我如何在Python中命名一个外部命令,就好像我把它写在一个<unk>或命令中?
当前回答
还有铅
>>> from plumbum import local
>>> ls = local["ls"]
>>> ls
LocalCommand(<LocalPath /bin/ls>)
>>> ls()
u'build.py\ndist\ndocs\nLICENSE\nplumbum\nREADME.rst\nsetup.py\ntests\ntodo.txt\n'
>>> notepad = local["c:\\windows\\notepad.exe"]
>>> notepad() # Notepad window pops up
u'' # Notepad window is closed by user, command returns
其他回答
使用:
import subprocess
p = subprocess.Popen("df -h", shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE).communicate()[0]
print p.split("\n")
它提供良好的产量,更容易与:
['Filesystem Size Used Avail Use% Mounted on',
'/dev/sda6 32G 21G 11G 67% /',
'none 4.0K 0 4.0K 0% /sys/fs/cgroup',
'udev 1.9G 4.0K 1.9G 1% /dev',
'tmpfs 387M 1.4M 386M 1% /run',
'none 5.0M 0 5.0M 0% /run/lock',
'none 1.9G 58M 1.9G 3% /run/shm',
'none 100M 32K 100M 1% /run/user',
'/dev/sda5 340G 222G 100G 69% /home',
'']
下面是一个Python脚本,它将在Ubuntu上运行命令,同时在实时显示日志:
command = 'your command here'
process = subprocess.Popen(command, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
while True:
output = process.stdout.readline().decode()
if output == '' and process.poll() is not None:
break
if output:
print(output.strip())
rc = process.poll()
if rc == 0:
print("Command succeeded.")
else:
print("Command failed.")
有很多不同的图书馆,允许您使用Python呼叫外部命令. 对于每个图书馆,我给了一个描述,并显示了一个例子呼叫外部命令. 我使用的命令作为例子是ls -l(列出所有文件)。 如果你想了解更多关于任何图书馆,我列出并链接到文件的每一个。
来源
这些都是图书馆
希望这会帮助你做出决定哪个图书馆使用:)
副过程
subprocess.run(["ls", "-l"]) # Run command
subprocess.run(["ls", "-l"], stdout=subprocess.PIPE) # This will run the command and return any output
subprocess.run(shlex.split("ls -l")) # You can also use the shlex library to split the command
os 用于“操作系统依赖功能”。 它也可以用来呼叫与 os.system 和 os.popen 的外部命令(注:也有 subprocess.popen)。 os 总是会运行盾牌,并且对于那些不需要或不知道如何使用 subprocess.run 的人来说是一个简单的替代方案。
os.system("ls -l") # Run command
os.popen("ls -l").read() # This will run the command and return any output
饰 sh
sh 是一个子过程界面,允许您呼叫程序,就好像它们是功能。
sh.ls("-l") # Run command normally
ls_cmd = sh.Command("ls") # Save command as a variable
ls_cmd() # Run command as if it were a function
铅
ls_cmd = plumbum.local("ls -l") # Get command
ls_cmd() # Run command
佩克斯
pexpect.run("ls -l") # Run command as normal
child = pexpect.spawn('scp foo user@example.com:.') # Spawns child application
child.expect('Password:') # When this is the output
child.sendline('mypassword')
织物
fabric.operations.local('ls -l') # Run command as normal
fabric.operations.local('ls -l', capture = True) # Run command and receive output
发送
r = envoy.run("ls -l") # Run command
r.std_out # Get output
命令
这里有很多答案,但没有一个满足了我所有的需求。
我需要运行命令并捕获输出和输出代码. 我需要时间out 执行的程序,并强迫它出去,如果时间out 达到,并杀死它的所有儿童过程. 我需要它在 Windows XP 和以后, Cygwin 和 Linux 工作。
def _run(command, timeout_s=False, shell=False):
### run a process, capture the output and wait for it to finish. if timeout is specified then Kill the subprocess and its children when the timeout is reached (if parent did not detach)
## usage: _run(arg1, arg2, arg3)
# arg1: command + arguments. Always pass a string; the function will split it when needed
# arg2: (optional) timeout in seconds before force killing
# arg3: (optional) shell usage. default shell=False
## return: a list containing: exit code, output, and if timeout was reached or not
# - Tested on Python 2 and 3 on Windows XP, Windows 7, Cygwin and Linux.
# - preexec_fn=os.setsid (py2) is equivalent to start_new_session (py3) (works on Linux only), in Windows and Cygwin we use TASKKILL
# - we use stderr=subprocess.STDOUT to merge standard error and standard output
import sys, subprocess, os, signal, shlex, time
def _runPY3(command, timeout_s=None, shell=False):
# py3.3+ because: timeout was added to communicate() in py3.3.
new_session=False
if sys.platform.startswith('linux'): new_session=True
p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT, start_new_session=new_session, shell=shell)
try:
out = p.communicate(timeout=timeout_s)[0].decode('utf-8')
is_timeout_reached = False
except subprocess.TimeoutExpired:
print('Timeout reached: Killing the whole process group...')
killAll(p.pid)
out = p.communicate()[0].decode('utf-8')
is_timeout_reached = True
return p.returncode, out, is_timeout_reached
def _runPY2(command, timeout_s=0, shell=False):
preexec=None
if sys.platform.startswith('linux'): preexec=os.setsid
p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT, preexec_fn=preexec, shell=shell)
start_time = time.time()
is_timeout_reached = False
while timeout_s and p.poll() == None:
if time.time()-start_time >= timeout_s:
print('Timeout reached: Killing the whole process group...')
killAll(p.pid)
is_timeout_reached = True
break
time.sleep(1)
out = p.communicate()[0].decode('utf-8')
return p.returncode, out, is_timeout_reached
def killAll(ParentPid):
if sys.platform.startswith('linux'):
os.killpg(os.getpgid(ParentPid), signal.SIGTERM)
elif sys.platform.startswith('cygwin'):
# subprocess.Popen(shlex.split('bash -c "TASKKILL /F /PID $(</proc/{pid}/winpid) /T"'.format(pid=ParentPid)))
winpid=int(open("/proc/{pid}/winpid".format(pid=ParentPid)).read())
subprocess.Popen(['TASKKILL', '/F', '/PID', str(winpid), '/T'])
elif sys.platform.startswith('win32'):
subprocess.Popen(['TASKKILL', '/F', '/PID', str(ParentPid), '/T'])
# - In Windows, we never need to split the command, but in Cygwin and Linux we need to split if shell=False (default), shlex will split the command for us
if shell==False and (sys.platform.startswith('cygwin') or sys.platform.startswith('linux')):
command=shlex.split(command)
if sys.version_info >= (3, 3): # py3.3+
if timeout_s==False:
returnCode, output, is_timeout_reached = _runPY3(command, timeout_s=None, shell=shell)
else:
returnCode, output, is_timeout_reached = _runPY3(command, timeout_s=timeout_s, shell=shell)
else: # Python 2 and up to 3.2
if timeout_s==False:
returnCode, output, is_timeout_reached = _runPY2(command, timeout_s=0, shell=shell)
else:
returnCode, output, is_timeout_reached = _runPY2(command, timeout_s=timeout_s, shell=shell)
return returnCode, output, is_timeout_reached
然后用它如下:
总是将命令作为一个行(它更容易)。你不需要分开它;函数在需要时将分开它。
所以我们可以用这个类似的时间:
a=_run('cmd /c echo 11111 & echo 22222 & calc',3)
for i in a[1].splitlines(): print(i)
或者没有时间:
b=_run('cmd /c echo 11111 & echo 22222 & calc')
更多例子:
b=_run('''wmic nic where 'NetConnectionID="Local Area Connection"' get NetConnectionStatus /value''')
print(b)
c=_run('cmd /C netsh interface ip show address "Local Area Connection"')
print(c)
d=_run('printf "<%s>\n" "{foo}"')
print(d)
你也可以指定Shell=True,但在大多数情况下,这个功能是无用的。我宁愿自己选择我想要的Shell,但这里是,如果你也需要它:
# windows
e=_run('echo 11111 & echo 22222 & calc',3, shell=True)
print(e)
# Cygwin/Linux:
f=_run('printf "<%s>\n" "{foo}"', shell=True)
print(f)
為什麼我沒有使用更簡單的新方法 subprocess.run()?
因为它支持在Python 3.7+,但最后支持的Python版本在Windows XP是3.4. 而且由于这个功能的Timeout论点在Windows中是无用的,它不会杀死执行命令的儿童过程. 如果你使用 capture_output + Timeout论点,它会挂在如果有一个儿童过程仍然运行。
import subprocess
p = subprocess.run(["ls", "-ltr"], capture_output=True)
print(p.stdout.decode(), p.stderr.decode())
网上尝试
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