对于那些既想对任何异常进行重试，又想显式设置异常类型的人，可以使用以下方法:

public class RetryManager 
{
    public void Do(Action action, 
                    TimeSpan interval, 
                    int retries = 3)
    {
        Try<object, Exception>(() => {
            action();
            return null;
        }, interval, retries);
    }

    public T Do<T>(Func<T> action, 
                    TimeSpan interval, 
                    int retries = 3)
    {
        return Try<T, Exception>(
              action
            , interval
            , retries);
    }

    public T Do<E, T>(Func<T> action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        return Try<T, E>(
              action
            , interval
            , retries);
    }

    public void Do<E>(Action action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        Try<object, E>(() => {
            action();
            return null;
        }, interval, retries);
    }

    private T Try<T, E>(Func<T> action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        var exceptions = new List<E>();

        for (int retry = 0; retry < retries; retry++)
        {
            try
            {
                if (retry > 0)
                    Thread.Sleep(interval);
                return action();
            }
            catch (E ex)
            {
                exceptions.Add(ex);
            }
        }

        throw new AggregateException(exceptions);
    }
}

重试助手:一个通用的java实现，它包含可返回类型和无效类型的重试。

import java.util.function.Supplier;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

public class RetryHelper {
  private static final Logger log = LoggerFactory.getLogger(RetryHelper.class);
  private int retryWaitInMS;
  private int maxRetries;

  public RetryHelper() {
    this.retryWaitInMS = 300;
    this.maxRetries = 3;
  }

  public RetryHelper(int maxRetry) {
    this.maxRetries = maxRetry;
    this.retryWaitInMS = 300;
  }

  public RetryHelper(int retryWaitInSeconds, int maxRetry) {
    this.retryWaitInMS = retryWaitInSeconds;
    this.maxRetries = maxRetry;
  }

  public <T> T retryAndReturn(Supplier<T> supplier) {
    try {
      return supplier.get();
    } catch (Exception var3) {
      return this.retrySupplier(supplier);
    }
  }

  public void retry(Runnable runnable) {
    try {
      runnable.run();
    } catch (Exception var3) {
      this.retrySupplier(() -> {
        runnable.run();
        return null;
      });
    }

  }

  private <T> T retrySupplier(Supplier<T> supplier) {
    log.error("Failed <TASK>, will be retried " + this.maxRetries + " times.");
    int retryCounter = 0;

    while(retryCounter < this.maxRetries) {
      try {
        return supplier.get();
      } catch (Exception var6) {
        ++retryCounter;
        log.error("<TASK> failed on retry: " + retryCounter + " of " + this.maxRetries + " with error: " + var6.getMessage());
        if (retryCounter >= this.maxRetries) {
          log.error("Max retries exceeded.");
          throw var6;
        }

        try {
          Thread.sleep((long)this.retryWaitInMS);
        } catch (InterruptedException var5) {
          var5.printStackTrace();
        }
      }
    }

    return supplier.get();
  }

  public int getRetryWaitInMS() {
    return this.retryWaitInMS;
  }

  public int getMaxRetries() {
    return this.maxRetries;
  }
}

用法:

    try {
      returnValue = new RetryHelper().retryAndReturn(() -> performSomeTask(args));
      //or no return type:
      new RetryHelper().retry(() -> mytask(args));
    } catch(Exception ex){
      log.error(e.getMessage());
      throw new CustomException();
    }

您还可以考虑添加要重试的异常类型。例如，这是您想要重试的超时异常吗?数据库异常?

RetryForExcpetionType(DoSomething, typeof(TimeoutException), 5, 1000);

public static void RetryForExcpetionType(Action action, Type retryOnExceptionType, int numRetries, int retryTimeout)
{
    if (action == null)
        throw new ArgumentNullException("action");
    if (retryOnExceptionType == null)
        throw new ArgumentNullException("retryOnExceptionType");
    while (true)
    {
        try
        {
            action();
            return;
        }
        catch(Exception e)
        {
            if (--numRetries <= 0 || !retryOnExceptionType.IsAssignableFrom(e.GetType()))
                throw;

            if (retryTimeout > 0)
                System.Threading.Thread.Sleep(retryTimeout);
        }
    }
}

您可能还注意到，所有其他示例在测试retries == 0时都存在类似的问题，要么重试无穷大，要么在给定负值时无法引发异常。Sleep(-1000)在上面的catch块中也会失败。这取决于你期望人们有多“愚蠢”，但防御性编程永远不会伤害到你。

我是递归和扩展方法的粉丝，所以这里是我的观点:

public static void InvokeWithRetries(this Action @this, ushort numberOfRetries)
{
    try
    {
        @this();
    }
    catch
    {
        if (numberOfRetries == 0)
            throw;

        InvokeWithRetries(@this, --numberOfRetries);
    }
}

指数回退是比简单地尝试x次更好的重试策略。您可以使用Polly这样的库来实现它。

你应该试试波莉。它是由我编写的。net库，允许开发人员以流畅的方式表达临时异常处理策略，如重试，永远重试，等待和重试或断路器。

例子

Policy
    .Handle<SqlException>(ex => ex.Number == 1205)
    .Or<ArgumentException>(ex => ex.ParamName == "example")
    .WaitAndRetry(3, _ => TimeSpan.FromSeconds(3))
    .Execute(DoSomething);