我得到了一个AsyncTask，应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?
public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {
private Main main;
public HostAvailabilityTask(Main main) {
this.main = main;
}
protected Boolean doInBackground(String... params) {
Main.Log("doInBackground() isHostAvailable():"+params[0]);
try {
return InetAddress.getByName(params[0]).isReachable(30);
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return false;
}
protected void onPostExecute(Boolean... result) {
Main.Log("onPostExecute()");
if(result[0] == false) {
main.setContentView(R.layout.splash);
return;
}
main.continueAfterHostCheck();
}
}
这里有一个简单的解决方案，以确保你的应用程序可以访问互联网:
static final String CHECK_INTERNET_ACCESS_URL = "https://www.google.com";
public static void isInternetAccessWorking(Context context) {
StringRequest stringRequest = new StringRequest(Request.Method.GET, CHECK_INTERNET_ACCESS_URL,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
// Internet access is OK
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
// NO internet access
}
});
Volley.newRequestQueue(context).add(stringRequest);
}
这个解决方案使用Android的Volley库，必须在build.gradle中声明:
implementation 'com.android.volley:volley:1.1.1'
更新29/06/2015
如果你正在使用Xamarin。Android和想要检查连接，你可以使用Nuget包，这将给你在多个平台上的功能。好的候选人在这里和这里。
[更新结束]
The Answers above are quite good, but they are all in Java, and almost all of them check for a connectivity. In my case, I needed to have connectivity with a specific type of connection and I am developing on Xamarin.Android. Moreover, I do not pass a reference to my activities Context in the Hardware layer, I use the Application Context. So here is my solution, in case somebody comes here with similar requirements. I have not done full testing though, will update the answer once I am done with my testing
using Android.App;
using Android.Content;
using Android.Net;
namespace Leopard.Mobile.Hal.Android
{
public class AndroidNetworkHelper
{
public static AndroidNetworkStatus GetWifiConnectivityStatus()
{
return GetConnectivityStatus(ConnectivityType.Wifi);
}
public static AndroidNetworkStatus GetMobileConnectivityStatus()
{
return GetConnectivityStatus(ConnectivityType.Mobile);
}
#region Implementation
private static AndroidNetworkStatus GetConnectivityStatus(ConnectivityType connectivityType)
{
var connectivityManager = (ConnectivityManager)Application.Context.GetSystemService(Context.ConnectivityService);
var wifiNetworkInfo = connectivityManager.GetNetworkInfo(connectivityType);
var result = GetNetworkStatus(wifiNetworkInfo);
return result;
}
private static AndroidNetworkStatus GetNetworkStatus(NetworkInfo wifiNetworkInfo)
{
var result = AndroidNetworkStatus.Unknown;
if (wifiNetworkInfo != null)
{
if (wifiNetworkInfo.IsAvailable && wifiNetworkInfo.IsConnected)
{
result = AndroidNetworkStatus.Connected;
}
else
{
result = AndroidNetworkStatus.Disconnected;
}
}
return result;
}
#endregion
}
public enum AndroidNetworkStatus
{
Connected,
Disconnected,
Unknown
}
从以下链接找到并修改(!):
在你的manifest文件中至少添加:
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
如果您正在访问它，您可能已经拥有INTERNET权限。那么一个允许测试连通性的布尔函数是:
private boolean checkInternetConnection() {
ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
// test for connection
if (cm.getActiveNetworkInfo() != null
&& cm.getActiveNetworkInfo().isAvailable()
&& cm.getActiveNetworkInfo().isConnected()) {
return true;
} else {
Log.v(TAG, "Internet Connection Not Present");
return false;
}
}
这个线程中的大多数答案只检查是否有可用的连接，但不检查该连接是否工作，其他答案不是设备范围，我的解决方案应该在每个设备上工作。
你可以在启动应用程序之前在你的主要活动中删除我的代码，它会快速确定是否有实际的互联网连接，如果有对话框将立即删除，应用程序将被启动，如果没有警报会弹出说应用程序需要互联网连接才能工作。
final AlertDialog alertDialog = new AlertDialog.Builder(this).create();
alertDialog.setTitle("Checking Connection");
alertDialog.setMessage("Checking...");
alertDialog.show();
new CountDownTimer(5000, 1000) {
@Override
public void onTick(long millisUntilFinished) {
new Thread(new Runnable() {
public void run() {
try {
URL url = new URL("http://web.mit.edu/");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setConnectTimeout(5000);
isConnected = connection.getResponseCode() == HttpURLConnection.HTTP_OK;
} catch (Exception e) {
e.printStackTrace();
}
}
}).start();
if (isConnected == false){
alertDialog.setMessage("Try " + (5 - millisUntilFinished/1000) + " of 5.");
} else {
alertDialog.dismiss();
}
}
@Override
public void onFinish() {
if (isConnected == false) {
alertDialog.dismiss();
new AlertDialog.Builder(activity)
.setTitle("No Internet")
.setMessage("Please connect to Internet first.")
.setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// kill the app?
}
})
.setIcon(android.R.drawable.ic_dialog_alert)
.show();
} else {
// Launch the app
}
}
}.start();
我已经尝试了近5+不同的android方法，发现这是谷歌提供的最佳解决方案，特别是android:
try {
HttpURLConnection urlConnection = (HttpURLConnection)
(new URL("http://clients3.google.com/generate_204")
.openConnection());
urlConnection.setRequestProperty("User-Agent", "Android");
urlConnection.setRequestProperty("Connection", "close");
urlConnection.setConnectTimeout(1500);
urlConnection.connect();
if (urlConnection.getResponseCode() == 204 &&
urlConnection.getContentLength() == 0) {
Log.d("Network Checker", "Successfully connected to internet");
return true;
}
} catch (IOException e) {
Log.e("Network Checker", "Error checking internet connection", e);
}
它比任何其他可用的解决方案都更快、高效和准确。
