我有一个字符串数组,我需要在JavaScript中排序,但以不区分大小写的方式。如何做到这一点?
当前回答
如果不管输入数组中元素的顺序如何,你都想保证相同的顺序,这里是一个稳定排序:
myArray.sort(function(a, b) {
/* Storing case insensitive comparison */
var comparison = a.toLowerCase().localeCompare(b.toLowerCase());
/* If strings are equal in case insensitive comparison */
if (comparison === 0) {
/* Return case sensitive comparison instead */
return a.localeCompare(b);
}
/* Otherwise return result */
return comparison;
});
其他回答
现在是时候重新审视这个老问题了。
您不应该使用依赖toLowerCase的解决方案。它们效率很低,而且在某些语言(例如土耳其语)中根本不起作用。喜欢这个:
['Foo', 'bar'].sort((a, b) => a.localeCompare(b, undefined, {sensitivity: 'base'}))
查看浏览器兼容性文档,了解灵敏度选项的所有信息。
arr.sort(function(a,b) {
a = a.toLowerCase();
b = b.toLowerCase();
if (a == b) return 0;
if (a > b) return 1;
return -1;
});
arr.sort(function(a,b) {
a = a.toLowerCase();
b = b.toLowerCase();
if( a == b) return 0;
if( a > b) return 1;
return -1;
});
在上面的函数中,如果我们只比较小写的两个值a和b,我们将不会得到漂亮的结果。
例如,如果数组是[A, A, B, B, c, c, D, D, e, e],我们使用上面的函数,我们就得到了这个数组。它没有改变任何东西。
为了使结果为[A, A, B, B, C, C, D, D, E, E],当两个小写值相等时,我们应该再次进行比较:
function caseInsensitiveComparator(valueA, valueB) {
var valueALowerCase = valueA.toLowerCase();
var valueBLowerCase = valueB.toLowerCase();
if (valueALowerCase < valueBLowerCase) {
return -1;
} else if (valueALowerCase > valueBLowerCase) {
return 1;
} else { //valueALowerCase === valueBLowerCase
if (valueA < valueB) {
return -1;
} else if (valueA > valueB) {
return 1;
} else {
return 0;
}
}
}
如果你在努力理解以下内容,这可能会有所帮助:
var array = ["sort", "Me", "alphabetically", "But", "Ignore", "case"];
console.log('Unordered array ---', array, '------------');
array.sort(function(a,b) {
a = a.toLowerCase();
b = b.toLowerCase();
console.log("Compare '" + a + "' and '" + b + "'");
if( a == b) {
console.log('Comparison result, 0 --- leave as is ');
return 0;
}
if( a > b) {
console.log('Comparison result, 1 --- move '+b+' to before '+a+' ');
return 1;
}
console.log('Comparison result, -1 --- move '+a+' to before '+b+' ');
return -1;
});
console.log('Ordered array ---', array, '------------');
// return logic
/***
If compareFunction(a, b) is less than 0, sort a to a lower index than b, i.e. a comes first.
If compareFunction(a, b) returns 0, leave a and b unchanged with respect to each other, but sorted with respect to all different elements. Note: the ECMAscript standard does not guarantee this behaviour, and thus not all browsers (e.g. Mozilla versions dating back to at least 2003) respect this.
If compareFunction(a, b) is greater than 0, sort b to a lower index than a.
***/
http://jsfiddle.net/ianjamieson/wmxn2ram/1/
用. tolowercase()规范.sort()中的case。