我有一个这样的数组:
var arr1 = ["a", "b", "c", "d"];
我如何随机化/打乱它?
我有一个这样的数组:
var arr1 = ["a", "b", "c", "d"];
我如何随机化/打乱它?
当前回答
对CoolAJ86答案的简单修改,不修改原始数组:
/**
* Returns a new array whose contents are a shuffled copy of the original array.
* @param {Array} The items to shuffle.
* https://stackoverflow.com/a/2450976/1673761
* https://stackoverflow.com/a/44071316/1673761
*/
const shuffle = (array) => {
let currentIndex = array.length;
let temporaryValue;
let randomIndex;
const newArray = array.slice();
// While there remains elements to shuffle...
while (currentIndex) {
randomIndex = Math.floor(Math.random() * currentIndex);
currentIndex -= 1;
// Swap it with the current element.
temporaryValue = newArray[currentIndex];
newArray[currentIndex] = newArray[randomIndex];
newArray[randomIndex] = temporaryValue;
}
return newArray;
};
其他回答
//doesn change array
Array.prototype.shuffle = function () {
let res = [];
let copy = [...this];
while (copy.length > 0) {
let index = Math.floor(Math.random() * copy.length);
res.push(copy[index]);
copy.splice(index, 1);
}
return res;
};
let a=[1, 2, 3, 4, 5, 6, 7, 8, 9];
console.log(a.shuffle());
递归解决方案:
function shuffle(a,b){
return a.length==0?b:function(c){
return shuffle(a,(b||[]).concat(c));
}(a.splice(Math.floor(Math.random()*a.length),1));
};
罗纳德·费舍尔和弗兰克·耶茨洗牌
ES2015(ES6)版本
Array.prototype.shuffle2 = function () {
this.forEach(
function (v, i, a) {
let j = Math.floor(Math.random() * (i + 1));
[a[i], a[j]] = [a[j], a[i]];
}
);
return this;
}
Jet优化ES2015(ES6)版本
Array.prototype.shuffle3 = function () {
var m = this.length;
while (m) {
let i = Math.floor(Math.random() * m--);
[this[m], this[i]] = [this[i], this[m]];
}
return this;
}
var shuffle = function(array) {
temp = [];
originalLength = array.length;
for (var i = 0; i < originalLength; i++) {
temp.push(array.splice(Math.floor(Math.random()*array.length),1));
}
return temp;
};
Fisher Yates的这种变体稍微更有效,因为它避免了元素与自身的交换:
function shuffle(array) {
var elementsRemaining = array.length, temp, randomIndex;
while (elementsRemaining > 1) {
randomIndex = Math.floor(Math.random() * elementsRemaining--);
if (randomIndex != elementsRemaining) {
temp = array[elementsRemaining];
array[elementsRemaining] = array[randomIndex];
array[randomIndex] = temp;
}
}
return array;
}