在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
更可取的解决方案是,
onclick(){
btn.setEnabled(false);
btn.setClickable(false);
//yourwork
myWork();
}
myWork(){
//your tasks.
btn.setEnabled(true);
btn.setClickable(true);
}
由于一个环节很容易被忽略,我不得不一遍又一遍地重复这个环节
其他回答
I found none of these suggestions works if the onClick method doesn't return immediately. The touch event is queued by Android and the next onClick is called only after the first one is finished. (Since this is done on the one UI thread this is really normal.) I needed to use the time when the the onClick function is finished + one boolean variable to mark whether the given onClick is running. Both these marker attributes are static to avoid any onClickListener to run at the same time. (If user clicks on another button) You can simple replace your OnClickListener to this class and instead of implementing the onClick method you need to implement the abstract oneClick() method.
abstract public class OneClickListener implements OnClickListener {
private static boolean started = false;
private static long lastClickEndTime = 0;
/* (non-Javadoc)
* @see android.view.View.OnClickListener#onClick(android.view.View)
*/
@Override
final public void onClick(final View v) {
if(started || SystemClock.elapsedRealtime()-lastClickEndTime <1000 ){
Log.d(OneClickListener.class.toString(), "Rejected double click, " + new Date().toString() );
return;
}
Log.d(OneClickListener.class.toString(), "One click, start: " + new Date().toString() );
try{
started = true;
oneClick(v);
}finally{
started = false;
lastClickEndTime = SystemClock.elapsedRealtime();
Log.d(OneClickListener.class.toString(), "One click, end: " + new Date().toString() );
}
}
abstract protected void oneClick(View v);
}
你可以使用这种方法。通过使用后延迟,你可以照顾双击事件。
void debounceEffectForClick(查看视图){
view.setClickable(false);
view.postDelayed(new Runnable() {
@Override
public void run() {
view.setClickable(true);
}
}, 500);
}
你可以用Kotlin扩展函数和RxBinding来实现它
fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit): Disposable =
RxView.clicks(this)
.debounce(debounceTime, TimeUnit.MILLISECONDS)
.observeOn(AndroidSchedulers.mainThread())
.subscribe { action() }
or
fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit) {
this.setOnClickListener(object : View.OnClickListener {
private var lastClickTime: Long = 0
override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - lastClickTime < debounceTime) return
else action()
lastClickTime = SystemClock.elapsedRealtime()
}
})
}
然后就是:
View.clickWithDebounce{ Your code }
The Best and simple solution i found is
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;
/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}
使用setEnabled(false)禁用按钮,直到用户可以安全地再次单击它。
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