The Best and simple solution i found is 
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;

/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check 
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}

Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).

我也遇到了类似的问题，我正在显示一些日期选择器和时间选择器，有时它会被点击2次。我用这个方法解决了这个问题:

long TIME = 1 * 1000;
@Override
public void onClick(final View v) {
v.setEnabled(false);
    
    new Handler().postDelayed(new Runnable() {

        @Override
        public void run() {
            v.setEnabled(true);
        }
    }, TIME);
}

你可以根据自己的需要改变时间。

我的解决方案是尝试使用一个布尔变量:

public class Blocker {
    private static final int DEFAULT_BLOCK_TIME = 1000;
    private boolean mIsBlockClick;

    /**
     * Block any event occurs in 1000 millisecond to prevent spam action
     * @return false if not in block state, otherwise return true.
     */
    public boolean block(int blockInMillis) {
        if (!mIsBlockClick) {
            mIsBlockClick = true;
            new Handler().postDelayed(new Runnable() {
                @Override
                public void run() {
                    mIsBlockClick = false;
                }
            }, blockInMillis);
            return false;
        }
        return true;
    }

    public boolean block() {
        return block(DEFAULT_BLOCK_TIME);
    }
}

并使用如下:

view.setOnClickListener(new View.OnClickListener() {
            private Blocker mBlocker = new Blocker();

            @Override
            public void onClick(View v) {
                if (!mBlocker.block(block-Time-In-Millis)) {
                    // do your action   
                }
            }
        });

更新:Kotlin解决方案，使用视图扩展

fun View.safeClick(listener: View.OnClickListener, blockInMillis: Long = 500) {
    var lastClickTime: Long = 0
    this.setOnClickListener {
        if (SystemClock.elapsedRealtime() - lastClickTime < blockInMillis) return@setOnClickListener
        lastClickTime = SystemClock.elapsedRealtime()
        listener.onClick(this)
    }
}

我知道这是一个老问题，但我分享了我找到的解决这个常见问题的最佳方案

        btnSomeButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            // Prevent Two Click
            Utils.preventTwoClick(view);
            // Do magic
        }
    });

在另一个文件中，比如Utils.java

    /**
 * Método para prevenir doble click en un elemento
 * @param view
 */
public static void preventTwoClick(final View view){
    view.setEnabled(false);
    view.postDelayed(
        ()-> view.setEnabled(true),
        500
    );
}

通用解决方案

@Override
        public void onClick(View v) {
            tempDisableButton(v);
            //all the buttons view..
        }

public void tempDisableButton(View viewBtn) {
        final View button = viewBtn;

        button.setEnabled(false);
        button.postDelayed(new Runnable() {
            @Override
            public void run() {
                button.setEnabled(true);
            }
        }, 3000);
    }