严格相等运算符将告诉您两个对象类型是否相等。然而,是否有一种方法来判断两个对象是否相等,就像Java中的哈希码值一样?

堆栈溢出问题JavaScript中有hashCode函数吗?类似于这个问题,但需要一个更学术的答案。上面的场景说明了为什么有必要有一个,我想知道是否有等效的解决方案。


当前回答

我看到了意大利式的代码答案。 不使用任何第三方的lib,这是非常容易的。

首先,按键对两个对象进行排序。

let objectOne = { hey, you }
let objectTwo = { you, hey }

// If you really wanted you could make this recursive for deep sort.
const sortObjectByKeyname = (objectToSort) => {
    return Object.keys(objectToSort).sort().reduce((r, k) => (r[k] = objectToSort[k], r), {});
}

let objectOne = sortObjectByKeyname(objectOne)
let objectTwo = sortObjectByKeyname(objectTwo)

然后简单地使用字符串来比较它们。

JSON.stringify(objectOne) === JSON.stringify(objectTwo)

其他回答

let user1 = { name: "John", address: { line1: "55 Green Park Road", line2: { a:[1,2,3] } }, email:null } let user2 = { name: "John", address: { line1: "55 Green Park Road", line2: { a:[1,2,3] } }, email:null } // Method 1 function isEqual(a, b) { return JSON.stringify(a) === JSON.stringify(b); } // Method 2 function isEqual(a, b) { // checking type of a And b if(typeof a !== 'object' || typeof b !== 'object') { return false; } // Both are NULL if(!a && !b ) { return true; } else if(!a || !b) { return false; } let keysA = Object.keys(a); let keysB = Object.keys(b); if(keysA.length !== keysB.length) { return false; } for(let key in a) { if(!(key in b)) { return false; } if(typeof a[key] === 'object') { if(!isEqual(a[key], b[key])) { return false; } } else { if(a[key] !== b[key]) { return false; } } } return true; } console.log(isEqual(user1,user2));

当然,当我们在它的时候,我会抛出我自己对车轮的重新发明(我为辐条和使用的材料的数量感到自豪):

////////////////////////////////////////////////////////////////////////////////

var equals = function ( objectA, objectB ) {
    var result = false,
        keysA,
        keysB;

    // Check if they are pointing at the same variable. If they are, no need to test further.
    if ( objectA === objectB ) {
        return true;
    }

    // Check if they are the same type. If they are not, no need to test further.
    if ( typeof objectA !== typeof objectB ) {
        return false;
    }

    // Check what kind of variables they are to see what sort of comparison we should make.
    if ( typeof objectA === "object" ) {
        // Check if they have the same constructor, so that we are comparing apples with apples.
        if ( objectA.constructor === objectA.constructor ) {
            // If we are working with Arrays...
            if ( objectA instanceof Array ) {
                // Check the arrays are the same length. If not, they cannot be the same.
                if ( objectA.length === objectB.length ) {
                    // Compare each element. They must be identical. If not, the comparison stops immediately and returns false.
                    return objectA.every(
                        function ( element, i ) {
                            return equals( element, objectB[ i ] );
                        }
                    );
                }
                // They are not the same length, and so are not identical.
                else {
                    return false;
                }
            }
            // If we are working with RegExps...
            else if ( objectA instanceof RegExp ) {
                // Return the results of a string comparison of the expression.
                return ( objectA.toString() === objectB.toString() );
            }
            // Else we are working with other types of objects...
            else {
                // Get the keys as arrays from both objects. This uses Object.keys, so no old browsers here.
                keysA = Object.keys( objectA );

                keysB = Object.keys( objectB );

                // Check the key arrays are the same length. If not, they cannot be the same.
                if ( keysA.length === keysB.length ) {
                    // Compare each property. They must be identical. If not, the comparison stops immediately and returns false.
                    return keysA.every(
                        function ( element ) {
                            return equals( objectA[ element ], objectB[ element ] );
                        }
                    );
                }
                // They do not have the same number of keys, and so are not identical.
                else {
                    return false;
                }
            }
        }
        // They don't have the same constructor.
        else {
            return false;
        }
    }
    // If they are both functions, let us do a string comparison.
    else if ( typeof objectA === "function" ) {
        return ( objectA.toString() === objectB.toString() );
    }
    // If a simple variable type, compare directly without coercion.
    else {
        return ( objectA === objectB );
    }

    // Return a default if nothing has already been returned.
    return result;
};

////////////////////////////////////////////////////////////////////////////////

它会尽可能快地返回false,但当然,对于一个差异嵌套很深的大对象,它可能不那么有效。在我自己的场景中,良好地处理嵌套数组非常重要。

希望它能帮助需要这种“轮子”的人。

如果你在AngularJS中工作,angular。Equals函数将确定两个对象是否相等。在Ember.js中使用isEqual。

角。equals -关于这个方法的更多信息,请参阅文档或源代码。它还对数组进行了深度比较。 js isEqual -关于这个方法的更多信息,请参阅文档或源代码。它不会对数组进行深度比较。

Var紫色=[{"紫色":"喝了"}]; Var drinking =[{"紫色":"喝了"}]; 如果(角。等于(紫色,喝)){ 文档。写(有dat); } < script src = " https://ajax.googleapis.com/ajax/libs/angularjs/1.4.5/angular.min.js " > < /脚本>

我写了一个运行在Node.js和浏览器上的小库,叫做compare.js。它提供了常见的比较运算符,例如==,!=,>,>=,<,<=和所有JavaScript数据类型的标识符。

例如,你可以用

cmp.eq(obj1, obj2);

这将检查是否相等(使用深度相等的方法)。否则,如果你这样做

cmp.id(obj1, obj2);

它将通过引用进行比较,从而检查标识。 您还可以在对象上使用<和>,它们表示子集和超集。

Compare.js被近700个单元测试覆盖,因此它应该不会有太多的bug;-)。

你可以在https://github.com/goloroden/compare.js上免费找到它,它是MIT许可下的开源软件。

我已经实现了一个方法,它接受两个json,并使用递归检查它们的键是否具有相同的值。 我用另一个问题来解决这个问题。

const arraysEqual = (a, b) => { if (a === b) return true; if (a === null || b === null) return false; if (a.length !== b.length) return false; // If you don't care about the order of the elements inside // the array, you should sort both arrays here. for (let i = 0; i < a.length; ++i) { if (a[i] !== b[i]) return false; } return true; }; const jsonsEqual = (a, b) => { if(typeof a !== 'object' || typeof b !== 'object') return false; if (Object.keys(a).length === Object.keys(b).length) { // if items have the same size let response = true; for (let key in a) { if (!b[key]) // if not key response = false; if (typeof a[key] !== typeof b[key]) // if typeof doesn't equals response = false; else { if (Array.isArray(a[key])) // if array response = arraysEqual(a[key], b[key]); else if (typeof a[key] === 'object') // if another json response = jsonsEqual(a[key], b[key]); else if (a[key] !== b[key]) // not equals response = false; } if (!response) // return if one item isn't equal return false; } } else return false; return true; }; const json1 = { a: 'a', b: 'asd', c: [ '1', 2, 2.5, '3', { d: 'asd', e: [ 1.6, { f: 'asdasd', g: '123' } ] } ], h: 1, i: 1.2, }; const json2 = { a: 'nops', b: 'asd' }; const json3 = { a: 'h', b: '484', c: [ 3, 4.5, '2ss', { e: [ { f: 'asdasd', g: '123' } ] } ], h: 1, i: 1.2, }; const result = jsonsEqual(json1,json2); //const result = jsonsEqual(json1,json3); //const result = jsonsEqual(json1,json1); if(result) // is equal $('#result').text("Jsons are the same") else $('#result').text("Jsons aren't equals") <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="result"></div>