我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?
当前回答
使用已知的现有库来处理处理时间计算所涉及的异常。我现在最喜欢的是moment.js。
<script src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.13.0/moment.js"></script>
<script>
var now = moment(); // get "now"
console.log(now.toDate()); // show original date
var thirty = moment(now).add(30,"minutes"); // clone "now" object and add 30 minutes, taking into account weirdness like crossing DST boundries or leap-days, -minutes, -seconds.
console.log(thirty.toDate()); // show new date
</script>
其他回答
const MINUTE = 60 * 1000;
new Date(Date.parse(yourDate) + numOfMins * MINUTE)
let d = new Date();
d.setMinutes(d.getMinutes() + 30);
// console.log(d)
我觉得这里的许多答案都缺乏创造性的成分,这是时间旅行计算非常需要的。我提出了30分钟时间翻译的解决方案。
(这里jsfiddle)
function fluxCapacitor(n) {
var delta,sigma=0,beta="ge";
(function(K,z){
(function(a,b,c){
beta=beta+"tT";
switch(b.shift()) {
case'3':return z('0',a,c,b.shift(),1);
case'0':return z('3',a,c,b.pop());
case'5':return z('2',a,c,b[0],1);
case'1':return z('4',a,c,b.shift());
case'2':return z('5',a,c,b.pop());
case'4':return z('1',a,c,b.pop(),1);
}
})(K.pop(),K.pop().split(''),K.pop());
})(n.toString().split(':'),function(b,a,c,b1,gamma){
delta=[c,b+b1,a];sigma+=gamma?3600000:0;
beta=beta+"im";
});
beta=beta+"e";
return new Date (sigma+(new Date( delta.join(':')))[beta]());
}
新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);
对于像我这样的懒人:
Kip的答案(从上面)在coffeescript中,使用“enum”,并对同一对象进行操作:
Date.UNIT =
YEAR: 0
QUARTER: 1
MONTH: 2
WEEK: 3
DAY: 4
HOUR: 5
MINUTE: 6
SECOND: 7
Date::add = (unit, quantity) ->
switch unit
when Date.UNIT.YEAR then @setFullYear(@getFullYear() + quantity)
when Date.UNIT.QUARTER then @setMonth(@getMonth() + (3 * quantity))
when Date.UNIT.MONTH then @setMonth(@getMonth() + quantity)
when Date.UNIT.WEEK then @setDate(@getDate() + (7 * quantity))
when Date.UNIT.DAY then @setDate(@getDate() + quantity)
when Date.UNIT.HOUR then @setTime(@getTime() + (3600000 * quantity))
when Date.UNIT.MINUTE then @setTime(@getTime() + (60000 * quantity))
when Date.UNIT.SECOND then @setTime(@getTime() + (1000 * quantity))
else throw new Error "Unrecognized unit provided"
@ # for chaining