你是在测试两个对象是否相等吗?即:它们的属性是相等的?

如果是这样的话，你可能会注意到这种情况:

var a = { foo : "bar" };
var b = { foo : "bar" };
alert (a == b ? "Equal" : "Not equal");
// "Not equal"

你可能需要这样做:

function objectEquals(obj1, obj2) {
    for (var i in obj1) {
        if (obj1.hasOwnProperty(i)) {
            if (!obj2.hasOwnProperty(i)) return false;
            if (obj1[i] != obj2[i]) return false;
        }
    }
    for (var i in obj2) {
        if (obj2.hasOwnProperty(i)) {
            if (!obj1.hasOwnProperty(i)) return false;
            if (obj1[i] != obj2[i]) return false;
        }
    }
    return true;
}

显然，该函数可以进行相当多的优化，并能够进行深度检查(处理嵌套对象:var a = {foo: {fu: "bar"}})，但您可以理解。

正如FOR所指出的，你可能需要根据自己的目的进行调整，例如:不同的类可能对“equal”有不同的定义。如果您只是处理普通对象，上述方法可能就足够了，否则可以使用自定义MyClass.equals()函数。

如果你的问题是检查两个对象是否相等，那么这个函数可能会有用

function equals(a, b) {
const aKeys = Object.keys(a)
const bKeys = Object.keys(b)
if(aKeys.length != bKeys.length) {
    return false
}
for(let i = 0;i < aKeys.length;i++) {
    if(aKeys[i] != bKeys[i]) {
        return false
    } 
}
for(let i = 0;i < aKeys.length;i++) {
    if(a[aKeys[i]] != b[bKeys[i]]) {
        return false
    }
}
return true
}

first we check if the length of the list of keys of these objects is the same, if not we return false to check if two objects are equal they must have the same keys(=names) and the same values of the keys, so we get all the keys of objA, and objB and then we check if they are equal once we find that tow keys are not equal then we return false and then when all the keys are equal then we loop through one of the keys of one of the objects and then we check if they are equal once they are not we return false and after the two loops finished this means they are equal and we return true NOTE: this function works with only objects with no functions

我发现比较两个javascript对象的值而忽略属性顺序的一个简单方法是使用JSON stringify replacer函数:

const compareReplacer = (key, value) => {
    if(typeof value === 'object' && !(value instanceof Array))
        return Object.entries(value).sort();
    return value;
}
export const compareObjects = (a, b) => JSON.stringify(a, compareReplacer) === JSON.stringify(b, compareReplacer);

这将在每一步对属性进行排序，以便字符串结果对属性顺序不变。以前可能有人这样做过，但我只是想分享一下，以防万一:)。

function isDeepEqual(obj1, obj2, testPrototypes = false) { if (obj1 === obj2) { return true } if (typeof obj1 === "function" && typeof obj2 === "function") { return obj1.toString() === obj2.toString() } if (obj1 instanceof Date && obj2 instanceof Date) { return obj1.getTime() === obj2.getTime() } if ( Object.prototype.toString.call(obj1) !== Object.prototype.toString.call(obj2) || typeof obj1 !== "object" ) { return false } const prototypesAreEqual = testPrototypes ? isDeepEqual( Object.getPrototypeOf(obj1), Object.getPrototypeOf(obj2), true ) : true const obj1Props = Object.getOwnPropertyNames(obj1) const obj2Props = Object.getOwnPropertyNames(obj2) return ( obj1Props.length === obj2Props.length && prototypesAreEqual && obj1Props.every(prop => isDeepEqual(obj1[prop], obj2[prop])) ) } console.log(isDeepEqual({key: 'one'}, {key: 'first'})) console.log(isDeepEqual({key: 'one'}, {key: 'one'}))

在Node.js中，你可以使用它的原生require("assert"). deepstrictequal。更多信息: http://nodejs.org/api/assert.html

例如:

var assert = require("assert");
assert.deepStrictEqual({a:1, b:2}, {a:1, b:3}); // will throw AssertionError

另一个返回true / false而不是返回错误的例子:

var assert = require("assert");

function deepEqual(a, b) {
    try {
      assert.deepEqual(a, b);
    } catch (error) {
      if (error.name === "AssertionError") {
        return false;
      }
      throw error;
    }
    return true;
};

如果你真的想比较并返回两个对象的差值。 您可以使用这个包:https://www.npmjs.com/package/deep-diff

或者只使用这个包使用的代码

https://github.com/flitbit/diff/blob/master/index.js

只是不要把它转换成字符串进行比较。