请求。headers['x-forwarded-for'] || request.connection.remoteAddress . headers['x-forwarded-for'

如果有x-forward -for报头，则使用它，否则使用. remoteaddress属性。

The x-forwarded-for header is added to requests that pass through load balancers (or other types of proxy) set up for HTTP or HTTPS (it's also possible to add this header to requests when balancing at a TCP level using proxy protocol). This is because the request.connection.remoteAddress the property will contain the private IP address of the load balancer rather than the public IP address of the client. By using an OR statement, in the order above, you check for the existence of an x-forwarded-for header and use it if it exists otherwise use the request.connection.remoteAddress.

这里有很多很棒的观点，但没有一个是全面的，所以这里是我最终使用的:

function getIP(req) {
  // req.connection is deprecated
  const conRemoteAddress = req.connection?.remoteAddress
  // req.socket is said to replace req.connection
  const sockRemoteAddress = req.socket?.remoteAddress
  // some platforms use x-real-ip
  const xRealIP = req.headers['x-real-ip']
  // most proxies use x-forwarded-for
  const xForwardedForIP = (() => {
    const xForwardedFor = req.headers['x-forwarded-for']
    if (xForwardedFor) {
      // The x-forwarded-for header can contain a comma-separated list of
      // IP's. Further, some are comma separated with spaces, so whitespace is trimmed.
      const ips = xForwardedFor.split(',').map(ip => ip.trim())
      return ips[0]
    }
  })()
  // prefer x-forwarded-for and fallback to the others
  return xForwardedForIP || xRealIP || sockRemoteAddress || conRemoteAddress
}

在你的请求对象中有一个属性叫socket，它是一个网络。套接字对象。净。套接字对象有一个属性remoteAddress，因此你应该能够通过这个调用得到IP:

request.socket.remoteAddress

(如果您的节点版本低于13，请使用已弃用的request.connection.remoteAddress)

EDIT

正如@juand在评论中指出的那样，如果服务器位于代理之后，获得远程IP的正确方法是request.headers['x-forwarded-for']

编辑2

在Node.js中使用express时:

如果你设置了app.set('信任代理'，true)，请请求。ip将返回真实ip地址，即使在代理。查看文档了解更多信息

在Typescript中使用ValidatorJS。下面是NodeJS中间件:

// Extract Client IP Address
app.use((req, res, next) => {
    let ipAddress = (req.headers['x-forwarded-for'] as string || '').split(',')[0]
    if (!validator.isIP(ipAddress))
        ipAddress = req.socket.remoteAddress?.toString().split(':').pop() || ''
    if (!validator.isIP(ipAddress))
        return res.status(400).json({errorMessage: 'Bad Request'})

    req.headers['x-forwarded-for'] = ipAddress
    next()
})

在这里，我假设所有请求都应该有一个有效的IP地址，因此如果没有找到有效的IP地址，则返回一个代码为400的响应。

也有同样的问题…im也是新的javascript，但我解决了这个与req.connection.remoteAddress;这给了我IP地址(但在ipv6格式::ffff.192.168.0.101)，然后.slice删除前7位数字。

var ip = req.connection.remoteAddress;

if (ip.length < 15) 
{   
   ip = ip;
}
else
{
   var nyIP = ip.slice(7);
   ip = nyIP;
}

你可以像这样快速获取用户Ip

req.ip

在这个例子中，我们获取了用户的Ip，然后用req.ip把它发回给用户

app.get('/', (req, res)=> { 
    res.send({ ip : req.ip})
    
})