在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
防止点击乘法btns
使用:
private val disposables = CompositeDisposable()
private val clickInteractor = ClickInteractor(disposables)
...
button1.setOnClickListener{
clickInteractor.click {
Toast.makeText(context, "Btn1", Toast.LENGTH_LONG).show()
}
}
button2.setOnClickListener{
clickInteractor.click {
Toast.makeText(context, "Btn2", Toast.LENGTH_LONG).show()
}
}
ClickInteractor.kt:
class ClickInteractor constructor(disposables: CompositeDisposable) {
private val performPublish = PublishSubject.create<ClickInteractorCallback>()
init {
performPublish
.subscribeOn(Schedulers.io())
.observeOn(Schedulers.io())
.throttleFirst(1, TimeUnit.SECONDS, Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doOnNext { callback ->
callback.invoke()
}
.retry()
.execute(disposables)
}
fun click(callback: ClickInteractorCallback) {
performPublish.onNext(callback)
}
}
typealias ClickInteractorCallback = () -> Unit
其他回答
我们可以像这样使用按钮进行同步:
示例#1 (Java)
@Override
public void onClick(final View view) {
synchronized (view) {
view.setEnabled(false);
switch (view.getId()) {
case R.id.id1:
...
break;
case R.id.id2:
...
break;
...
}
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
view.setEnabled(true);
}
}, 1000);
}
}
示例#2 (kotlin)使用synchronized
myButton.setOnClickListener { view ->
synchronized(view) {
view.isEnabled = false
// do something
view.postDelayed({ view.isEnabled = true }, 500L)
}
}
祝你好运)
我的解决方案(Kotlin):
class OnDebouncedClickListener(private val delayInMilliSeconds: Long, val action: () -> Unit) : View.OnClickListener {
var enable = true
override fun onClick(view: View?) {
if (enable) {
enable = false
view?.postDelayed(delayInMilliSeconds) { enable = true }
action()
}
}
}
fun View.setOnDebouncedClickListener(delayInMilliSeconds: Long = 500, action: () -> Unit) {
val onDebouncedClickListener = OnDebouncedClickListener(delayInMilliSeconds, action)
setOnClickListener(onDebouncedClickListener)
}
使用:
button.apply {
setOnDebouncedClickListener {
//your action on click
}
}
试试这个,它是有效的:
mButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
mSlotLayout.setEnabled(false);
// do your work here
Timer buttonTimer = new Timer();
buttonTimer.schedule(new TimerTask() {
@Override
public void run() {
runOnUiThread(new Runnable() {
@Override
public void run() {
mButton.setEnabled(true);
}
});
}
}, 500); // delay button enable for 0.5 sec
}
});
你可以使用这种方法。通过使用后延迟,你可以照顾双击事件。
void debounceEffectForClick(查看视图){
view.setClickable(false);
view.postDelayed(new Runnable() {
@Override
public void run() {
view.setClickable(true);
}
}, 500);
}
Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).
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