<form id="csv_file_form" ng-submit="submit_import_csv()" method="POST" enctype="multipart/form-data">
    <input ng-model='file' type="file"/>
    <input type="submit" value='Submit'/>
</form>

在angularJS控制器中

$scope.submit_import_csv = function(){

        var formData = new FormData(document.getElementById("csv_file_form"));
        console.log(formData);

        $.ajax({
            url: "import",
            type: 'POST',
            data:  formData,
            mimeType:"multipart/form-data",
            contentType: false,
            cache: false,
            processData:false,
            success: function(result, textStatus, jqXHR)
            {
            console.log(result);
            }
        });

        return false;
    }

您的文件和json数据同时上传。

// FIRST SOLUTION var _post = function (file, jsonData) { $http({ url: your url, method: "POST", headers: { 'Content-Type': undefined }, transformRequest: function (data) { var formData = new FormData(); formData.append("model", angular.toJson(data.model)); formData.append("file", data.files); return formData; }, data: { model: jsonData, files: file } }).then(function (response) { ; }); } // END OF FIRST SOLUTION // SECOND SOLUTION // If you can add plural file and If above code give an error. // You can try following code var _post = function (file, jsonData) { $http({ url: your url, method: "POST", headers: { 'Content-Type': undefined }, transformRequest: function (data) { var formData = new FormData(); formData.append("model", angular.toJson(data.model)); for (var i = 0; i < data.files.length; i++) { // add each file to // the form data and iteratively name them formData.append("file" + i, data.files[i]); } return formData; }, data: { model: jsonData, files: file } }).then(function (response) { ; }); } // END OF SECOND SOLUTION

这应该是对@jquery-guru的答案的更新/评论，但由于我没有足够的代表，它将在这里。它修复了现在由代码生成的错误。

https://jsfiddle.net/vzhrqotw/

变化主要是:

FileUploadCtrl.$inject = ['$scope']
function FileUploadCtrl(scope) {

To:

app.controller('FileUploadCtrl', function($scope)
{

如果需要，请随意搬到更合适的地方。

使用onchange事件将输入文件元素传递给函数。

<输入类型=“文件”/>

因此，当用户选择一个文件时，您就有了对该文件的引用，而不需要用户单击“添加”或“上传”按钮。

$scope.fileSelected = function (element) {
    var myFileSelected = element.files[0];
};

上传文件

<input type="file" name="resume" onchange="angular.element(this).scope().uploadResume()" ng-model="fileupload" id="resume" />


        $scope.uploadResume = function () { 
            var f = document.getElementById('resume').files[0];
            $scope.selectedResumeName = f.name;
            $scope.selectedResumeType = f.type;
            r = new FileReader();

            r.onloadend = function (e) { 
                $scope.data = e.target.result;
            }

            r.readAsDataURL(f);

        };

下载文件:

          <a href="{{applicant.resume}}" download> download resume</a>

var app = angular.module("myApp", []);

            app.config(['$compileProvider', function ($compileProvider) {
                $compileProvider.aHrefSanitizationWhitelist(/^\s*(https?|local|data|chrome-extension):/);
                $compileProvider.imgSrcSanitizationWhitelist(/^\s*(https?|local|data|chrome-extension):/);

            }]);

我能够通过使用下面的代码使用AngularJS上传文件:

函数ngUploadFileUpload需要传递的参数的文件是$scope。按你的问题归档。

这里的关键点是使用transformRequest:[]。这将防止$http与文件内容混淆。

       function getFileBuffer(file) {
            var deferred = new $q.defer();
            var reader = new FileReader();
            reader.onloadend = function (e) {
                deferred.resolve(e.target.result);
            }
            reader.onerror = function (e) {
                deferred.reject(e.target.error);
            }

            reader.readAsArrayBuffer(file);
            return deferred.promise;
        }

        function ngUploadFileUpload(endPointUrl, file) {

            var deferred = new $q.defer();
            getFileBuffer(file).then(function (arrayBuffer) {

                $http({
                    method: 'POST',
                    url: endPointUrl,
                    headers: {
                        "accept": "application/json;odata=verbose",
                        'X-RequestDigest': spContext.securityValidation,
                        "content-length": arrayBuffer.byteLength
                    },
                    data: arrayBuffer,
                    transformRequest: []
                }).then(function (data) {
                    deferred.resolve(data);
                }, function (error) {
                    deferred.reject(error);
                    console.error("Error", error)
                });
            }, function (error) {
                console.error("Error", error)
            });

            return deferred.promise;

        }