我如何检查一个变量的类型是否为布尔类型?

我的意思是,有一些替代方案,比如:

if(jQuery.type(new Boolean()) === jQuery.type(variable))
      //Do something..

但这对我来说不太好。

有没有更清洁的方式来实现这个目标?


当前回答

基准:

都很相似……

const { performance } = require('perf_hooks');

const boolyah = true;
var t0 = 0;
var t1 = 0;
const loops = 1000000;
var results = { 1: 0, 2: 0, 3: 0, 4: 0 };

for (i = 0; i < loops; i++) {

    t0 = performance.now();
    boolyah === false || boolyah === true;
    t1 = performance.now();
    results['1'] += t1 - t0;

    t0 = performance.now();
    'boolean' === typeof boolyah;
    t1 = performance.now();
    results['2'] += t1 - t0;

    t0 = performance.now();
    !!boolyah === boolyah;
    t1 = performance.now();
    results['3'] += t1 - t0;

    t0 = performance.now();
    Boolean(boolyah) === boolyah;
    t1 = performance.now();
    results['4'] += t1 - t0;
}

console.log(results);

  // RESULTS
  // '0': 135.09559339284897,
  // '1': 136.38034391403198,
  // '2': 136.29421120882034,
  // '3': 135.1228678226471,
  // '4': 135.11531442403793

其他回答

基准:

都很相似……

const { performance } = require('perf_hooks');

const boolyah = true;
var t0 = 0;
var t1 = 0;
const loops = 1000000;
var results = { 1: 0, 2: 0, 3: 0, 4: 0 };

for (i = 0; i < loops; i++) {

    t0 = performance.now();
    boolyah === false || boolyah === true;
    t1 = performance.now();
    results['1'] += t1 - t0;

    t0 = performance.now();
    'boolean' === typeof boolyah;
    t1 = performance.now();
    results['2'] += t1 - t0;

    t0 = performance.now();
    !!boolyah === boolyah;
    t1 = performance.now();
    results['3'] += t1 - t0;

    t0 = performance.now();
    Boolean(boolyah) === boolyah;
    t1 = performance.now();
    results['4'] += t1 - t0;
}

console.log(results);

  // RESULTS
  // '0': 135.09559339284897,
  // '1': 136.38034391403198,
  // '2': 136.29421120882034,
  // '3': 135.1228678226471,
  // '4': 135.11531442403793

关于es2015箭头函数的另一个决策

const isBoolean = val => typeof val === 'boolean';

在JavaScript中检查变量类型最可靠的方法是:

var toType = function(obj) {
  return ({}).toString.call(obj).match(/\s([a-zA-Z]+)/)[1].toLowerCase()
}
toType(new Boolean(true)) // returns "boolean"
toType(true); // returns "boolean"

造成这种复杂性的原因是typeof true返回“boolean”,而typeof new boolean (true)返回“object”。

判断真假最简单的方法是: (typeof value === "boolean"), 但如果value是布尔类的实例,则返回"object"。因此,为了处理这个问题,我们必须添加另一个条件来检查是否: (value instanceof Boolean)

代码片段:

const value = false;
//const value = new Boolean(10);
//const value = new Boolean("hi");

if((typeof value === "boolean") || (value instanceof Boolean))
    console.log("boolean");
else
    console.log("not boolean");

这就是typeof存在的意义。括号是可选的,因为它是一个操作符。

if (typeof variable == "boolean") {
    // variable is a boolean
}