我试过类似的方法,但不管用。

class PostSerializer(serializers.ModelSerializer):

    class Meta:
        model = Post

    def save(self):
        user = self.context['request.user']
        title = self.validated_data['title']
        article = self.validated_data['article']

我需要一种能够访问请求的方法。用户从我的Serializer类。


当前回答

对于那些使用Django ORM并将用户添加为外键的人,他们将需要包括用户的整个对象,而我只能在create方法中做到这一点,并删除必选字段:

class PostSerializer(serializers.ModelSerializer):

def create(self, validated_data):
    
    request = self.context.get("request")
    
    post = Post()
    post.title = validated_data['title']
    post.article = validated_data['article']
    post.user = request.user

    post.save()

    return post

class Meta:
    model = Post
    fields = '__all__'
    extra_kwargs = {'user': {'required': False}}

其他回答

你需要在你的序列化器中做一个小编辑:

class PostSerializer(serializers.ModelSerializer):

    class Meta:
        model = Post

    def save(self):
        user = self.context['request'].user
        title = self.validated_data['title']
        article = self.validated_data['article']

下面是一个使用Model混合视图集的示例。在create方法中,您可以找到调用序列化器的正确方法。Get_serializer方法正确地填充上下文字典。如果需要使用视图集上定义的不同的序列化器,请参阅update方法,了解如何使用上下文字典初始化序列化器,该方法还将请求对象传递给序列化器。

class SignupViewSet(mixins.UpdateModelMixin, mixins.CreateModelMixin, viewsets.GenericViewSet):

    http_method_names = ["put", "post"]
    serializer_class = PostSerializer

    def create(self, request, *args, **kwargs):
        serializer = self.get_serializer(data=request.data)
        serializer.is_valid(raise_exception=True)
        self.perform_create(serializer)
        headers = self.get_success_headers(serializer.data)
        return Response(serializer.data, status=status.HTTP_201_CREATED, headers=headers)

    def update(self, request, *args, **kwargs):
        partial = kwargs.pop('partial', False)
        instance = self.get_object()
        kwargs['context'] = self.get_serializer_context()
        serializer = PostSerializer(instance, data=request.data, partial=partial, **kwargs)
        serializer.is_valid(raise_exception=True)
        self.perform_update(serializer)    
        return Response(serializer.data)

你不能直接访问self.context.user。首先,你必须在序列化器中传递上下文。以下步骤如下:

Some where inside your api view: class ApiView(views.APIView): def get(self, request): items = Item.object.all() return Response( ItemSerializer( items, many=True, context=request # <- this line (pass the request as context) ).data ) Then inside your serializer: class ItemSerializer(serializers.ModelSerializer): current_user = serializers.SerializerMethodField('get_user') class Meta: model = Item fields = ( 'id', 'name', 'current_user', ) def get_user(self, obj): request = self.context return request.user # <- here is current your user

您无法访问该请求。直接用户。您需要访问请求对象,然后获取用户属性。

是这样的:

user =  self.context['request'].user

或者为了安全起见,

user = None
request = self.context.get("request")
if request and hasattr(request, "user"):
    user = request.user

更多的上下文可以在这里阅读

正如Igor在其他回答中提到的,您可以使用CurrentUserDefault。如果你不想为此重写save方法,那么使用doc:

from rest_framework import serializers

class PostSerializer(serializers.ModelSerializer):
    user = serializers.PrimaryKeyRelatedField(read_only=True, default=serializers.CurrentUserDefault())
    class Meta:
        model = Post

如果你正在使用通用视图,并且你想在保存实例时注入当前用户,那么你可以覆盖perform_create或perform_update:

def perform_create(self, serializer):
    serializer.save(user=self.request.user)

User将作为一个属性添加到kwargs中,您可以通过serializer中的validated_data访问它

user = validated_data['user']