当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?

例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?

请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。

现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。


当前回答

受到许多不依赖包的答案的启发,我在这里分享我的实现。在任何循环中使用的函数都需要当前迭代数、迭代总数和初始时间。

import time    
def simple_progress_bar(i: int, n: int, init_time: float):
    avg_time = (time.time()-init_time)/(i+1)
    percent = ((i+1)/(n))*100
    print(
        end=f"\r|{'='*(int(percent))+'>'+'.'*int(100-int(percent))}|| " + \
        f"||Completion: {percent : 4.3f}% || \t "+ \
        f"||Time elapsed: {avg_time*(i+1):4.3f} seconds || \t " + \
        f"||Remaining time: {(avg_time*(n-(i+1))): 4.3f} seconds."
    )
    return



N = 325
t0 = time.time()
for k in range(N):
    # stuff goes here #
    time.sleep(0.0001)
    # stuff goes here #
    
    simple_progress_bar(k, N, t0)

其他回答

你也可以用启迪。主要的优点是你可以在不覆盖进度条的同时记录日志。

import time
import enlighten

manager = enlighten.Manager()
pbar = manager.counter(total=100)

for num in range(1, 101):
    time.sleep(0.05)
    print('Step %d complete' % num)
    pbar.update()

它还可以处理多个进度条。

import time
import enlighten

manager = enlighten.Manager()
odds = manager.counter(total=50)
evens = manager.counter(total=50)

for num in range(1, 101):
    time.sleep(0.05)
    if num % 2:
        odds.update()
    else:
        evens.update()

PIP安装progressbar2

import os
import time
import progressbar 

os.environ['PYCHARM_HOSTED'] = '1' # https://github.com/WoLpH/python-progressbar/issues/237

class COLOR: # https://stackoverflow.com/a/287944/11465149
    YELLOW    = '\033[93m'
    GREEN     = '\033[92m'
    RED       = '\033[91m'
    BOLD      = '\033[1m'
    ENDC      = '\033[0m'

widgets=[
    'FILE.JSON ',
    COLOR.YELLOW          , progressbar.Percentage()                        , COLOR.ENDC,
    COLOR.RED + COLOR.BOLD, progressbar.Bar(left=' ', marker='━', right=' '), COLOR.ENDC,
    COLOR.YELLOW          , progressbar.Timer()                             , COLOR.ENDC
]

for i in progressbar.progressbar(range(100), widgets=widgets):
    time.sleep(0.01)
    if i == 99:
        widgets[4] = COLOR.GREEN

使用enumerate(…progressbar(max_value=…)+ this,以防你想使用它作为下载进度条

在这里寻找等效的解决方案后,我只是为我的需求做了一个简单的进度类。我想我应该把它贴出来。

from __future__ import print_function
import sys
import re


class ProgressBar(object):
    DEFAULT = 'Progress: %(bar)s %(percent)3d%%'
    FULL = '%(bar)s %(current)d/%(total)d (%(percent)3d%%) %(remaining)d to go'

    def __init__(self, total, width=40, fmt=DEFAULT, symbol='=',
                 output=sys.stderr):
        assert len(symbol) == 1

        self.total = total
        self.width = width
        self.symbol = symbol
        self.output = output
        self.fmt = re.sub(r'(?P<name>%\(.+?\))d',
            r'\g<name>%dd' % len(str(total)), fmt)

        self.current = 0

    def __call__(self):
        percent = self.current / float(self.total)
        size = int(self.width * percent)
        remaining = self.total - self.current
        bar = '[' + self.symbol * size + ' ' * (self.width - size) + ']'

        args = {
            'total': self.total,
            'bar': bar,
            'current': self.current,
            'percent': percent * 100,
            'remaining': remaining
        }
        print('\r' + self.fmt % args, file=self.output, end='')

    def done(self):
        self.current = self.total
        self()
        print('', file=self.output)

例子:

from time import sleep

progress = ProgressBar(80, fmt=ProgressBar.FULL)

for x in xrange(progress.total):
    progress.current += 1
    progress()
    sleep(0.1)
progress.done()

将打印以下内容:

[========] 17/80 (21%) 63

jelde015的一个更普通的答案(当然是他的功劳)

手动更新加载条将是:

import sys
from math import *


def loadingBar(i, N, size):
    percent = float(i) / float(N)
    sys.stdout.write("\r"
                     + str(int(i)).rjust(3, '0')
                     +"/"
                     +str(int(N)).rjust(3, '0')
                     + ' ['
                     + '='*ceil(percent*size)
                     + ' '*floor((1-percent)*size)
                     + ']')

称之为:

loadingBar(7, 220, 40)

将结果:

007/220 [=                                       ]  

只要你想用当前的I值调用它。

将大小设置为条形图应有的字符数

iterrows的Progressbar。调整了@eusoubrasileiro代码,用于在循环遍历数据帧的行时显示进度。此外还显示百分比、ith/count、经过秒数、eps /sec、剩余秒数。允许指定第n个更新计数。

import time
import sys
def progressbar_iterrows(df, prefix="", size=60, file=sys.stdout, per=1000):
    count = len(df)
    t = 0
    def show(j,elapsed):
        avg = 0 if elapsed == 0 else j/elapsed
        remaining = 0 if avg == 0 else (count-j)/avg
        x = int(size*j/count)
        file.write("%s[%s%s] %i%% %i/%i elapsed:%i %i/sec remaining:%i\r" % (prefix, "#"*x, "."*(size-x), j/count, j, count, elapsed, avg, remaining))
        file.flush()
    file.write("Initializing ...\r")
    file.flush()
    for i, item in df.iterrows():
        yield i,item
        if t == 0:
            t = time.time()
        if i % per == 0:
            show(i,time.time()-t)
    file.write("\n")
    file.flush()

用法:

    for n,r in progressbar_iterrows(br_b_sections_df, "Processed: "):
        # do something

输出:

Processed: [........................] 0% 5000/28751240 elapsed:12 413/sec remaining:55054