虽然在Python中没有任何等同于goto/label的代码，但您仍然可以使用循环来获得goto/label的这种功能。

让我们以下面所示的代码示例为例，其中goto/label可以在python以外的任意语言中使用。

String str1 = 'BACK'

label1:
    print('Hello, this program contains goto code\n')
    print('Now type BACK if you want the program to go back to the above line of code. Or press the ENTER key if you want the program to continue with further lines of code')
    str1 = input()

if str1 == 'BACK'
    {
        GoTo label1
    }
print('Program will continue\nBla bla bla...\nBla bla bla...\nBla bla bla...')

现在，通过使用下面所示的while循环，可以在python中实现上述代码示例的相同功能。

str1 = 'BACK'

while str1 == 'BACK':
        print('Hello, this is a python program containing python equivalent code for goto code\n')
        print('Now type BACK if you want the program to go back to the above line of code. Or press the ENTER key if you want the program to continue with further lines of code')
        str1 = input()
print('Program will continue\nBla bla bla...\nBla bla bla...\nBla bla bla...')

不，有另一种方法来实现goto语句

class id:
     def data1(self):
        name=[]
        age=[]   
        n=1
        while n>0:
            print("1. for enter data")
            print("2. update list")
            print("3. show data")
            print("choose what you want to do ?")
            ch=int(input("enter your choice"))
            if ch==1:    
                n=int(input("how many elemet you want to enter="))
                for i in range(n):
                    name.append(input("NAME "))
                    age.append(int(input("age "))) 
            elif ch==2:
                name.append(input("NAME "))
                age.append(int(input("age ")))
            elif ch==3:
                try:
                    if name==None:
                        print("empty list")
                    else:
                        print("name \t age")
                        for i in range(n):
                            print(name[i]," \t ",age[i])
                        break
                except:
                    print("list is empty")
            print("do want to continue y or n")
            ch1=input()
            if ch1=="y":
                n=n+1
            else:
                print("name \t age")
                for i in range(n):
                    print(name[i]," \t ",age[i])
                n=-1
p1=id()
p1.data1()  

一个工作版本已经完成:http://entrian.com/goto/。

注:这是一个愚人节玩笑。(工作)

# Example 1: Breaking out from a deeply nested loop:
from goto import goto, label

for i in range(1, 10):
    for j in range(1, 20):
        for k in range(1, 30):
            print i, j, k
            if k == 3:
                goto .end
label .end
print "Finished\n"

不用说。是的，它很有趣，但不要使用它。

我有自己的做法。 我使用单独的python脚本。

如果我想要循环:

file1.py

print("test test")
execfile("file2.py")
a = a + 1

file2.py

print(a)
if a == 10:
   execfile("file3.py")
else:
   execfile("file1.py")

file3.py

print(a + " equals 10")

(注意:此技术仅适用于Python 2。x版本)

Python 2和3

pip3 install goto-statement

在Python 2.6到3.6和PyPy上测试。

链接:转向语句

foo.py

from goto import with_goto

@with_goto
def bar():

    label .bar_begin

    ...

    goto .bar_begin

使用评论中@bobince的建议来回答@ascobol的问题:

for i in range(5000):
    for j in range(3000):
        if should_terminate_the_loop:
           break
    else: 
        continue # no break encountered
    break

else块的缩进是正确的。代码在循环Python语法后使用模糊的else。参见为什么python在for和while循环之后使用'else' ?