在Java中有一个本地debounce click监听器

view.setOnClickListener(new DebouncedOnClickListener(1000) { //in milisecs
            @Override
            public void onDebouncedClick(View v) {
                //action
            }
        });

Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).

我希望这能帮助你，把代码放在你的事件处理程序。

// --------------------------------------------------------------------------------

    boolean hasTag = null != which.getTag( R.id.preventing_double_click_tag );

    if ( hasTag ) {
        // Do not handle again...
        return;
    } else {
        which.setTag( R.id.action, Boolean.TRUE );

        which.postDelayed( new Runnable() {
            @Override
            public void run() {
                which.setTag( R.id.action, null );
                Log.d( "onActin", " The preventing double click tag was removed." );
            }

        }, 2000 );
    }

加上Jim的回答，代码可以变得更简洁:

fun View.setOnSingleClick(onClick: () -> Unit) {
    var lastClickTime = 0L
    setOnClickListener {
        if (currentTimeMillis() > lastClickTime + 750) onClick()
        lastClickTime = currentTimeMillis()
    } 
}

用法:

aView.setOnSingleClick {  }

这个问题的实际解决方案是使用setEnabled(false)，灰色按钮，和setClickable(false)，使它第二次点击不能接收，我已经测试过了，它似乎是非常有效的。

点击保护工作与黄油刀

ClickGuard.guard(mPlayButton);