如何循环遍历JavaScript对象中的所有成员,包括作为对象的值?

例如,我如何循环(分别访问“your_name”和“your_message”)?

var validation_messages = {
    "key_1": {
        "your_name": "jimmy",
        "your_msg": "hello world"
    },
    "key_2": {
        "your_name": "billy",
        "your_msg": "foo equals bar"
    }
}

当前回答

每个2

(在此处找到):

var lunch = {
    sandwich: 'ham',
    age: 48,
};
lunch.forEach2(function (item, key) {
    console.log(key);
    console.log(item);
});

代码:

if (!Object.prototype.forEach2) {
    Object.defineProperty(Object.prototype, 'forEach2', {
        value: function (callback, thisArg) {
            if (this == null) {
                throw new TypeError('Not an object');
            }
            thisArg = thisArg || window;
            for (var key in this) {
                if (this.hasOwnProperty(key)) {
                    callback.call(thisArg, this[key], key, this);
                }
            }
        }
    });
}

其他回答

变量obj={name:“SanD”,年龄:“27”}Object.keys(obj).forEach((key)=>console.log(key,obj[key]));

为了循环遍历JavaScript对象,我们可以使用forEach,为了优化代码,可以使用箭头函数。

如果使用递归,则可以返回任意深度的对象财产-

function lookdeep(object){
    var collection= [], index= 0, next, item;
    for(item in object){
        if(object.hasOwnProperty(item)){
            next= object[item];
            if(typeof next== 'object' && next!= null){
                collection[index++]= item +
                ':{ '+ lookdeep(next).join(', ')+'}';
            }
            else collection[index++]= [item+':'+String(next)];
        }
    }
    return collection;
}

//example

var O={
    a:1, b:2, c:{
        c1:3, c2:4, c3:{
            t:true, f:false
        }
    },
    d:11
};
var lookdeepSample= 'O={'+ lookdeep(O).join(',\n')+'}';


/*  returned value: (String)
O={
    a:1, 
    b:2, 
    c:{
        c1:3, c2:4, c3:{
            t:true, f:false
        }
    },
    d:11
}

*/
var validation_messages = {
    "key_1": {
        "your_name": "jimmy",
        "your_msg": "hello world"
    },
    "key_2": {
        "your_name": "billy",
        "your_msg": "foo equals bar"
    }
}
for (var i in validation_messages) {
    console.log("i = \"" + i + "\"");
    console.log("validation_messages[\"" + i + "\"] = ");
    console.log(validation_messages[i]);
    console.log("\n");
    for (var j in validation_messages[i]) {
        console.log("j = \"" + j + "\"");
        console.log("validation_messages[\"" + i + "\"][\"" + j + "\"] = \"" + validation_messages[i][j] + "\"");
        console.log("\n");
    }
    console.log('\n');
}

输出:

i = "key_1"
validation_messages["key_1"] = 
{
  your_name:"jimmy",
  your_msg:"hello world"
}

j = "your_name"
validation_messages["key_1"]["your_name"] = "jimmy"

j = "your_msg"
validation_messages["key_1"]["your_msg"] = "hello world"


i = "key_2"
validation_messages["key_2"] = 
{
  your_name:"billy",
  your_msg:"foo equals bar"
}

j = "your_name"
validation_messages["key_2"]["your_name"] = "billy"

j = "your_msg"
validation_messages["key_2"]["your_msg"] = "foo equals bar"
for(var key in validation_messages){
    for(var subkey in validation_messages[key]){
        //code here
        //subkey being value, key being 'yourname' / 'yourmsg'
    }
}

在ECMAScript 5下,可以组合Object.keys()和Array.protocol.forEach():

变量obj={第一个:“约翰”,上一个:“Doe”};////访问非继承的可枚举密钥//Object.keys(obj).forEach(函数(键){console.log(key,obj[key]);});