如何使用PHP5类创建单例类?
当前回答
我同意第一个答案,但我也会将类声明为final,这样它就不能被扩展,因为扩展单例违背了单例模式。此外,实例变量应该是私有的,这样就不能直接访问它。还要将__clone方法设为私有,这样就不能克隆单例对象。
下面是一些示例代码。
/**
* Singleton class
*
*/
final class UserFactory
{
private static $_instance = null;
/**
* Private constructor
*
*/
private function __construct() {}
/**
* Private clone method
*
*/
private function __clone() {}
/**
* Call this method to get singleton
*
* @return UserFactory
*/
public static function getInstance()
{
if (self::$_instance === null) {
self::$_instance = new UserFactory();
}
return self::$_instance;
}
}
示例使用
$user_factory = UserFactory::getInstance();
这阻止你做什么(这将违反单例模式..
你不能这么做!
$user_factory = UserFactory::$_instance;
class SecondUserFactory extends UserFactory { }
其他回答
数据库类,检查是否有任何现有的数据库实例,它将返回先前的实例。
class Database {
public static $instance;
public static function getInstance(){
if(!isset(Database::$instance) ) {
Database::$instance = new Database();
}
return Database::$instance;
}
private function __cunstruct() {
/* private and cant create multiple objects */
}
public function getQuery(){
return "Test Query Data";
}
}
$dbObj = Database::getInstance();
$dbObj2 = Database::getInstance();
var_dump($dbObj);
var_dump($dbObj2);
/*
After execution you will get following output:
object(Database)[1]
object(Database)[1]
*/
Ref http://www.phptechi.com/php-singleton-design-patterns-example.html
PHP 5.3允许通过后期静态绑定创建可继承的单例类:
class Singleton
{
protected static $instance = null;
protected function __construct()
{
//Thou shalt not construct that which is unconstructable!
}
protected function __clone()
{
//Me not like clones! Me smash clones!
}
public static function getInstance()
{
if (!isset(static::$instance)) {
static::$instance = new static;
}
return static::$instance;
}
}
这解决了一个问题,在PHP 5.3之前,任何扩展了Singleton的类都会生成父类的实例,而不是它自己的实例。
现在你可以做:
class Foobar extends Singleton {};
$foo = Foobar::getInstance();
$foo将是Foobar的一个实例而不是Singleton的一个实例。
简单的例子:
final class Singleton
{
private static $instance = null;
private function __construct(){}
private function __clone(){}
private function __wakeup(){}
public static function get_instance()
{
if ( static::$instance === null ) {
static::$instance = new static();
}
return static::$instance;
}
}
希望有帮助。
以上答案都是可以的,但我还会再补充一些。
无论谁在2021年来到这里,我都将展示另一个使用单例模式类作为trait的例子,并在任何类中重用它。
<?php
namespace Akash;
trait Singleton
{
/**
* Singleton Instance
*
* @var Singleton
*/
private static $instance;
/**
* Private Constructor
*
* We can't use the constructor to create an instance of the class
*
* @return void
*/
private function __construct()
{
// Don't do anything, we don't want to be initialized
}
/**
* Get the singleton instance
*
* @return Singleton
*/
public static function getInstance()
{
if (!isset(self::$instance)) {
self::$instance = new self();
}
return self::$instance;
}
/**
* Private clone method to prevent cloning of the instance of the
* Singleton instance.
*
* @return void
*/
private function __clone()
{
// Don't do anything, we don't want to be cloned
}
/**
* Private unserialize method to prevent unserializing of the Singleton
* instance.
*
* @return void
*/
private function __wakeup()
{
// Don't do anything, we don't want to be unserialized
}
}
所以,像在任何课堂上一样轻松地使用它。假设,我们想在UserSeeder类中实现单例模式。
<?php
class UserSeeder
{
use Singleton;
/**
* Seed Users
*
* @return void
*/
public function seed()
{
echo 'Seeding...';
}
}
不幸的是,当有多个子类时,Inwdr的答案就失效了。
下面是一个正确的可继承单例基类。
class Singleton
{
private static $instances = array();
protected function __construct() {}
protected function __clone() {}
public function __wakeup()
{
throw new Exception("Cannot unserialize singleton");
}
public static function getInstance()
{
$cls = get_called_class(); // late-static-bound class name
if (!isset(self::$instances[$cls])) {
self::$instances[$cls] = new static;
}
return self::$instances[$cls];
}
}
测试代码:
class Foo extends Singleton {}
class Bar extends Singleton {}
echo get_class(Foo::getInstance()) . "\n";
echo get_class(Bar::getInstance()) . "\n";