvider(criteria, true);

第四步:了解最后知道的地点

Location location = locationManager.getLastKnownLocation(provider);

第五步:获取经纬度

如果location对象为空,那么不要尝试调用下面的方法

getLatitude和getLongitude是返回双值的方法

我已经发布了一个小的库,可以很容易地在Android中获取位置数据,它甚至照顾到Android M运行时权限。

您可以在这里查看它:https://github.com/julioromano/RxLocation并使用它或其源代码作为实现的示例。